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Structural Design Analysis Report

1) The document provides design details for a steel beam including dimensions, material properties, loads, and design checks. 2) Key dimensions of the beam are 125x125x6.5 mm and the steel grade is SM490 with yield strength of 325 MPa. 3) Design checks are performed for flexure, shear, and interaction of combined forces and all checks indicate the beam design is adequate and within code requirements.

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43 views1 page

Structural Design Analysis Report

1) The document provides design details for a steel beam including dimensions, material properties, loads, and design checks. 2) Key dimensions of the beam are 125x125x6.5 mm and the steel grade is SM490 with yield strength of 325 MPa. 3) Design checks are performed for flexure, shear, and interaction of combined forces and all checks indicate the beam design is adequate and within code requirements.

Uploaded by

heinsteinz
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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BeST MEMBER : C1

Project Name : Designer : Date : Page :

Design Conditions y
Design Code : KBC09-Steel(LSD)

9
Section Size : -125x125x6.5x9
6.5
Steel Material Fy = 325 N/mm2 (SM490)
x

125
Unbraced Lengths Lx = 0.00, Ly = 0.00 m
Lb = 0.00 m
EffectiveLengthFact. Kx = 0.00, Ky = 0.00
125
Modification Factor Cb = 0.00

Design Force and Moment Unit : cm

Pu = 0.0 kN As = 30.31
Ix = 847 Iy = 293
Mux = 26.0, Muy = 0.0 kNm
Zx = 154 Zy = 72
Vux = 0.0, Vuy = 23.0 kN J = 8 Cw = 9855

Check Thickness Ratios for Flexure


Check Flange
-. p = 0.38 E/Fy = 9.54
-. r = 1.0 E/Fy = 25.12
-. bf/2tf = 6.94 < p ---> Compact Section
Check Web
-. p = 3.76 E/Fy = 94.43
-. r = 5.70 E/Fy = 143.16
-. h/tw = 13.38 < p ---> Compact Section

Check Flexural Strength about Major Axis


Compute Yielding Strength
-. Mp = Fy*Zx = 50.05 kNm
Compute Lateral-Torsional Buckling
-. Lp = 1.76ry E/Fy = 1.37 m
E Jc
-. Lr = 1.95rts ... = 6.64 m
0.7Fy Sxho
-. Mn,LTB = Mp = 50.05 kNm
Compute Flexural Strength about Major Axis
-. Mnx = Min[Mp, Mn,LTB] = 50.05 kNm
-. Mnx = *Mnx = 45.05 kNm

Check Interaction of Combined Strength


-. Pu/Pn < 0.20

-. Ratio =
Pu
2Pn
+
Mux
[+
Muy
Mnx Mny ] = 0.577 < 1.000 ---> O.K.

Check Shear Strength


Check Shear Strength in Local-y Direction
-. r = 2.24* E/Fy = 56.26
-. h/t = 13.38 < r
-. Cv = 1.00
-. Vn = 0.6*Fy*Aw*Cv = 158.44 kN
-. Vny = *Vn = 158.44 kN
-. Vuy/Vny = 0.145 < 1.000 ---> O.K.

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