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Microwave Engineering
V. S. Bagad
Technical Publications Pune®i
Microwave Enginerring
ISBN 9788184313604
Al rights reserved with Technical Publications. No part of this book should be
reproduced in any form, Electronic, Mechanical, Photocopy oF ony information storage and
‘eirieval systom without prior permission in writing, from Technical Publications, Pune
Published by =
‘Technical Publications Pune”
1, Aait Residency, 419, Shaniwar Peth, Pune - 411 030, nds
Printers :
Vikram Printers
34, Parvati Industrial Estate
Pune-Satara Road,
Pune - 411008.Table of Contents
1.1 Microwave Spactrum and Bands .......cuc.scessstesuseien
11.1 Microwave Frequencies .
1.1.2 Electromagnetic Field po
1.1.3 Popegaion of lecomagnaie Waves .
tT
1.2 Applications of Microwave ...
1.3 Rectangular Waveguides .....
1.3.1 Modes of Propagation.
192 Nomevistance of TEM Made
1.3.3 Solutions of Wave Equations in Rectangular Co-ordinaias =.
1.3.4 Field Equations for TE Mode...
1.3.8 Field Patter in Waveguide .
1.3.6 Waveguide Parameters .
1.3.7 Comparison of TE and TM Modes .
1.3.8 Boundary Conditions for TE Made
1.3.9 Boundary Concittons for TM Moda
1.4 Power Transmitted in Waveguide ..
4.5 Power Loss in Waveguide .....
1.5.1 Power Loss in Dielectric Filing
1.5.2 Power Loss in Waveguide Walls ....... 1-23
1.5.3 Misaligned Waveguide Sectons ......., ce 1-2
1.6 Waveguide Excitation ........c0sssuussssasssss 1-23
1.7 Comparison of Waveguide and Co-axial Cable 1-25
1.8 Advantages of Waveguide Over Co-axial Cable... 1-25
Solved Examples .......c.ccscscceesceesesceeeseesimnscesimneesieaeseeen 12 26
Points to Remember 1-40
sep cater eecueinen! princess
Soto GAREReview Questions...
2.1 Propagation of TE Wave in Circular Waveguide...
2.4.1 Boundary Conditions / Characteristic Equations
2.1.2 Dominant and Degenerate Modes:
2.4.3 Impossibility of TEM Mode
2.2.1.1 Higher Onder Modes in Strip Lines
2.2.1.2 Losses in Strip Lines
22.4.3 Excitation of Strip Lines.
2.2.2 Microstrip Lines...
22.2.1 Effective Dielectric Constant
2.2.2.2 Characteristic Impedance (Z,)
2.2.2.3 Losses in Microstrip Lines
(2.2.2.4 Q-factor of Microstrip . .
2.2.2.5 Limitations of Microstrip... ss ss
‘Comparison of Stripline and Microstrip
225 Slot bins
224 Coplanar Lines .....
2.2.5 Advantages of Planar Transmission Lines:
2.2.6 Disadvantages of Pianar Transmission Lines .
2.3 Cavity Resonators...... ae
2.3.1 Rectangular Cavity Resonator... .
2.3.2 Q-Factor of Cavity Resonator... .
2.3.3 Applications af Cavity Resonator. .
2.3.4 Re-entrant Cavity
2.3.5 Excitation of Cavity Resonator... -
Solved Examples...
Points to Remember 2-22
Review Questions 2-22
tS SESE RIESE Pl ab SEES3.14 Seattering Parameters
3.1.2 Scattering Matrix... _ wees - . 2... 3-5
1.1.3 Scattering Matrix Representation for Multiport Network
311.5 Properties of $-Parametors... we
$4.6 S.Parametors of» Two Pot Notun ih Mamatched Load ee 2. 3-10
3.1.7. Comparison between ($], (2), and [Y| Matrices... co
3.1.8 Relations of Z,
3.2 Waveguide Tees...
4216-Plane Toe.
3.23 Magic Tee... sees
3.3 Waveguide Couplings...
8.3.4 Coupling Loops ..
3.4 Microwave Attenuators .
‘3.4.1 Fixed Attenuator .
3.4.2 Variable Attenuator. .. .
3.5 Waveguide Comers, Bends and Twists...
3.6 Waveguide Transitions ...
3.6.1 Rectangular to Circular Waveguide Te Transition.
3.6.2 Circular to Rectangular Waveguide Transition : ceeteeeeteeees
£163 Ton botween Cosa Gabi and Rectannder Wavoguido vee eceeeeeeesees 9229
3.7 Tuning Screws ....
3.8 Directional Couplers.......
3.8.1 Directional Coupler Parameters
3.8.2 Two Hole Directional Coupler.
3.8.3 Multihole Directional Coupler
3.8.4 Bathe Hole Directional Coupler
3.9 Waveguide Flanges . «3-37
3.10 Matched Terminations .... siseeereerenseenetessereseimeraneessees 87 BB
3.10.4 Standard Mis-matehes =... cee eee teens 3-40
Figo ego raeMicrowave Engineering 2-12 Circular Waveguides
The propagating fields in slot lines are concentrated in the dielectric regions
at the gap between the two adjacent conductors. The magnetic fields has a
strong component in the propagation direction. Therefore, the primary
transmission mode is not TEM but TE. This characteristics is more when the
system requires the incorporation of non-reciprocal ferrite components.
Fig. 2.2.7 shows field patterns of slot line
E Lines
Hines
Fig. 2.2.7 Field pattern of slot lines
The magnetic field has beth longitudinal and transverse components, the
propagating mode is TE. The characteristic impedance Zo at’ slot lines are
proportional to the width of the slot and frequency.
Advantage of slot line over micrdstrip line is that the active and passive
somponents can easily be shunt mounted to the line from the top while in
microstrip series mounting is possible.
2.2.4 Coplanar Lines
The coplanar lines consists of a thin metal strip with ground planes on either
side. It combines some of the advantages of microstrip and slot lines. For
example, series and shunt connections are easily achieved in coplanar line.
Fig. 2.2.8 shows coplanat lines.
Ground planes
‘Center strip
Dielectric substrate (c,)
Fig. 2.2.6 Coplanar lines:Microwave Engineering
Circular Waveguides
© The propagating modes in coplanar lines are TE modes. As a significant
magnetic field component is present, nonreciprocal ferrite components can be
realized,
2.2.5 Advantages of Planar Transmission Lines
.
Major advantages of planar transmission lines are
1. Compact in size
2. Light in weight
3. Highly reliable
4. Better reproducibility
5. Longer life
6. Low cost
7. Basy access to component mounting (exception is strip line)
8. Characteristic impedance can be controlled by adjusting, dimension of strip.
2.2.6 Disadvantages of Planar Transmission Lines
* There are few disadvantages of planar transmission lines.
1. As the size of strip is small, power handling capability is lower.
2. Because of open structure, radiation losses are more.
2.3 Cavity Resonators
* A cavity resonator is a metallic enclosure formed by shorting two ends of a
section of a waveguide. Cavity resonator confines the electromagnetic energy.
The stored electric and magnetic field components inside the cavity
determines the equivalent inductance and capacitance. Within the cavity,
various TE, and TMyy, Modes are possible. A very high value of Q can be
obtained with these resonator.
© In microwave applications the commonly used cavity resonators are
1. Rectangular cavity resonator
2. Circular cavity resonator
3, Re-entrant cavity resonatorMicrowave Engineering 2-14 Circular Waveguides.
2.3.1 Rectangular Cavity Resonator
* In a rectangular waveguide
section if the short circuit is
placed at two ends. The
resultant configuration is
called a rectangular cavity
resonator in which the signal
bounces back and forth
between the opposite walls,
Fig. 2.3.1 shows rectangular
cavity resonator,
Fig. 2.3.1 Rectangular cavity resonator
If m = number of half-wave periodicity in the x-direction
n = number of half wave periodicity in the y-direction
Pp = number of half wave periodicity in the z-direction
‘Then for both modes ic. TE,,.. and TM,,,,, the resonant frequency f, is expressed by
(ey +8
Because for air :
B= band
B= %
(hy &) V2 =
Therefore,
2.3.2 Q-Factor of Cavity Resonator
* Qfactor is the measure of the frequency selectivity of a circuit, Q is defined
as
Maximum energy stored during a cycle
Q = 25) erage energy discipated per cycleMicrowave Engineering 2.45 Circular Waveguides
where o, = Energy stored in cavity
P,_ = Average power loss in cavity
o, = 2
1" FT
* The average power loss can be divided into three parts -
i) Power loss in walls (Pw)
ii) Power loss in dielectric (P,,)
) Power loss due to loading of coupled device (P, gsspting)
+ PL = Pie + Pra + Pe coupling
For loaded circuit
os
Qa = 4
w+ Pld + Preoupling.
a. G2" O
where Q, = Qfactor of wall
Q-factor of dielectric
Q-factor of coupling
Q, is unloaded Q factor
Since Qy >> Qu,
and
where K = Coupling coefficientMicrowave Engineering 2-16 Circular Waveguides
* There can be three values of coupling coefficient
i) Critical coupling
When resonator and generator are matched, then K = 1
Q for loaded circuit is given by -
Qe
Qs
ii) Over coupling : K > 1
Here cavity terminals are at maximum voltage, and the impedance at maxi
voltage is standing wave ratio (p) Le. K =p.
aq = a
T+p
) Under coupling : K < 4
Here cavity terminals are of minimum voltage and the impedance is equal to
reciprocal of SWR (3)
ie. K
1
P
Qu
PL
pri
The relationship of coupling coefficient K and SWR is shown in the Fig. 2.3.2.
Under coupled
Critically
SWRip) Wedd
» on Over coupled
Coupling coefficient (i)
Fig. 2.3.2 Coupling coefficient Vs SWRMicrowave Engineering 2-47
2.3.3 Applications of Cavity Resonator
+ In microwaves the cavity resonators are
devices. Few of them are explained below.
1) Microwave filters :
ae .
Movable
plunger
Fig. 2.3.3 Cavity resonator in notch filter
2) Wavemeter :
Circular Waveguides:
used in microwave measuring
In notch (narrow band) filters
the use of cavity resonator is
shown in Fig. 2.3.3.
In notch filter shown in the
Fig. 2.3.3 the cavity dimensions
are flexible ie. it can be
changed by plunger screw
movement when — incoming
signal frequency is equal ta
resonant frequency. Thus
energy stored in the cavity can
also be varied, Therefore it acts
as noteh filter or band pass
filter,
Screw
‘Waveguide
Cavity
Fig. 2.3.4 Cavity resonator In wavemeterMicrowave Engineering 2-18 Circular Waveguides
Wavemeter is used for measuring frequency. Cavity dimensions are changed
by screw when incoming signal frequency in waveguide matches with
resonant frequency of cavity, the cavity absorbs power and output of
waveguide is minimum, A calibrated micrometer scale gives directly the
frequency. Fig. 23.4 shows the arrangement of wavemeter.
3) Microwave signal generation
Cavity resonators are used in Reflex Klystron and Magnetron for generation of
microwave signal
4) Radar systems
Cavity resonators are employed in Duplexers of Radar systems.
2.3.4 Re-entrant Cavity
In order to maintain resonance at operating frequency and for efficient
energy transfer into the cavity resonator, the inductance and. capacitance
must be reduced. The re-entrant cavities are specially designed to meet this
requirement.
Re-entrant cavity is one in which metallic boundaries extend into the interior
of cavity, One of the commonly used reentrant cavity is co-axial cavity. In
this not only inductance is reduced but resistance losses are also reduced and
shelf shielding enclosure prevents radiation losses. Fig. 2.3.5 shows co-axial
re-entrant cavity
Fig. 2.3.5 Co-axlal re-entrant cavity
Re-entrant cavities are used in Klystrons and other microwave tubes.
2.3.5 Excitation of Cavity Resonator
In order to excite a particular mode, the cavity must be properly coupled to
an external source. Different coupling methods are used in microwave filters
and wavemetersMicrowave Engineering
(A) Loop Coupling
Rectangular cavity
Fig. 2.3.6 Loop coupled cavity
magnetic flux lines.
(B) Probe Coupling
Co-axial line Rectangular cavity
Fig. 2.3.7 Probe coupled cavity
(C) Aperture Coupling
Apertyre 1 iris
Fig. 2.3.8 Aperture coupled cavity
resonator
Circular Waveguides
A rectangular cavity that is loop
coupled to a co-axial line is shown in
Fig. 23.6.
The loop size is very small and the
current in the loop can be considered
to be constant. The conduction current
in the loop produces a linking
magnetic field. The loop is capable of
exciting any cavity mode. The plane of
the loop is placed perpendicular to the
A rectangular cavity that is probe
coupled to a co-axial line is shown in
Fig. 2.3.7. Any cavity mode having an
electric field component parallel to the
probe can be excited by this coupling
arrangement.
In aperture coupling cavity resonator is
excited by a generator by means of a
small centred hole in the transverse
wall. Such type of coupling is also
called as iris coupling. Fig. 2.3.8 shows
iris/aperture coupling.
A magnetic field component that is
parallel to the lang dimension of the
slot will be coupled through the
aperture.Microwave Engineering 2-20 Circular Wavequides
Solved Examples
map Example 2.1: A metal box is 3x4x5 cm in dimensions, filled with air. Calculate the
resanant frequency of the cavity for TE 102.
= Sem = 3x10%m
Solution; Given a
b = 4cm=4x107m
d
= 5ems5x1l0?m
m= 1
n=0
p=2
Resonant frequency for rectangular cavity is given by
a
mm Example 2.2: Calculate the lowest resonant frequency of @ rectangular cavity resonator
with dimensions a = 2 cm, b= I cm and d = 3.0m
Solution : The dominant mode for rectangular waveguide is TE, mode and lowest
frequency can be obtained when p = I(ie. lowest value).
Therefore the TEj,, mode will give the lowest resonant frequency i.e. m = 1, n= 0
and p=1
Given : a = 2cm, b = lem, d =3cm.
Resonant frequency for rectangular cavity is given by,Microwave Engineering 2-21 Circular Waveguides
_ 3x10@ fy
fe ay 3) .
f, = 9GHz » Ans.
mm Example 2.3: A rectangular cavity resonator 10x 8% 6 em. Compute the following:
@) Resonant frequency
b) Resonant frequency of dominant mode for a dielectric filled cavity of e, = 3, For TE,
mode
Solution : a = 10cm=010m
b = 8cm= 008 m
c = 6cm=0.06m
m = 1
n=l
pel
f,
= 34 GHz w Ans.
(b) Resonant frequency with filled dielectric is given by
f = 2GHz . Ans.Microwave Engineering 2-22 Circular Waveguides
Points to Remember
1, The principal mode of propagation in coaxial line is TEM. Hence it does not
have cut-off frequency.
2. Strip line consists of a central conductor strip and two ground plates. The
dominant mode in strip line is TEM.
3, Microstrip line consists of a conductor strip and a ground plane. The
electromagnetic wave propagates in quasi TEM mode.
4. Three types of losses taking place in microstrip.
i) Dielectric loss
ii) Ohmic loss
iii) Radiation loss
5. Slot lines consists of two conducting planes separated by a slot. The
electromagnetic waves propagates in TE mode.
6. Coplanar lines consists of a thin metal strip with ground planes on either
side. The propagating modes in coplanar lines are TE modes.
7. A cavity resonator is a metallic enclosure formed by shorting two ends of a
section of a waveguide.
Review Questions.
L. Explain the construction and field pattern of strip line.
2. Write a note on higher order modes im strip lines.
3. Briefly explain how the strip lines are excited.
4. Describe the construction and field pattern for microstrip line.
5. Elaborate different lasses taking place in microstrip line.
6. What are the limitations of microstrip line ?
2. Compare strip line and microstrip line
& Explain the construction and field pattern for slot lines.
9. Write @ note on coplanar fines.
10, Give advantages and disadvantages of planar transmission lime.
11. Explain cavity resonator.
12, Deduce Q factor for cavity resonator,
13. Briefly explain the applications of cavity resonator.
QoogWaveguide Components and
Applications - I
3.1 Microwave Network
.
A microwave network consists of microwave devices and components
(sources, attenuators, resonators, filters, amplifiers etc.) are coupled by
transmission lines or waveguides. The point of intersection of two or more
signals is called as junction.
In electronic circuits operating at low frequency, a port is a pair of terminals
while for a microwave frequency a port is a reference plane transverse to the
length of the microwave transmission line or waveguide.
The variables at low frequencies are voltages and currents. The variables
{voltages and currents) are related interms of ABCD parameters,
Z-parameters, Y-parameters or h-parameters in matrix forms
Consider a generalized two-port linear network as shown in Fig. 3.1.1.
Two Port
% Hee i
fg
Fig. 3.1.1 Two port network
The relationship between variables and parameters is given by following matrices.
41, ABCD parameters / chain matrix :
ie] [e alle
(3-1)Microwave Engineering 3-2 Waveguide Components and Applications - |
2. Z-parameters / impedance parameters :
Mil _ [Zu Ze fh
V2} [2n 222} [le
3. ¥-parameters / admittance parameters :
fa]. [Ye Ya] [Ve
th] * [yn Yn] [ve
4. h-parameters / hybrid parameters :
Vi] _ fin he] fh
Te} [har haz | LV2
Limitations of ABCD, Z, Y and h-Parameters.
* Problems arise in the measurement of these parameters at microwave
frequencies. These measurements involve terminating the networks in open
and short circuits and subsequent measurement of voltages and currents.
Firstly it is difficult to achieve good quality open and short circuits at
frequencies above 1 GHz, and terminating, active devices in this way, can
damage the devices due to the total reflection of power back into the device.
* Another problem arises in the measurement of voltages and currents at
microwave frequencies and often they can only be derived from measurable
quantities such as VSWR reflection coefficient, power etc. The easiest
parameters to measure are incident and reflected power and the optimum
test conditions are when the two port is terminated in matched loads.
+ For describing and analyzing a microwave network the input-output
parameters are defined by scattering matrix. Scattering matrix is also known
as S-matrix. Since at microwave frequencies measuring voltage, current and
impedance is difficult instead of transmission coefficient, reflection coefficient,
standing wave ratio can be measured accurately. Hence, the conventional
methods of using Z, Y, h and ABCD parameters are not applicable at
microwave: frequencies. Scattering matrix is widely used to analyze the
microwave’ networks. Also scattering matrix can be applied to multiport
networks which is common in microwave application.
3.1.4 Scattering Parameters
+ First consider a general transmission line as shown in Fig. 3.1.2. Here V; and
¥; are the incident and reflected voltages at the load port.
lv.
Incident power P,Microwave Engineering 3-3 | Waveguide Components and Applications -1
wat .
Zo
Power delivered to the load
. Me
Reflected power P;
Vel?
rh z
Load reflection coefficient
Ze
Fig. 3.1.2 Generalised transmission line
_ ¥e_Z.-Zo
Zi +Zo
Now replace the source and line by its Thevenin equivalent as shown in Fig. 3.1.3
If we now define variables a and b such that
a= tT and b= Val
2Re (Zs) 2Re(Z.)"
Where * denotes complex conjugate and Re represents the real part, then we find
that the power available from the source is
Pa = fal?
and the power delivered to the load is
R= |aP-/b/
Where |b|? is the power which is scattered or reflected by the load.
a and b are termed the generalised incident and reflected scattering variables or
power waves. They have dimensions of power.
= The scattering parameters S of the load is defined as-
s = b.V-S1 4 -Z
a W+Z,1 2 +ZyMicrowave Engineering 3-4 Waveguide Components and Applications -|
This is a very similar form to that of the generalised reflection coefficient.
Note that $ is defined interms of 7,.
Fig. 3.1.3 Thevenin equivalent of Fig. 3.1.2
* Now consider the generalised two port circuit shown in the Fig. 3.1.4. The
set of linear equations describing the behaviour of the circuit using the
power waves as variables is :
by = Sy ay +Sy2 a2
bz = Sn ar +Sx a2
‘or in matrix form
fb} = [5] a)
where [5] is known as the scattering matrix.
where be fr and
(|
a=],
az
and the scattering matrix is defined by,
Su Sa
s
[ese]
=> abe
Su = a and Sas
and with a, = 0(V, =0)
= be abe
Sa = 32 and Sp =
So S;, and Sz2 represents the generalised input and output reflection coefficients.Microwave Engineering 3-5 Waveguide Components and Applications -1
* It should be noted at this point that these generalised S-parameters are
defined interms of the reference impedances at the ports and so a set of
values is meaningless without knowledge of the reference impedances
associated with each port. However, almost without exception, S-parameters
are defined with reference to the characteristic impedance of the network or
system in which they are considered.
Fig. 3.1.4 Two port for power wave definition
3.1.2 Scattering Matrix
© It is a matrix which shows a linear relationship between coefficients of the
ports
« Scattering matrix is a useful analytical technique for studying multiport
microwave networks. Its elements relate forward and reverse travelling
waves at the various ports of the network. The elements of this matrix are
called scattering coefficients or scattering parameters, in short it is
abbreviated as S-parameters. These S-parameters are complex numbers,
For a two port network the equations of S-parameters are given as,
by = Sy ay +S az
bz = Sy ai +Sm ar
Reflection coefficient at port-1 when port-2 is
terminated with matched load ie. a: = 0
Attenuation of wave travelling from port-2 to
port-1.
Attenuation of wave travelling from port-1
to port-2Microwave Engineering 3-6 Waveguide Components and Applications - |
terminated with a matched load a;
Sn = Bl Reflection coefficient at port-2 when port-1 is
ar
ato
Here a represents normalised incident wave and
b represents normalised reflected wave at the corresponding ports.
Su Se
Sn Sa
The diagonal elements of the scattering matrix are reflection coefficient and the off
diagonal elements are transmission coefficient.
Scattering matrix
s
3.1.3 Scattering Matrix Representation for Multipart Network
* For a multiport (say n) microwave function, equations of S-parameters are
expressed as:
by = Spay +Siz a2 +53 ag ++ Sin an
bp = Snap +Sx az +8 a3 ¢....4+S2n an
by = Sai An +52 02 +Sp3 3 +... Son dn
* Above equations can be represented by nxn mat
for n-port microwave junction is represented as
by Su Si + Sin | [ar
by Sa Sa
The scattering matrix
ba} [Sm Sa — Sm |lan
3.1.4 Losses in Network
* In microwave circuits it is sometimes necessary to represent various losses in
terms of S-parameters when the ports are terminated with matched load.
‘Consider two port network as shown in Fig. 3.15.
Let P, is power fed at port-1.
P, és power reflected at port-1,
P, is qutput power at port-2.Microwave Engineering 3-7 Waveguide Components and Applications -1
ty Ip
Me Vy V2
Port - 1 Pot-2
—e —a,
—_—) —
Fig. 3.1.5
Then insertion loss, transmission loss, reflection loss, return loss associated with
two port network is given as,
a) Insertion loss.
Insertion loss (dB) = 10 log Z
2
Insertion loss (4B) = 10 log [21
[ba]
Insertion loss (dB) = 20 log Bal
q
Insertion loss (dB) = 20 log —!—
|S. |
b) Transmission loss
Transmission loss is also called as attenuation loss.
‘Transmission loss (dB) = 10 log © =
2
Transmission loss (dB) = 10 log Ss
a
¢) Reflection loss
R
-F
1
= 10 log —~—.
1-]$n["
Reflection loss (dB) = 10 logMicrowave Engineering 3-8 Waveguide Components and Applications - |
d) Return loss
Return loss (dB) = 10 log a
Return loss (4B) = 20 log in
7
1
[sn]
Return loss (4B) = 20 log
3.1.5 Properties of S-Parameters
© Scattering parameters are complex quantities. In microwave network the
S-parameters show following properties.
4) Symmetry Property
« The symmetry property states that if a microwave junction satisfies a
reciprocity condition, the junction is a linear passive circuit and the
S-parameters are equal to their corresponding, transposes.
5 = 5
or s=s!
Where
ST is the transpose of S.
Example 1: Consider S-matrix of a two port network,
_ [Su Se
S= fe =|
Su Sa
st=
[es Sn
By symmetry property,
Sa = Sn
Example 2: Consider 3 x 3 S-matrix,
Su Sa Sia)
S=|Sn Sn Sx]
|
Sn Sx Su}Microwave Engineering Waveguide Components and Applications - |
Su Sa Su
S'=|S2 Sn Su
Sis Su Sa
By symmetry property,
Si2 = Sx
Sis = Sa
Sm = Se
+ The symmetry property results from the fact that the transmission of energy
from port-1 to port-2 is exactly equal in magnitude to the transmission of
energy (in reverse direction) from port-2 to port-1, provided that the network
is bilateral and there are no losses in it.
2) Unity Property / Unitary Property
* Unity property states that “the sum of the products of each term of any row
or column of S-matrix multiplied by its complex conjugate is unity."
ss
For j= 1,23..
3) Zero Property
* Zero property states that "the sum of the product of each term of any row or
column multiplied by the complex conjugate of the corresponding terms of
any other row is zero.
Six Si, = 0
For k=
4) Phase Shift Property
«If any of the terminal planes (k'* port) is moved away from the junction by
an electric distance B,, |,, each of the coefficient S; involving k will be
multiplied by the factor e-Pk,
* A change in the specified location of the terminal planes of an arbitrary
junction will affect only the phase of the scattering coefficient of the junction.
Ss = 6S,Microwave Engineering 3-40 Waveguide Components and Applications -1
on 0 wu. O
Where, 6 =| 0 62 .. 0
Ove see Onn
bu = bor = Oy CPMEfor k = 1,2, 3,0.
3.1.6 5-Parameters of a Two Port Network with Mismatched Load
* In a transmission line, two port network is formed when there is
discontinuity between the input and output port eg. waveguide step
junction, transitions of signal. During propagation of microwave signal from
one port to other evanescent modes are excited, which contains reactive
energy. The evanescent modes decay with propagation. The terminal
reference plane are chosen beyond the effect of evanescent.
* For a two port network terminated by normalized load and source
impedances.
t= 2
s
Zy
[E
es
By)
Now S-parameter equations
ae
by = Sia; +512 a2
by = Sm ai+Sy a2
Substituting value of a2 =t2 bz
by = Sy a) +S bz tz
bz = Sn ai+Sy b2t2
The input reflection coefficient is given as,
br
ar
1sMicrowave Engineering 3-41 Waveguide Components and Applications -|
Sig Sate
ue Sut Toga
For a reciprocal network Siz =Sz
3.1.7 Comparison between [S], [Z], and [Y] Matrices
+ [5]. [Z] and [Y] matrices give the unique intrinsic properties of the device
with the circuit characteristics at test frequency. Also one matrix can be
represented interms of other matrix.
The common properties of [S], [Z] and [Y] matrices are -
1. Number of elements in each matrices are equal.
2. For a reciprocal device the matrices exhibits reciprocity properties,
eg. Zy = Zj or Sij = Si
3. If a matrix is symmetrical, its equivalent matrix is also symmetrical.
4. Few properties of S-matrix are proved to be advantageous aver the [Z] and
[¥] matrices such as -
a} Unitary property
b) When reference plane is changed, the S-coefficients changes only in phase.
c) By knowing the matrix coefficients, all the measurement parameters can be
calculated such a direct correspondance is not possible with [Z] and [Y]
matrices.
3.1.8 Relations of Z, Y and ABCD with S-Parameters
For a two-port network the relationship between variables and parameters are
given as,
Et
Ml 2)
Rearranging and comparing above two matrices we get,
Za
Za
il) Z-paramoters
A=Microwave Engineering 3-12 Waveguide Components and Applications -1
_ Zu 22-2 Zn)
Zn
_ -Zn
Zu
= fe sie
Rearranging and comparing with ABCD parameter matrix.
iii) Y-parameters
_D
Yn + &
_ LA
Yo = -=
1
Ye = 5
Ya = c+AD
Wy) S-matrix
bi] _ [Sn Sz] far
br} [Sa S| aa
gs, = CADBIC+D)
nS (A-B+E-D)
Sp = 2 2(AD+BO)
2 (A-B+C-D)
Sa = —— 2.
at” (A =B+C=D)
Sq = TASB+C+D)
(A-B+C-DyMicrowave Engineering 3-13 Waveguide Componants and Applications -|
iam Example 3.1.1: Express S-parameters interms of impedance when two transmission
lines are joined with character impedances Z, and Z>.
Solution : Assuming matched input and output impedances.
The reflection coefficient at input side.
and Sa
&- 2B
The S-matrix can be written as,
3.2 Waveguide Tees
© Waveguide tee junctions are used to split the line power into two or combine
the power from two lines with proper consideration of the phase. The
junctions that are widely encountered in the microwave techniques are
E-plane, H-plane tee and magic tee.
3.2.1 E-Plane Tee
+ An E-plane tee is designed by fastening a piece of similar waveguide to the
broader wall of a waveguide section. The fastened waveguide is called
auxiliary arm. It is parallel to the plane of the electric field of the dominantMicrowave Engineering 3-14 Waveguide Components and Applications - |
mode TE,, in the main waveguide as shown in Fig. 3.2.1. Hence this type of
junction is called E-plane Tee. Fig. 323 shows the propagation of
electromagnetic fields in an E-plane Tee when the dominant mode TE, is
incident on the symmetrical port-3. While passing through the junction the
electric lings of force bend and as a result af this, fields of opposite polarity
emerge from the two arms.
Fig. 3.2.1 E-plane tee
+ If the fields of opposite polarity are fed into
the two arms 1 and 2, the fields in the
symmetrical arm 3 are added as shown in
Fig. 3.2.1
* If the fields of same polarity are fed inta the
two side arms _there emerge out the Fig. 3.2.2 Transmission line
symmetric arm in opposite phase and equivalent of E-plane tee
therefore cancel out the effect of each other
as shown in Fig. 3.2.3.
¥
Pot @
Input TE 10
Output — Output
port pot
Fig. 3.2.3 E-field of TE,, mode with input at port-3Microwave Engineering 3-15 Waveguide Components and Applications -|
Analysis of E-Plane Tee using S-Matrix
‘Consider a three port microwave junctions having a scattering matrix given by
Si Sz Ss
[S] = |S Sx Sx (3.2.1)
Su Sa Se
Suppose the junction is perfectly matched, there are no reflections at the ports.
This is matrix notation implies :
Sy = Sy =Sy=0 = AB.2.2)
Since [8] is symmetric and unitary, we have,
Spy = Sy weA3.2.3la))
Sy, = Sy +f3.2.3(b)}
Sy = Sy +(3.2.3(C))
Si Sf, +5253, +51355, (3.2.4)
For a loss-less junction, we have,
Su Sf, +5283, +5055, = 1 (3.2.5 (a))
Sy 53, +5228}, +5238}, = 1 +(3.2.5 (b))
Sy Sj, #5325, + S83 = 1 -AB.2.5 ())
From equation (3.2.2) and (3.2.4),
Su +53, = 0 -A3.2.6)
By using equation (3.2.2) and (3.2.5 (a)), we find
182|? = 1 [83/7 = 1+ [Sp]? (3.2.7)
In case of E-plane tee, the outputs at ports-1 and 2 are out of phase by 180° with
an input at port-3. The scattering coefficient is given by,
Sa = Sey =~ Sis ---(3.28)
If port-3 is perfectly matched to the junction,
S, = 0 3.2.9)
With above properties, from equations (3.23) and (3.2.9), the scattering matrix
becomes :
Si Sz Ss
[S} = |Si2 Sm -Sis --(3.2.10)
Ss -Su 0Microwave Engineering 3-16 Waveguide Components and Applications - 1
From unitary property, [S] -[S*] = 1
From (3.2.10), we can write the scattering matrix as,
Su Sa Sa [8,2 8) Sa] fo 0
jSe Sx Ss |/5, Sb Sy }=/0 1 0
[Sa Sis Si, =8j, 0 | oo1
By multiplying R, C, :
(Sul? * [Sa]? * 18:5 e(B.2.11)
By multiplying R, Cy :
[Sia]? + 1Ss21? * [Sia]? -(3.2.12)
By multiplying R, C, :
[S317 + [S317 = 1 23.2.1)
By multiplying R, C; :
$583, -Ss Sf, = 0
Sy (Si -Sh) = 0 of S,=S,
From (3.2.11) and (3.2.12), we get,
Sn = Sn - 3.2.15)
From equation (3.2.13) we get,
+ A3.2.04)
5, = # A216)
By using the values of equations (3.2.14) to (3.2.16) in equation (3.2.11), we get,
2 2,1,
Sul? + [Sul +3 = 1
1
21Sulh= 5 > ISul? -AB247)
From equations (3.2.14), (3.2.16) and (3.2.17), the scattering matrix of equation
(3.2.10) becomes,
[s] = (3.2.18)
g]enic in
1Microwave Engineering 3-17 Waveguide Components and Applications - |
The scattering matrix is defined as,
{b]
is} = LOL
[s} fal
[B] = {5} fa (3.2.19)
Where b is output port and a is input port.
1oioa
by 2 2 2 | fa
b,}=}2 2 1} Ia (3.2.20)
2 3 7 |" 82!
bs 1 1 as
v2 2
_i,i1 1
b= Fat gat em G22)
1, il L
b= Fat Emm (8.2.22)
1 1
by = ana (3.2.23)
There are three cases arises in E-plane tee :
Case 1:
* When an input at port-3 equally divides between port-l and port2 but
introduces a phase shift of 180° between two output. Hence E-plane tee acts
as a 3 dB splitter.
a = %=0, a 40
From equation (3.2.21) to (3.2.23), output is :
1 1
b= ae bo aga by
Case 2:
Equal inputs at port-1 and 2 result in no output.
a = aza
a= 0
From equation (3.2.21) to (3.2.23),Microwave Engineering 3-48 Waveguide Components and Applications - 1
b, =
b, = a-—a=0 ieb,=0
Case 3:
When input at port-1 is non zero and at ports-2 and 3, it is zero, then output
is
a, #0, a, =0,a,=0
= a
bea
;
a= >
:
ar
3.2.2 H-Plane Tee
An H-plane tee is obtained
by fastening the auxiliary
waveguide perpendicular to
narrow arm of the waveguide
section. The auxiliary arm
should lie in the H-plane of
the dominant mode TE,y
mode in the main waveguide
as shown in Fig. 3.24. When
a wave incident in the
symmetrical side arm ie.
Port-3, then it splits into two
equal inphase waves in two
main arms ie. Port-l and
port-2 as shown in Fig. 3.24.
‘The reason for the two waves
being inphase is that while
passing, through the Fig. 3.2.5 Transmission line equivalent of
H-plane tee
comer a
PotMicrowave Engineering 3-19 Waveguide Components and Applications -|
H-junetion the electric field does not suffer any bending and the junction
splits one wave into two ports.
+ If two waves are fed from two side arms 1 and 2, these are added at a
auxiliary arm at port-3 as shown in Fig, 3.25.
* When a wave incident in the side arm ray at port-I, then it is again divided
symmetrically into two arms port-2 and port-3 as shown in Fig. 3.2.5.
Analysis of H-plane tee using S-Matrix
* In H-plane tee, there are also 3 possible inputs and three outputs. So
scattering matrix is given by,
[Se S2 Sal]
[S] = |S Sn Sx | oo(9.2.24)
[Su Se Sus |
For symmetric plane, scattering coefficients 5,, and S.y must be equal
Sis = Sas 43.2.25)
From the symmetric properties :
Si = Sy
Sa = Sav Sy = Se 3.2.26)
The port-3 is perfectly matched, then
0 (3.2.27)
By using properties of equations (3.2.25) to (3.2.27), the scattering matrix of
equation (3.2.24) can be rewritten as,
Su Sz Sis
(S] = |S Sx Ss + AB.2.28)
Si Sis 0
From unitary property =
Is}[S*] = 1
Si $2 Ss] {Si Sh Sh] [1 90
Sn Sm Ss] |Si, Sz 5 |=|0 1 0
Ss Ss 0] |s $3 0} lo 01
Maltiplying R, C,, we get,
81, “Sf, +512 Sf, +8 Sf, = 1Microwave Engineering 3-20 Waveguide Components and Applications -1
And |Sy[? + [Sp [? + [S317 =1 43.2.29)
By multiplying R, C, :
[Sip]? + [Sa]? + [5,3]? = 1 (3.2.30)
From equations (3.2.29) and (3.2.30) :
ISul? = [Sp/?
Sy = Sy (3.2.31)
By multiplying R, C,, we get,
[S317 + [S317 = 1 = 2 (S5[?=1
(3.2.32)
By multiplying R; C,
Sy 5}, +Sis 8}, = 0
Sp (Si, +8),) = 0
Since S,, #0
Sj, +Si, = 0
Si, = -Sh
$1 = -Su (3.2.33)
By using values of (3.2.32) and (3.2.33) in (3.2.39),
2 2,1_
WSnl?+ [S12 +5 = 1
1
222
218i? = 5
1
Sy, = =
ey
From equations (3.2.31) and (3.2.32),
1
Sa = -3
Sn = 5Microwave Engineering 3-24 Waveguide Components and Applications -1
By using above calculated values in the S - matrix of equation (3.2.29) written as :
1 _1 1
2°37
_/.2 1 1
= |-3 3 5
Lio
v2 2
The output of the three different ports is calculated by using equation (3.2.20),
Quad
by 202 V2\fa
o}=|2 2 Th
| 2
Lbs Lad VP lss
v2 V2
b, = ta-ta44 (3.2.34(a))
1 = FU Za yw ol
bp = -Lattasrta +GB.2.34(b)
ne ght htm
1 1
be = tae (8.
2 te (3.2.34(c))
There are two cases arises in H-plane tee :
Case 1: When the input applied to the port-3 only,
a; #0, a,=a,=0
then output from equations (3.2.34),
= 33
bee
= 43
by =
b, = 0
‘The input power divides between port-1 and port-2. It is also a 3 dB splitter.
3 dB splitter : If P,, P, and P, are different ports of E or H-plane tee, then total
output power is written as,
Py, = Pi+P,
If input power at port P, is equal to port P, ie.
P= Py
then total power : P, = 2P,Microwave Engineering 3-22 Waveguide Components and Applications -|
The amount of power coming out of port P, or port P, due to the input at port
Py.
Case 2: a, = a=0
a, = 0
= 28482 2 SB.
b, = 5 at 3 5 0
be = 54548 = r0
by = Sh BR
2 2B
Power output at port-3 is addition of power at port-l and port-2 and in same
phase.
3.2.3 Magic Tee
* A magic tee is a combination of an E-plane and H-plane tee, It acts as a
4-port hybrid circuit. It is also called as Hybrid tee. Fig. 32.6 shows magic
tee.
Collinear arm
Hearn
Fig. 3.2.6 Magic tee (Hybrid tee)
Characteristics of magic tea
1. If two waves of equal magnitude and the same phase are fed into port-1 and
port-2, the output will be zero at port-3 and additive at port-4.
2. If a wave is fed into port-4, it will be divided equally between port-1 and
port-2 of the collinear arms and will not appear at port-3.
Su = Sa =1/¥2, Su = Sq = 1/2 and Sy =0Microwave Engineering 3-23 Waveguide Components and Applications -1
3. If a wave is fed into port-3, it will produce an output of equal magnitude
and opposite phase at port-1 and port-2. The output at port-4 is zero.
Sis = Sn = 1/ V2, So = Sp = 1/2 and Sy =0
4. If wave is fed into one of the collinear arms at port-1 or port-2, it will not
appear in the other collinear arm at port-2 or port-1 because the E-arm causes
a phase delay while the H-arm causes a phase lead.
S2 = Su =0
Magic tee is symmetrical about an imaginary plane bisecting arms port-3 and
port.
* If port-1 and 2 are terminated in matched loads and no reflections take place
inside the junction, entrance of power through either port 3 or 4 results in
equal power delivery to arm 1 and 2. Reflections may take place due to
severe discontinuities in the junction
Effects of reflections
1. Only a portion of the power that approaches the junction through port-3 or 4
is delivered to port-1 and 2.
2. Power is not divided equally between port-1 and 2, when power enters
through port-3 or 4
3. Balance does not exist between port1 and 2 ie. some power transmits
directly from port-1 to port-2.
Reflections must, therefore, be avoided or compensated. By virtue of above
properties discussed above, a magic tee has several applications.
Applications of magic tee
1. As an isolator.
2. As a matching device
3. As a phase shifter.
4. As duplexer.
5. As mixer,
S-matrix for magic tee is a 4 x 4 matrix
Si Sa Sa Sis
Sn Sn Sn Sa
Ss, Sm Ss Sa}
Sa Se Ss Su]
(S] =
But S, = 0, Sp=0 SyMicrowave Engineering 3-24 Waveguide components and Applications -1
8, = 0, S250, Sy=0, Sy=0
and Sia = Soe S13 = - Ss
For port-3 and port-4 matched
©. Smatrix becomes
0 0 Sy
0 0 Sp
is} =
61 Sa Sz 0
Sa Se 0
0 0 Sis oud
10 0 -Ss 0-11
“{|Six -Sa 0 -10 0
Sis Sia 0 1 0 0
3.3. Waveguide Couplings
* Ih order to produce field intensities of desired mode in the waveguide a
probe or loop coupling device is commonly used. The waveguides are
excited from microwave signal source through a co-axial cable.
© The inner conductor of the co-axial cable is projected inside the waveguide.
This inner conductor acts as an electric dipole. The dipole is oriented so as
to excite the electric field intensity of the mode and the coupling loop so as
to generate the magnetic field intensity of the desired mode, the TEia mode
Co-axial cable
Fig. 3.3.1 Co-axial to waveguide adapterMicrowave Engineering 3-25 Waveguide components and Applications -1
with the probe at the centre from the broad wall or perpendicular to the
maximum E-field. Fig. 3.3.1 shows co-axial to waveguide adapter.
By choosing proper values of L and D, the input impedance of the probe can
be adjusted to the characteristic impedance of co-axial line feed.
3.3.1 Coupling Loops
In order to excite a particular mode, the waveguide must be properly
coupled to an external source. Different coupling methods are used in
microwave fillers and wavemeters
A rectangular waveguide that is
loop coupled to a co-axial line is
shown in Fig. 3.3.2.
The loop size is very small and the
current in the loop can be
considered to be constant. The
conduction current in the loop
produces a linking magnetic field.
Co-axial line
The loop is capable of exciting any
mode. The plane of the loop is
placed perpendicular to the
magnetic flux lines.
Fig. 3.3.2 Loop coupling
3.4 Microwave Attenuators
A device used to control the amount of microwave power transferred from
one point to another on a microwave transmission system is called
microwave attenuator.
Microwave attenuators control the flow of microwave power either by
reflecting it or absorbing it.
Attenuators can be classified as fixed or variable type.
3.4.1 Fixed Attenuator
Fixed attenuator consists of a dissipative element called pad which is placed
in a waveguide. The pad is placed in such a way that its plane is parallel to
the electric field, for this two thin metal rods are used. The pad is tapered
for providing a gradual transition from the waveguide medium to the
absorbing medium of pad. This also reduces the reflections. Fig. 3.4.1 shows
side view of fixed attenuator in a waveguide.Microwave Engineering 3-26 Waveguide components and Applications -1
Power
Thin i absorbing
a pas
AEA
(ZEZENZEZEIA VEIT
Fig. 3.4.1 Fixed attenuator
© The amount of power that a fixed attenuator can absorb depends on-
i) Strength of dielectric field.
ii) Location of pad within waveguide.
iii) Area of pad.
iv) Frequency of operation.
v) Pad material used for power absorption.
Fixed attenuators are used where fixed amount of attenuation is required.
3.4.2 Variable Attenuator
* Variable attenuator provides continuous attenuation. The amount of
attenuation introduced is controlled by the depth of insertion of absorbing
plate inside the waveguide. Por this a knob and gear assembly is used. The
Fig. 3.4.2 Variable attenuatorMicrowave Engineering 3-27 Waveguide components and Applications -|
knob can be calibrated suitably. The maximum attenuation will be offered
when the pad extends all the way across the guide. Fig. 3.4.2 shows variable
attenuator.
3.5 Waveguide Corners, Bends and Twists
© Change of direction of guides are often required in microwave applications.
For changing the direction through an angle, waveguide corners, bends and
twists are used. Use of corner and bends will create discontinuities in the
guide therefore standing wave ratio will be increased because of reflections.
In order to minimize the reflections in the bend, its length (L) is made
several wavelengths. Generally the length (L) of bends or comers is odd
multiple of quarter wavelengths.
* IEA, = Wavelength in waveguide,
then length
‘Where n= 0,1,2,3,..
Sharper the bend greater will be the reflections and losses.
Fig. 3.5.1 shows various waveguide corners, bends and twists.
Fig. 3.5.1 Waveguide bends, corners and twist
Twistowave Engineering 3-32 Waveguide components and Applications - 1
The losses introduced by well designed matching screw are small hence the
susceptance for quarter wavelength insertion tends to infinite value.
+ The disadvantage of screw tuning is the requirement of a slot in the wall of
the waveguide
3.8 Directional Couplers
* Directional coupler is used to measure the unidirectional power being
delivered to a load by sampling technique. In sampling technique, only a
known fraction of power in foeward wave is measured. From this fractional
power, the total power can be measured. There are no reflections at the
junction of these four port.
* Directional coupler is a four port waveguide junction, Fig. 3.8.1. shows
directional coupler structure using waveguide.
Auxiliary output
Matched
termination ‘Ausiliary arm
Port Pont-2
Hole’ at 2a
Main’ arm
Fig. 3.8.1 Directional coupler
* Directional coupler measures power in auxiliary waveguide arm in one
direction.
Symbolic representation of directional coupler is shown in Fig. 3.8.2
Main waveguides.
Porte ® Port-2
Port:3 ° © Port-4
Auxiliary waveguide
Fig. 3.8.2 Directional coupler symbolMicrowave Engineering 3-33 Waveguide components and Applications - |
3.8.1 Directional Coupler Parameters
© The performance of a directional coupler is measured interms of four basic
parameters.
i) Coupling Factor (C)
if) Directivity (D)
iii) Isolation (I)
iv) Return loss (R)
i) Coupling factor (C)
© The coupling factor is a measure of how much of incident power is being
sampled. It is the ratio of power levels in main and auxiliary waveguides.
The coupling factor is denoted by C
Main waveguide
Incident
power
Py
Forward
coupled power
Pa
‘waveguide
Fig. 3.8.3
* Let the incident power is A, in main waveguide and the power coupled in
the auxiliary waveguide in forward direction is Py.
Then, Cas) = 10 togno( F}
ii) Directivity (D)
© The directivity is a measure of how well the directional coupler distinguishes
between the forward and reverse travelling power. It is the ratio of forward
coupled power at auxiliary waveguide to the reverse power at auxiliary
waveguide. It is denoted by D.
«Let the power coupled in the auxiliary waveguide in forward direction is P,
and the reverse power at auxiliary port is P3.Microwave Engineering 3-34 Waveguide components and Applications - |
Reverse Forward
power ‘coupled power
Py Pa
Auxiliary
waveguide
Fig. 3.8.4
(P
Then, Daw, = 10 togiol $)
iii) Isolation (I)
* The isolation measures the directive properties of directional coupler. It is
defined as the ratio of incident power at main waveguide (P1) to the reverse
power at auxiliary waveguide (P3). It is denoted by 1
Then, l=10 tos) dB
3
iv) Return loss (R)
* Return loss is defined as the ratio of power incident to the power
transmitted in the main arm. It is also denoted as insertion loss.
r)
‘Then, og (7
Where P, is the received power from the port where power is transmitted.
3.8.2 Two Hole Directional Coupler
«By making holes in the common wall between two waveguides power can
transfer between the guides. Using two or more holes allows the design of a
directional coupler, where the power transfer from one guide to the second
occurs preferentially in one direction of propagation in the second guide. The
two hole coupler is shown in the Fig. 3.8.5.Microwave Engineering 3-35 Waveguide components and Applicatigns -|
eee ee
Port-2
Port-1
T stots ¥ sit
— i!
Ports AS A Portes
P, = Input port
P, - Output port
P, - Isolated port
P,- Coupled port
Fig. 3.8.5 Two hole directional coupler
+ Two hole directional coupler consists of twe guides with two (holes)
common between them. These two apertures holes are at a distance of 2.,/4.
+ Energy is coupled through the slots from the main to the coupled guide.
Because the slots are a quarter-wavelength a part, the energy in the coupled
guide will cancel in one direction and reinforce in the other direction.
* Consider a wave propagating from port-1 to port-2. When the wave -passes
slot a energy is radiated into the coupled guide, where it radiates in both
directions. The main guide wave continues to propagate toward slot b. Part
of the wave couples through slot b into the other guide. As before the
coupled wave propagates in both directions in the other guide. The portion
that propagates towards portd is in phase with slot a energy and thus
reinforces the signal. But the prtion that propagates from slat b back towards
slot a is phase shifted 180% Thus the port-3 signals from slots a and b are out
of phase by 180° and cancel each other. We can label port 1 the input, port-2
the output, port-3 the isolated port and port-4 the coupled port.
«The spacing between slots a and b is critical because it is necessary to effect
a 180° phase shift in the a-b-b-a path.
3.8.3. Multihole Directional Coupler
* Multihole directional coupler operates on
the same basic principles as two hole
er — ex coupler. The coupling array holes are
t t 1 separated by a distance 1,/4. Fig. 3.8.6
shows multihole directional coupler.
Fig. 3.8.6 4-Hole directional couplerMicrowave Engineering 3-36 Waveguide components and Applications - I
3.8.4 Bathe Hole Directional Coupler
LF LT wa
feef
Main | Mainguide
Fig. 3.8.7 Bathe hole directional coupler
* Bathe hole directional coupler consists of two rectangular waveguides
coupled by means of circular aperture located at the center of common broad
edge.
S-Matrix of a Directional Coupler
ince in a directional coupler all four ports are completely matched. Therefore the
diagonal elements of S-matrix are zeros and
Sy = Sx = Sy = 5,4 = 0
It may be noted that there is no coupling between port-1 and port-3 and between
port-2 and port-4
Therefore
Hence the S-matrix of directional coupler becomes
0 Sy O Su
Si 0 Sy 0
0 Sy O Sy
Sa 0 Sy 0 |
S=
From the zero property of the S-matrix, we get,
S,. St, +Sa2 8}, = 0 (3.8.1)
Sy Sy +Su Sh = 0 -3.8.2)
Also from the unity property of the S-matrix, we get
Si 8h +S Si, = 0 3.8.3)
We can rewrite the equations (3.8.1) and (3.8.2) as follows,
[Sal ISiel = [Sab 131Microwave Engineering 3-41 Waveguide components and Applications -!
3.11 Waveguides Irisis
© Irises are fixed or adjustable projections from the walls of waveguide. Irises
are also known as windows. Irises are used for impedance matching
purposes.
* When a dominant wave is incident on such structure, higher order waves are
excited in order to satisfy boundary condition of zero tangential electric field
on irises. These higher order modes die down at a distance less than 2/4 and
store teactive energy. Depending on the type of energy inductive or
capacitive characteristics may be obtained, when magnetic energy is stored
resulting in inductive characteristics and when electric energy is stored
results in capacitive characteristics.
* The normalized susceptances of the irises are varying with the iris
dimensions. These reactive impedances are used to cancel the opposite
reactance in the mismatched load, Hence they can be used as impedance
matching element
Types of Irises
* There are three basic forms of irises -
i) Inductive Iris ii) Capacitive Iris iii) Resonant Iris
3.11.1 Inductive Iris
Conducting diaphragms extending
into a waveguide from side walls
have the effect of adding an
inductive susceptance across the
waveguide at the point at which
.
diaphragms are placed. In the
2 uz
rt
SEE
De
LE Mee
LZ
magnetic field some energy is
Sexo SEEN stored and hence there is an
ae increased inductance at that point
Projections from of the waveguide. Such an
side walls of guide element, therefore called an
inductive iris. The amount of
normalized inductive susceptance
added is a function of the
window insertion distance (J). Fig. 3.11.1 shows inductive iris in a
waveguide.
Fig. 3.11.4 Inductive iris‘Microwave Engineering 3-42 Waveguide components and Applications - I
3.11.2 Capacitive Iris
* Conducting diaphragms extending into the waveguide from top and bottom
walls produces effect of capacitive susceptance shunted across the waveguide
at that point. Fig. 3.11.2 shows capacitiv
Waveguide walls
LE
.
Fig. 3.11.2 Capacitive iris
«It is obvious that the potential which earlier had existed between top and
bottom walls of waveguide now exists between surfaces that are closer and
therefore the capacitance has increased at that point.
* Capacitive windows are not used extensively because of the possibility of
voltage breakdown which ultimately places limit on the power that can be
transmitted through the waveguide.
3.11.3 Resonant Iris
* A conducting diaphragm as shown in Fig. 3.11.3 gives the effect of a parallel
tuned LC circuit connected across the guide at the point where diaphragm is
placed. An equivalent circuit of resonant iris is also shown. The reactances
introduced form a circuit that is parallel resonant.
re
Resonant itis Equivalent circuit
Fig. 3.11.3
* Since the impedance of iris is very high for dominant mode and the shunting
effect is also negligible, other modes are attenuated considerably. Therefore,
resonant window acts a3 a made filter or band pass filter.