1
Titration with Potassium Bromate
       Potassium bromate is primary standard.
       Potassium bromate can be used as oxidising agent for inorganic reducers
determination. For direct titration with potassium bromate are used specific redox indicators
or various azo-dyes, which are destroyed by bromate ion surplus (disappearance colour).
       Mixture of potassium bromate and potassium bromide in acidified solution applies
for back-titration of organic compounds. This mixture produces bromine, which react with
aryl radicals in organic compounds structure. End point in bromatometric back-titration is
established iodometric-like  titration with sodium thiosulfate, with starch serving as the
indicator.
I. Preparation the primary standard solution (0,1 N potassium bromate)
1. Calculate a primary standard sample (mPBT) for preparation 250 ml of solution:
               N  V  meq PB
     mPBT =                   .      M.m. KBrO3 = 167,001 g;
                   1000
     mass of potassium bromate equivalent meqPB = M/6.
2.   Weight potassium bromate sample on hand balance with 0,1 g accuracy and put powder
     into weighting bottle.
3.   Weight weighting bottle with potassium bromate on analytical balance.
4.   Transfer the potassium bromate into volumetric flask and weight empty weighting bottle
     on analytical balance. Calculate the potassium bromate sample weight mPBP.
5.   Add 40-50 ml of distilled water to volumetric flask, dissolve potassium bromate and
     establish exact volume of solution with water.
6.   Calculate precision normal concentration of prepared standard solution of potassium
                          m  1000
     bromate: NPB =                 .
                         V  meq BP
7. Calculate the correction factor for prepared 0,1 N potassium bromate solution: CFPB =
     m PBP
           .
     m PBT
II. Sodium Salicylate Determination
In acid solution sodium salicylate transfer to phenol:
                                    OH                        OH
                                          COONa                    COOH
                            2                 + H SO =                 + Na2SO4
                                                 2  4
                                     OH
                                                              OH
                                           COOH
                                                  H2SO4
                                2                         2        + 2CO2 + H2O
Formed phenol reacts with bromine that produced by bromate-bromide mixture:
                                                                                             2
                      KBrO3 + 5KBr + 3H2SO4 = 3Br2 + 3K2SO4 = 3H2O
                                     OH                OH
                                                 Br          Br
                                          + 3Br2 =                + 3HBr
                                                       Br
Bromine surplus is titrated with sodium thiosulfate after potassium iodide addition:
                                        Br2 + 2KI = 2KBr = I2
                               I2 + 2Na2S2O3  2NaI + Na2S4O6
1. Load a burette with 0,1 N standard sodium thiosulfate solution.
2. To conical flask pour in 10 ml aliquot of sample (VS), add pipette using 10 ml of prepared
     0,1 N potassium bromate standard solution (VPB), add 10 ml of 10 % potassium bromide
     solution, and add 10 ml of 1 M H2SO4 solution.
3.   Cover the flask with a stopper and put into dark place at 10 min.
4.   Add 10 ml of 10 % potassium iodide solution and titrate the sample with thiosulfate until
     the solution becomes pale yellow. Introduce 5 drops of starch indicator, and titrate with
     constant stirring to the disappearance of the blue colour.
5.   Read the burette mark (VST).
6.   Repeat titration also two times. Calculate the median volumes of used sodium thiosulfate
     standard solution.
7.   Calculate sodium salicylate percentage in sample:
                                    (VPB  N PB  VST  N ST )  meq SodSal
                        xSodSal =                                           100%
                                                    VS
M.m. Sodium salicylate = 160,11;               meqSodSal = M/6.