Lithium Aluminum Hydride Reductions
Lithium Aluminum Hydride Reductions
Lecture 14
2.1.1.1 Introduction
Lithium aluminum hydride (LAH) is a strong reducing agent with chemical formula
LiAlH4. It can reduce a variety of functional groups such as aldehydes, esters,
acids, ketones, nitriles, epoxides and azides. It vigorously reacts with water and
all the reactions are performed in polar aprotic solvents.
2.1.1.2 Preparation
It was first prepared by treating lithium hydride (LiH) with aluminum chloride
(AlCl3) (Scheme 1).
Scheme 1
Na + Al + 2H2 NaAlH4
Scheme 2
The aldehydes and ketones are reduced to give the corresponding alcohols
when treated with LAH (Scheme 3). For the reduction of aldehydes and ketones,
the reaction is generally performed in ether solvents at low temperature.
                                O                                 OH
                            R        H      LiAlH4           R         H
                                or                                or
                                O                                 OH
                            R        R'                      R         R'
                                O                                               OH
                                            LiAlH4
                     Br                                      Br
                                     Me                                             Me
                                          Et2O, -78 C
Scheme 3
Mechanism
The hydride from LAH is transferred to the carbonyl group to form alkoxy anion
which then forms complex with aluminum (Scheme 4). Similarly, four hydride
atoms are replaced by four alkoxy groups and the aluminum complex thus
formed is then hydrolyzed by dilute acid to give the desired alcohol.
                                                             R                                           R
                                                O        H                              O            H      R
    O                            H                       H   O                                       H O      H
              H                                                                     R       H
                               O Al H       R       H                                                         H
            H Al H                                         O Al H                                    O Al O
R       H                   R    H                      R                                         R
              H                                              H                                         H
                             H H                         H H                                       H H       O
R H
                                                                                                         R
                                                                                                     H       R
                                                                           OH                       H   O      H
                                                                                        H3O                    H
                                                                  4 R           H                     O Al O
                                                                            H                     R     O    H
                                                                                                   H H       H
                                                                                                           R
Scheme 4
The acids are often reduced with LAH to prepare the corresponding alcohols
(Scheme 5). The other comparable method for reduction of acid is using BH 3 as
a reducing agent. The three hydride ions are consumed for reducing one acid
group.
                                          O
                                                       LiAlH4
                                     R        OH                         R         OH
                                     Me                                             Me
                                       O                LiAlH4
OH Et2O OH
Scheme 5
The esters and amides are reduced to the corresponding alcohols and amines,
respectively, when treated with LAH (Scheme 6). Each molecule of ester or
amides consumes two molecules of hydride ions.
                           O
                                     R'
                       R        O                               R        OH + R'              OH
                           or                 LiAlH4                or
                           O
                                                                              R'
                                     R'                        R         N
                      R         N
                                                                         R'
                                R'
                      Me                      Me
                                O O                    LiAlH4             HO                  OH
                       O                      O
                                                        Et2O                        O    O
                                O     O                                            Me    Me
                            Me        Me
                                                LiAlH4
                            NH                                  NH
                       O                 OH      THF
                                                                         OH
Me Me
Scheme 6
The azides, nitriles and nitro compounds are reduced to the corresponding
amines in presence of LAH (Scheme 7). The aromatic nitro compounds do not
give the desired amines.
                            R        N3
                                or
                                                 LiAlH4
                           R C N                            R     NH2
                             or
                            R        NO2
Scheme 7
The epoxides are reduced to the corresponding alcohols (Scheme 8). The
hydride ion is transferred to the less hindered side of the epoxides.
                                             Me LiAlH           Me
                                                     4
                                             O                  OH
                                                            HO
                     O     Me                                    Me
                                                LiAlH4
                                H        O                           H       O
                                               Et2O/THF
                                     O         0 C                       O
                         CO2Me
                                                                 OH
Scheme 8
2.1.2.1 Introduction
Though LAH is a powerful reducing agent but is less selective. The reactivity and
selectivity can be modified by replacing the three hydride ion with alkoxy groups
such as tert-butoxy or ethoxy group. The resulting reagents are less reactive but
more selective than LAH.
2.1.2.2 Preparation
The lithium trialkoxyaluminum hydride can be prepared by treating LAH with the
alcohol and better to prepare in situ prior to use (Scheme 9).
                              3 t-BuOH                    LiAlH(Ot-Bu)3
                 LiAlH4   +      or                           or          + 3H2
                              3 EtOH                      LiAlH(OEt)3
Scheme 9
This is less reactive compared to LAH and reduces aldehydes and ketones to
alcohols and acid chlorides to aldehydes (Scheme 10). The other functional
groups such as acids, amides and nitriles do not react or react very slowly.
                                O                                         O
                                         LiAlH(Ot-Bu)3
                                    Cl                                        H
                                         diglyme, -78 C
                    NC                                       NC
Scheme 10
                                                                                      O
                                             CN        LiAlH(OEt)3                        H
                                                         Et2O
Scheme 11
                                                                R     NH2
                  R'
                                                                                                      R NH2
                           R
             R'        N                                             R
                       H                                        R
                                                  R'                         O            NO2
                                           R'                   CN                    R
                                                                     H2N
                                                  N R
                                   O                                                  O          O
                                                                                            or                      OH             OH
                               R       OR'                                        R       R' R        H                   or
R'OH + R          OH                                            Red-Al                                          R    R'        R    H
                                   O                                                              O
                               O            R                                              R
                                       O                                                         NR'2
                               R                            O            O
                                                        R       Cl R         OH
                  R    OH                                                                                 R      NR'2
R OH
Scheme 12
Examples:
   OH                              OH     OH               OH
        Reduction
                                    +              +
        Ether
TMS                   TMS               TMS
                                                           TMS
            LAH              19             49             32
SMEAH 100 0 0
                          OH                                                  OH
      HOH2C
                              OH SMEAH                                         OH
                  N                     Toluene                           N
                      t-Bu
                                                                    30%
        O                                                  Al                       O                 Al
                                                       O        H     Al
Me                    O      SMEAH                                            Me                      O
                                           Me                         O                     C
            Me               THF                                                         Me Al
                                                           Me
                                                                                               O
                                                  OH
                                                                                               Al
                                                                                           O
                                                                                    Me
                                            Me     Me                 CH2OH
                                                                                               Me
Me
                                                     Me
                                                                          Me               O
        O            Me              Me                         Al
                               Al                           O                  H3O
                R'                                                        Me           R       H
    R       O             Me   H    Me                               R'
                                                        R       O
                                                            H
                                                        tetrahedral
                                                        intermediate
Scheme 13
The nitriles are selectively reduced to the corresponding aldehydes with one
equivalent of DIBAL-H at low temperature. The use of two equivalent of DIBAL-H
gives the corresponding primary amine.
                              Me                                           Me
                          H                                           H
                                       CN                                           CHO
                                               DIBAL-H
                                            CH2Cl2, -78 C
                              Me                                           Me
Scheme 14
Examples:
                 O                                     O
            O                          ClH2C     O
ClH2C                 DIBAL
                      iPrOH, PPTS
                                                 79%
                PhH
       CN                          CHO
80%
Problems
    A. How will you carry out the following reduction reactions using aluminum hydride
        based reagents?
                         CHO                                 CH2OH
        1.      Ph                                Ph
                        CHO                                  CH2OH
        2. Ph                                    Ph
O O
3. NMe2 H
4. CN CHO
5. CO2Me CHO
                              DIBAL-H                 OH
                     CO2Me
                                THF
Text Book
M. B. Smith, Organic Synthesis, 2nd Ed., McGraw Hill, New York, 2004.
Lecture 15
2.1.5 Borohydrides
Different borohydrides are available depending on the metal cations and ligands
such as sodium borohydride, lithium borohydride, zinc borohydride, lithium or
potassium      trialkylborohydride       and     sodium    cyanoborohydride.   All   the
borohydrides reduce aldehydes and ketones to the corresponding alcohols but
due to its counter cations and ligands it shows some special selectivity towards
some functional groups.
The sodium borohydride is an ideal reducing agent for the reduction of aldehydes
and ketones to give the corresponding alcohols (Scheme 1). Unconjugated
ketones and aldehydes are rapidly reduced, usually in preference to a
conjugated carbonyl group that may be present elsewhere in the molecules. The
reactions are performed in polar solvents such as THF, DME, diglyme, hydroxyl
solvent and water but the ethanol is the solvent of choice.
O O
                       O                                           HO
                                          NaBH4, EtOH/CH2Cl2
                                          NH4Cl
                                    S                                    HS     S
                           HS
Scheme 1
                  O                                              OH
                      Me                                           Me
                                            NaBH4/CeCl3
                                  CO2Me                                        CO2Me
                                        MeOH
                                    OH                                           OH
                  Me       O     Me                              Me      O    Me
                                                                    91%
Scheme 2
Proposed Mechanism
Scheme 3
The esters react slowly and the carboxylic acids in normal condition do not react
but are reduced to alcohol in presence of catalytic amount of iodine in reflux
condition in THF (Scheme 4). This method provides effective route for the
                                 CO2H       NaBH4, I2            Ph         OH
                     Ph
                           H NH2            THF, reflux                H NH2
Scheme 4
Amides are not reduced directly by NaBH4, but if they are first converted to an
imimium salts that readily proceed the reduction to give an amine (Scheme 5).
                 O                               +   Cl
                      Cl                                  Cl                             Cl
             N                                   N               NaBH4           N
                             POCl3
EtOH
Scheme 5
Examples:
  O                          OH             OH
             MeOH
                                      +
            NaBH4           0              100
      NaBH4/CeCl3           96               4
  O                                                        OH
                           CO2Me     Luche reduction                             CO2Me
      CHO                                                       CHO
                                                               76%
O HO
                              Luche reduction
                   OTBS                                                 OTBS
  O                                                  O
           Me                                                  Me
                                                         77%
CO2Ph CO2Ph
                              Me                                        Me
                          H                                         H
                                CONMe2          LiBH4                    CONMe2
                              CO2Me                                      OH
                   Me                                          Me
Scheme 6
The zinc borohydride is prepared from zinc chloride and NaBH 4 in ether. It is
most useful for the reduction of                   -unsaturated aldehydes and ketones to give
saturated alcohols (Scheme 7).
                                O                               OH            OH
                                        Zn(BH4)2
                                                                      +
                                        H3O+
                                                                96%           4%
Scheme 7
The presence of three alkyl groups in boron atom makes the hydride strongly
nucleophile and hence it is a strong reducing agent compared to other
borohydrides, and it can reduce the aldehydes and ketones even at -78 C
temperature.       The      commonly                used        trilakylborohydrides        are   lithium
triethylborohydride, Li(Et3BH), and lithium and potassium tri-sec-butylborohydride
(L- and K-Selectrides). The bulky L- and K-selectrides can reduce carbonyl
compound from less hindered side resulting selective products (Scheme 8).
                            H                                             H
                                                 L-Selectride
                                                                               OH
                                    O
                            H                    THF, -78 C               H    H
                            H                                             H
                                            Et                                         Et
                                        H                                          H
                                                    Scheme 8
Examples:
Me     Me
                            Me       Me
             L-Selectride
                THF                     OH
  SO2 O
                              SO2
  N(iPr)2
                              N(iPr)2
                               92%
     OTBDMS                                        OTBDMS
                Me                                           Me
                      L-Selectride
 O                                            O
       H    H         ClCH2OMe               OMe     H   H
                      Et2NH
MeO2C       OTBDMS                           MeO2C       OTBDMS
                                                     90%
                                                             OMe
              CN           OTBDMS K-Selectride                                 CN
O                                                                                   OTBDMS
                                                         O
                              Me      ClCH2OMe                                       Me
                                      Et2NH                         60%
Other than the carbonyl groups, lithium triethylborohydride can reduce primary
bromides and tosylates to the corresponding hydrocarbons (Scheme 9). The
epoxides are also cleaved to give the alcohols and the hydride is transferred to
the less hindered side if epoxides. Lithium triethylborohydride is called super
hydride and an extremely powerful source of hydride.
                                     OTs
                                                                          Me
                                           Li(Et3BH), THF
                                           NaOH, H2O2
Scheme 9
Examples:
                                                                H
                   H
                           Super hydride                 N
              N                                                     O
                       O                   HOH2C
MeO2C                          THF
                                                            O
               O
                                                     97%
                              Super hydride
   Me                                            Me
Me                N   CO2Me                 Me              N   CH2OH
                  CO2Me                                     CO2Me
                                                         90%
                                           O                    O
         CO2H
                      H
                                           O +                  O
             Et
                                           Et                   Et
         O
              Source      Yield (%)             Ratio
                  DIBAL       64      25                  75
        Super hydride         83      85                  15
          L-Selectride        65      75                   25
NaBH3CN is less reactive reducing agent than sodium borohydride due to the
presence of electron withdrawing cyano group. Reaction of NaBH4 with HCN
gives NaBH3CN, which is soluble in THF, MeOH, H2O, HMPA and DMF.
NaBH3CN cannot reduce the aldehydes or ketones in neutral condition but it
reduces the protonated aldehydes and ketones at around pH 3 (Scheme 10).
The iminium ion could be reduced to the corresponding amine with almost
quantitative yield (Scheme 11).
                                   CO2Et                             H   CO2Et
                               H
                                                NaBH3CN                    H
                                       O                             N
                               N                 pH ~4                     OH
                      O    O           NaBH3CN                          O     O
         OHC                                            HOH2C
                                   MeOH, pH 4
                          NHCO2CH2Ph                                         NHCO2CH2Ph
                                                                    89%
Scheme 10
                          Ph                              Ph
                          N                               N
                               H           NaBH3CN              H
                                   N                                N
                          N                MeOH           N
                          Bn   Me                         Bn    Me
Scheme 11
                                                     NHTs
                                                     N                                Me
                   CHO                                   NaBH3CN
                           NH2NHTs
                                                         DMF, heat
Scheme 12
Scheme 31
Problems:
A. Complete the following reactions.
                        OH
                    N
 1.
2.                            Br
                        O
                    H H
      Ph        O
2.                             N           NaBH4
                        N                  EtOH
                O                  Br
                                    Me
                    H                    NaBH4
3.         O        N S
                        O                THF
                      O
Text Book
M. B. Smith, Organic Synthesis, 2nd Ed., McGraw Hill, New York, 2004.
Lecture 16
2.2.1 Introduction
The solution of alkali metal in ammonia (at -33 C) can generate solvated
electrons and metal cations.
These solvated electrons can reduce conjugated double bonds, triple bonds and
aromatic compounds. Most of the organic compounds are not soluble in liquid
ammonia and, therefore, the compounds are dissolved in THF or Et2O and are
added to the dissolved metal solution.
                            Me                                  Me
                                      Na, (NH3)liquid
                                                                      Me
                                                           Me
Scheme 1
                              Me                                                Me
                                                Li, (NH3)liquid
                 O                              Et2O                   O
                                                                               H
                                                then aq. NH4Cl               Me           Me
                        Me             Me
                            cyperone
                              Me                                                Me
                                                Li, (NH3)liquid
                 O                              EtOH                   HO
                                                                               H
                        Me             Me                                    Me           Me
cyperone
Scheme 2
Mechanism
The solvated electron is transferred to the conjugated system to give the radical
anion which is protonated by added alcohol or ammonia and then the second
electron transfer generates the enolate anion which on protonation during work
up gives the desired carbonyl compound (Scheme 3).
O Li O OH OH Li O
       Me                               Me                             Me                            Me               Me
                                                                                               Li
                                                                                                       aq. NH4Cl
Me
Scheme 3
                                         Li, (NH3)liquid
                                         EtOH
Scheme 4
                                                                         X
               X                                       X
                   Birch reduction
                                                               or
Scheme 5
The aldehydes and esters groups are in the electron donation side because
these are reduced to the corresponding alcohols in Birch condition before the
reduction of aromatic ring (Scheme 6). The addition of one or two equivalent of
water or t-BuOH to the NH3 before the addition of metal can preserve the ester
group in Birch reduction.
O O
Scheme 6
Mechanism
The solvated electron accepts an electron and generates the radical anion which
then takes a proton from the alcohol and forms a radical intermediate (Scheme
7). The radical intermediate then takes another electron and converts to the
carbanion which on protonation gives the desired 1,4-cyclohexadiene derivatives.
The role of alcohol is to supply the proton because the NH3 is not sufficient acidic
to supply the proton to all the intermediate anion.
                    H                     H                    H   H                H         H           H     H
                -                                      -
                e               ROH                   e                                           ROH
H H H H H
Scheme 7
Examples:
        O           OMe                                                     O            OMe
                                                           o
                                                                       Et
                         K, NH3, t-BuOH, THP, -78 C
            N                                                                   N
                                                                                CH2OH
                        CH2OH i. Li/NH
                                      3
                                                               O
MeO                              ii. HO2C-CO2H,
                                     H2O, t-BuOH
                                              Lindlar          R       R'
                                              catalyst
                           R         R'
                                              H2               Z alkene
Scheme 8
                                                           R       R
                                R         R
                                    H H                    H       H
Examples:
                                                                        Br
  Br                             N
                                             Lindlar
                             N       N3                             Br        O
Br       O                   H               H2, MeOH
                                                                                    O            H2N    N
             O
                                                                                                  H2N
Pr
                                                                                  CH2OH
                             H2
                                                       Pr
                            Lindlar catalyst
                            quinoline, MeOH
                       OH
     O                                                          O
                                                                             H2
                                                                    O
 O                                                                           Lindlar catalyst
Me                                                                  Me
O O
                                                                                                                           O
                                                            O
                                                                                                96%                        Me
                                                       Me
                                  Me      H2                                                     Me
                 N                                                            N
                 CHO                      Lindlar catalyst
                                                                              CHO
                                                                             92%
The benzyl group and cyano group (alkyl nitrile) could be deprotected by
dissolved metal in ammonia (Scheme 9).
                  Me    H                                                Me   H
                                          Li, EtOH (7equiv)
                                    H     NH3, THF                                     H
          O                BnO                                  O                 HO
                                 Ph            Na, NH3         Ph
                                Ph      CN                    Ph     H
                                 Ph                            Ph
Scheme 9
                            O
                                        Na, EtOH
                       R        OR'                       R   OH + R'    OH
                                H                                H
                                    CO2Me                            CH2OH
                                              Na, EtOH
                                    COOH                             COOH
                                              NH3
                                H                                H
Scheme 10
Proposed Mechanism
The carbonyl group of ester takes an electron and converts to the radical anion
which takes a proton from the alcohol and forms the radical intermediate. The
latter takes the second electron and a proton and undergoes elimination of an
alcohol to give aldehydes that further proceeds further reduction to give the
desired alcohol.
                                                                                                                H
    O                       O                            OH                   OH                          O
              e                         EtOH                        e                   EtOH
R       OR'             R       OR'                  R       OR'          R     OR'                   R         OR'
                                                                                                    -HOR'
                      OH                    OH                     OH               O                       O
                                EtOH                     e               EtOH                   e
                  R     H               R        H            R     H           R       H             R         H
Examples:
                                            Na
EtO2C                                                    HOH2C
                                CO2Et                                                   CH2OH
                                            EtOH
                                                                        75%
Problems
                         Na, EtOH
1.
OH
                      Li-NH3-EtOH
2.
                    OMe
                           Na, EtOH
3.
                            H3O
                      Na-NH3-EtOH
 4.
CO2H
                 Na-NH3-EtOH
5.
      OEt
            Na-NH3-EtOH
6.
                         Na, EtOH
7.
8.                         Na, EtOH
                   NOH
                            reflux
        O
                    (EtO2)2SiHMe
9. Ph
            Br      KF
Text Book
M. B. Smith, Organic Synthesis, 2nd Ed., McGraw Hill, New York, 2004.
Lecture 17
2.3.1 Introduction
Hydrogen is the most abundant chemical element in the universe with atomic
number 1 and symbol H. It has three isotopes hydrogen 1H, deuterium 2D and
tritium 3T and the 1H is the most abundant (99.98%). The hydrogen 1H and
deuterium 2D are stable isotopes whereas the tritium 3T is a radioactive. In
organic chemistry, hydrogen is used to reduce a variety of functional groups but
the hydrogen gas itself can not reduce any functional groups without a catalyst.
Platinum oxide (PtO2) also known as Adams catalyst is generally used for the
platinum catalyzed hydrogenation reaction. Other catalysts such as Pd on
charcoal,       Wilkinsons          catalyst        RhCl(PPh3)3,         Crabtrees       catalyst
[Ir(cod)(PChx3)(py)]PF6, Ru(OAc)2(BINAP), Raney nickel and Nickel boride (Ni2B)
are used. These reactions are performed in ethyl acetate, alcohols and acetic
acid as solvents.
                                Me                              Me
                         Me                              Me          CO2H
                                     CO2H
                                                Pt, H2
                                                AcOH
                                Me                              Me
                                      O                               O
                                          RhCl(PPh3)3
                                          H2, toluene
Me Me Me
                                 OAc                                                     OAc
                        Me                                                      Me
                                                   Pd-C, H2
               O             H         OAc                             O             H      OAc
                                                   EtOH                                    H
                   Me                  Me                                  Me    H           Me
                         MeO2C                                                   MeO2C
                                  O                                    O
                                                  Ni2B, H2
                                                  MeOH                          Me
                                        Me
Scheme 1
                                             Et                   Et
                                                  P           P
                                                      Et Et
                                                (R,R)-DuPHOS
                                         [(R,R)-Et-DuPHOS-Rh]+                                 CO2Me
                             CO2Me
                                                                                          NHAc
                         NHAc
                                                                                 99% ee
                                         O                             OH
                                                B-H
                                                                                                   PPh2
                                            O
                                                                                                   PPh2
                                 [Rh(COD)2]BF4          Me
        Me                                                    94% ee
                                   (+)-BINAP
                                     -78 oC                                          (+)-BINAP
Scheme 2
                       OH
                                                              OH      OH
                                  OH          Pt, H2
Scheme 3
Pd/BaSO4/quinoline
                                               Pd/CaCO3/PbO
                                               H2, MeOH
Me                                     CO2H                   Me
                                                                                            CO2H
Scheme 4
                               CO2Et                     CO2Et
                                          Ni, H2
                                       100 atm., 50 C
                                          PtO2, H2
                               CO2H                           CO2H
                                       AcOH, 25 C
Scheme 5
The aromatic nitro compounds can be reduced to give the corresponding amines
when treated with molecular hydrogen in the presence of Pt, Pd or Ni catalyst
(Scheme 6). The reaction is generally performed in methanol, ethanol or ethyl
acetate at ambient temperature.
                                   NO2                  NH2
                                           Pd/C, H2
                                           EtOAc, rt
Scheme 6
O O
                                          Cl   Pd/BaSO4/quinoline                    H
                                               H2
Proposed Mechanism
O H2 O O
R        Cl                  R        Pd Cl                 R        H
              Pd-BaSO4
Scheme 7
Examples:
O H2, Pd/C/BaSO4 O
Cl       CCl3                                       H     CCl3
                quinoline, petroleium ether
                                                        50%
                                                                                     O
                             O        H2, Pd/C
                                                                                         H
                                 Cl
                                       Pd/PPTA                           48%
                O                                                        O
                         H2, Pd-BaSO4
                    Cl                                                       H
                         quinoline, NaOH, xylene
                                                                      O
               O
                             H2, Pd-C, quinoline      MeO                 H
MeO                 Cl
                                                       MeO
MeO                           NaOAc, toluene
                                                                OMe
         OMe
O OH
Me [RhCl2(bipy)2]Cl 2H2O Me
Scheme 8
                                                                      Ph2P
                                                              OH                       PPh2
                         O      [(RhCl(COD)]2-                                  N
                                (2S,4S)-BPPM             O      O               CO2C(Me)3
                O        O
                                H2                      87 ee                 (2S,4S)-BPPM
Scheme 9
The benzyl ethers, N-Cbz (Cbz = carboxy benzyl), and thioketal groups could be
removed by reaction with molecular hydrogen and Pd or nickel catalyst (Scheme
10). The benzyl ethers and N-Cbz are deprotected by Pd-catalyst and molecular
hydrogen whereas the thioketal groups are reduced to the corresponding alkanes
when treated with Raney nickel and molecular hydrogen.
                            NHCbz                                                  NH2
                    O                                                      O
                        O
                                                                           O
                   O
                                            H2, Pd/C, 0.01N HCl        O
                                    OBn
                                            EtOAc-EtOH                              OH
                        OPBz
                                                                           OPBz
                                                            Raney Ni
                                S                    S
                                                            H2
                                    S           S
Scheme 10
Problems
1.
2.
     NC                      NC
3.
                 OH                       OH
4.
OH
               CO2H                         CO2H
5.
                   OH                                OH
6.
7.
Text Book
M. B. Smith, Organic Synthesis, 2nd Ed., McGraw Hill, New York, 2004.
Lecture 18
                      Me
                 Me                                60 C          Me    Me
                            N N             Me               2              + N2
                 NC
                                          Me                          CN
                                NC
                           AIBN
                                            Bu                                          H
                Me     Me                                                       Me            Me
                            +       H       Sn Bu                Bu3Sn      +
                      CN                    Bu                                          CN
                                          Bu
                       R     + H          Sn Bu                   Bu3Sn + R               H
                                            Bu
Scheme 1
                                      O                                             O
                                 H                                              H
                                                 Bu3SnH (1.2 equiv)
                                 R'                                                     R'
                                                 Bu3SnH (1.2 equiv)
                                        R                                                     R
                                N                AIBN (0.05 equiv)                    N
                                H                                                     H
                       Br                        toluene, 110 C
Scheme 2
                     R
           EtO2C          CO2Et                                            EtO2C R
                            O Me                                                       CO2Et
                                Me              Bu3SnH-AIBN                               O
                             O  Me                                                             Me
                          N  Ph                 benzene, heat                    N        O     Me
                     Br
                                                                                       Ph      Me
                            Ph
                                                                              Ph
                                 O                                             O
                                      NH        Bu3SnH-AIBN                          NH
I benzene, heat
Scheme 3
                                                          S
                           NaH, CS2                                    Bu3SnH-AIBN
                                                                  Me                          R Me
            R    OH                         R         O       S
                           MeI                                         toluene, heat
Scheme 4
Mechanism
The tributyltin radical reacts with the sulfur atom to give a radical intermediate
which then cleaves to give the desired radical and reacts with TBTH to
regenerate the tributyltin radical and the product (Scheme 5).
                                         S                                                  SnBu3
                NaH, CS2                         Me                                     S
R       OH                     R     O       S                                                  Me
                MeI                                                        R       O        S
                                         AIBN
                            Bu3SnH                       Bu3Sn
                                                                                                         SnBu3
                                                                                                     S
                                                       R Me                    R                             Me
                                                                                                O        S
                                                         Bu3SnH
Scheme 5
Examples:
                      Me                                                                     Me
                               TBTH, AIBN               .        Me
             CH2I                                                                  Me
    Me                                                  CH2
                                                 Me
        Me                                                                         Me
                                                   Me
                                                                                            80%
                                                   .
         IH2C                                                         .
    O                                            H3C
                                         O                            OH                                 O
                      TBTH, AIBN
             CO2Et
                                                 CO2Et
                      PhH
                                                                      CO2Et                              CO2Et
                                                                                                         45%
                                         Cu2+
                           NH2-NH2                    HN=NH
                                         H2O2
                                         heat
                   HO2CN NCO2H                        HN NH + CO2
                                         MeOH
                          O
                                          heat                      SO3H
                           S NH-NH2
                           O                           HN NH +
                                        Diglyme
Scheme 6
                      H      H                    H      H          H      H
                          N N                         N N
Examples:
        CH2-OTBS                                      CH2-OTBS
                        KO2CN=NCO2K
HO                                           HO
                   O                                      O      O
             O
                                                       91%
                 t-Bu                                         t-Bu
   HO         CH2Br                                         CH2Br
                                             HO
                  KO2CN=NCO2K
HO                                       HO
                        AcOH, MeOH
                                                      80%
        O                                         O
             O                                          O
                       KO2CN=NCO2K
Me                                      Me
                         AcOH, MeOH
                                                  77%
            OTHP                                      OTHP
                        Cu(OAc)2/H2O2
EtOH/N2H4
2.4.3 Silanes
Silane hydrides can be used for the reduction of carbonyls and alkenes. Addition
of transition metal salts such as ZnCl2 or copper salts to the silane facilitates the
reduction (Scheme 7).
                                      Me                   Me
                                              Et3SiH
                                              TFA
                                                           72%
                                      (EtO)2SiHMe                CH2OH
                                CHO                        Ph
                     Ph
                                       KF
                                  O                                   O
                                        Ph2SiH2
                                       ZnCl2-Pd(PPh3)3
                                        CHCl3
Scheme 7
                       O                               HO H
                                Ph2SiH2, L*                Me
                           Me                                     N   N
                                H2O                                Ph   H
                                              Yield: 99%         L* Me
                                                Ee: 84%
Scheme 8
                                  NO2                                                  NO2
                                              OH                 O
                                                     Al(OiPr)3
                    Cl              COMe                                     Cl              CH(OH)Me
OH O
Mechanism
                                      PrOi         OiPr
                                              Al                                       Al(OiPr)2
          O         Al(OiPr)3           O            O                   O             O           H+     OH
                                                                                  +
      R                  i-PrO-                                                            H R
                                            H                                                               H R
                                                    R
Scheme 9
Examples:
              MeO         O                                                       O
                                  Al(OiPr)3                      MeO
      O                                                    O
      O                       O    toluene                 O
                                                                                      OH
                     OH                                          79% O
  O                                   OH
              AlMe3
              i-PrOH, toluene
                                        82%
           O                                    OH
                 Cl AlMe3                             Cl
                     i-PrOH, toluene
                                          91%
Problems
                                diimide
                          OH
1.
                          OH    diimide
2.
                      Bu3SnH
3.
                 N    AIBN
                 H
        Br
             H
                          Bu3SnH
4.                   O
                 O        AIBN, Toluene, Reflux
     PhS     H
Cl Bu3SnH O
O AIBN
Text Book
M. B. Smith, Organic Synthesis, 2nd Ed., McGraw Hill, New York, 2004.
Lecture 19
2.5.1 Photoreduction
                     O                 OH                                   OH OH                            O
                              +                        hv
                                                                   Ph                   Ph       +
                Ph       Ph       Me       Me                                                          Me        Me
                                                                       Ph          Ph
                     O                 OH                                OH                  O
                              +                        hv                          +
             Ph          Ph       Me       Me        reflux       Ph          Ph       Me         Me
Scheme 1
                     O                                                             OH
                                           OH                                                                    O
                                                            hv
           Me                 Me +                                       Me                  Me +           Me        Me
                                   Me           Me
           Me                 Me                                         Me                  Me
Scheme 2
                                                n, *                                                 n, *             OH
     O                        1        O                Intersystem           3         O                                               OH
                 hv                                     crossing (ISC)                                       Me        Me
Ph        Ph n                    Ph       Ph                                      Ph        Ph                                    Ph    Ph
                         *
dimerization
                                                                                                                                    OH OH
                                                                                                                              Ph              Ph
                                                                                                                              Ph             Ph
Scheme 3
Scheme 4
                        O                                 O                                         OH
                                           hv
                                  Me               Ph         Me +              Me +           Ph
                   Ph
Norrish type II
                                                                            OH
                                       O        Me
                                                          hv           Ph
                                                N
                                  Ph              Ph                             N
                                                                                     Ph
                                                                                OH Me
                                  O              Me
                                                              hv       Me                 Me
                             Me                    Me
                                       O                                    O
Scheme 5
                              hv                       R3N
                                                                           + R3N
H+
e-, H+
                                              H    H             H    H
                                                  dimerization
Scheme 6
The excited aromatic compounds could also be reduced by hydride source such
as sodium borohydride, lithium aluminum hydride of metal hydride (Scheme 7).
The reaction may undergo via the following sequences.
CN CN CN H H CN CN
hv NaBH4 H3O+
Scheme 7
2.5.2 Bio-reduction
The reductions of carbonyl groups have been studied most by using different bio-
reductants such as Bakers yeast or with reductase enzyme. For example, the
reductions of -ketoesters have been studied extensively (Scheme 8). The ethyl
acetoacetate could be reduced to give the corresponding 3-hydroxybutyrate. On
the other hand, 4-chloroacetoacetate when reduced with Bakers yeast, gives the
corresponding         (S)-alcohol           with     opposite      selectivity.    Therefore,     the
stereochemistry of the reduced product depends on the shape and size of the
prochiral starting substrates. It also says that the Bakers yeast has at least two
different active reducing sites.
                      O       O              Baker's yeast                 OH O
                Me                OEt                                 Me           OEt
                                            H2O, sucrose, 30 C
                          O       O             Baker's yeast                     OH O
                 Cl                                                        Cl
                                      OEt                                                OEt
                                              H2O, sucrose, 30 C
Scheme 8
The reduction with Bakers yeast is very much substrate dependant and it works
well with -keto substrates but it is less selective with other keto-functional
substrates. Therefore, it promoted further study on this subject for better results.
For example, a better result has been achieved with lyophilized whole cells of
Rhodococcus ruber DSM 44541, for asymmetric reduction of aryl ketones and
other unfunctional ketones with good enantiomeric excess (Scheme 9).
Me O Rhodococcus ruber Me OH
Scheme 9
                          O                                                OH
                                             G. candidum, NAD+
                     Me                Me                             Me              Me
                                             secondary alcohol
                                  O                                                  OH
                 Br                          G. candidum, NAD+        Br
                                       Me                                              Me
                                             secondary alcohol
                                  O                                             OH
                                             G. candidum, NAD+
                                      CF3                                            CF3
                                             secondary alcohol
Scheme 10
The reduction with isolated enzymes have also been studied and the advantage
of this protocol is that it reduces the effect of other interfering enzymes which are
present in a cell but the weak point is that the stability of isolated enzymes and
use of expensive specific co-factor such as NADP (Nicotinamide adenine
dinucleotide phosphate) (Scheme 11).
                   H2N                                                                               H2N
                             O           O                                OH                                   O
                                 +                    enzyme
                             H       R       R'                     R       R'       +
           O                                                                                N O
                   N         H
 O                                                                                O
   O                                                                                O
  P O                                                                              P O
      OH OH                                                                      O     OH OH
O                                                                                  O P
  O P                                                                                   O
   O   O                                                                            O                      N
                         N
        O                        NH2                                                     O  N                      NH2
           N
                             N                                                                         N       N
      HO       O    N                                                                    HO       O
               PO3H                                                                               PO3H
                         NADPH                                                    NADP+
formate dehydrogenase
CO2 HCOO-
Scheme 11
                         H                                                       H
                                     O                                                    OH
                                                  HLADH
Scheme 12
Problems:
A What products would you expect from the following reactions?
         O    O
                               Baker's yest
1.
                  OEt
                      O
                                   light
                          Ph
2.
              O
                                   light
3.
                                     OH
O O
             O                                       OH
                                           light       Ph
                 Ph                                         +
                      +
                                                                NH
                               NH2
Text Book
M. B. Smith, Organic Synthesis, 2nd Ed., McGraw Hill, New York, 2004.