Selection of SPDs
10
Selection an installation of SPDs
in a facility                                                                                                                                 1/2          2/3
                                                                                                                          0B /1
                                                                                                                                  MB         SB            SA
1. Determining the protective zone (per PN-EN 62305, part 1)                                                          Power
                                                                                                                     supply
and the boundary transitions.                                                                                       conductor
                                                                                                                                               EBB
The boundary transitions of protective zones, and the service installation
MB, SB, SA, are locations where SPDs should be installed.
                   Boundary transitions across protective zones                                                 MB          main-distribution board
                                                                                                                SB          sub-distribution board
At the MB (main distribution board) which is the boundary transition 0B/1
                                                                                                                SA          socket outlet - the point directly in
(i.e. subject to the effects of a partial direct lightning strike), a test class 1
                                                                                                                            front of the device to be protected
SPD should be installed. A test class 1 SPD is intended to handle a lightning
impulse with 10/350 s waveshape.
                                                                                                                                          Iimp - point of strike
2. Determination of the expected surge current for typical examples.                                                                                      200 kA (100%)
                                                                                                                                                              Lightning
2.a. Example of an exposed structure (e.g. radio base stations, waterworks,                                                                                   conductor
                                                                                                                                                                (LPS)
RTV transmitter, etc.)
Assume lightning current sharing as:
50% to LPS, 50% to the power supply pole
                                                                                                                                          MB
(Iimp / 2) / n = (200 kA / 2) / 4 = 25 kA 10/350 s                                                                   Power
                                                                                                                     supply
                                                                                                                                                 100 kA (50%)
                                                                                                                    conductor                                EBB
Iimp / pole = 25 kA 10/350 s
where:                                                                                                                              100 kA (50%)
n - number of conductors (to simplify calculations, the influence
of gas, water and other conductors are omitted).
In each conductor a maximum current value of 25 kA 10/350 s
can be expected.                                                                           Iimp - point of strike
                                                                                                           200 kA (100%)
2.b. Example of two adjacent structures
                                                                                                               Lightning
(with same earthing resistance)                                                                                conductor
                                                                                                                 (LPS)
Assume lightning current sharing as:
50% - LPS
50% - Iimp = (Iimp / 2) / (1 + RA / RB) = 100 kA / 2 = 50 kA 10/350 s
                                                                                           MB                                                          MB
Iimp / pole = Iimp / n = 50 kA / 4 = 12,5 kA 10/350 s                 Power
                                                                      supply
                                                                                                   50 kA (25%)
                                                                     conductor                               EBB                                                          EBB
In this example we can expect the same distribution                                                                        50 kA (25%)
in both structures and in all conductors and a maximum
expected current Iimp of 12,5 kA per conductor.                                       100 kA (50%)
                                                                                 RA                                             RA = RB   RB
2.c. Example of two structures not in close vicinity
(earthing resistance is not the same)
                                                                                           Iimp - point of strike
Assume lightning current sharing as:
                                                                                                           200 kA (100%)
50% - LPS
                                                                                                               Lightning
                                                                                                               conductor
                                                                                                                 (LPS)
50% - Iimp = (Iimp / 2) / (1 + RA / RB) = 100 kA / 1,25 = 80 kA 10/350 s
Iimp / pole = Iimp / n = 80 kA / 4 = 20 kA 10/350 s
                                                                                           MB                                                          MB
                                                                       Power                       80 kA (40%)
                                                                      supply
Iimp = (Iimp / 2) / (1 + RA / RB) = 100 kA / 5 = 20 kA 10/350 s     conductor                               EBB                                                          EBB
                                                                                                                           20 kA (10%)
Iimp / pole = Iimp / n = 20 kA / 4 = 5 kA 10/350 s
                                                                                      100 kA (50%)
                                                                                 RA               1                             RA = RB   RB                       2
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                        Selection of SPDs
                                                                                                                                                     11
Example 2. c is the most common distribution of current: i.e. 40% to the structure
having the lower earthing resistance and 10% to the one with the higher resistance,
and equivalent distribution of current along the individual conductors. In reality
the specific installation to be protected may not be identical to one of the preceding
examples, in which case the closest one should be chosen and the maximum
expected current / pole of the SPD used.
General rules to be adopted:
       For three-phase TT systems select:          IN-PE = 4  Iimp / pole
       For single-phase systems select:            IN-PE = 2  Iimp / pole
3. Establish the electromagnetic immunity class for the SPD.
 Class (PN-EN 61000-4-5)                  UOC (1,2/50)                ISC (8/20)
 1                                        4 kV                        2 kA
 2                                        2 kV                        1 kA
 3                                        1 kV                        0,5 kA
 4                                        0,5 kV                      0,25 kA
UOC and ISC are values with which EMC immunity is tested.
4. Determining distance ( ) between the SPD and device
to be protected.
0A   zone of direct lightning strike                                                                                         0A
0B   zone of partial direct lightning strike                                                                                             Lightning
                                                                                                                                         conductor
0B/1 installation of SPD Class I / Type 1                                                                                                  (LPS)
     distance between the SPD and device to be protected
                                                                                                              0A                                 0A
Selection of SPD fulfilling the following demands                                                                            Protected
                                                                                                                              device
                                                                                                              0B     0B /1                       0B
                                      Uprot  Ui
                                                                                                           Power
                                  Uprot = Up + U                                                         supply
                                                                                                         conductor
                                                                                                                      SPD Class I
where:
Up     protection level of SPD [kV]
U     inductive voltage drop U = (L x di) / dt
Ui     dielectric strength of device [kV] in accordance with installation category
       (from I to IV)
Uprot voltage sensed by the device
Dielectric withstand according to category
 Category                                 Dielectric withstand
 I                                        6 kV
 II                                       4 kV
 III                                      2,5 kV
 IV                                       1,5 kV
Dielectric withstand category must be given by the manufacturer.
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                             Selection of SPDs
12
The protection level of SPDs also determines the length of the conductors.
The length of the conductors contributes an additional inductive voltage drop                             Influence of conductor length
as follows:
A typical conductor has a distributed inductance of approximately 1 H/m, which
at a current rate of rise of 1 kA/s contributes approximately 1 kV per meter length.                            a
                                                                                                                                   Protected
                                                                                                                                    device
                                       U = (L  di) / dt
                             U = 5 H  (1 kA / s) = 5 kV                                                                     =5 m           =a+b
                                                                                                                               L=5 H
                                                                                                                 b
To eliminate the effect of lead length, these should be kept as short as possible,
or a V-type connection to the SPDs hould be used, as shown below:
                                                                                                                     Uprot  Ui
                                                                                                                     Uprot = Up + U
                                                                                                                     Uprot = 1,3 kV + 5 kV
                                                                                                                     Uprot = 6,3 kV
                                                                                                                     Uprot = Ui (category I)
                                                                                                                        Additional SPD
                                                                                                                       or reduce length
                                                                                                                  of connection conductors
Rule: the cross sectional area of the earthing conductor used to install and SPD
should be not less than:
           16 mm2 - SPD class I
           6 mm2 - SPD class II, III
                    or in accordance with the manufacturer's instructions.
5. Relationship between Up [kV] and surge current [kA]
for Relpol S.A. SPDs (Uc = 320 V).
       [kV]
1,60
1,55
1,50
1,45
1,40
1,35
1,30                                                   1
1,25
1,20
1,15
1,10
                                                   2
1,05
1,00
0,95                                                                                                      Note: manufacturers usually only
0,90                                                                                                      provide the value of Up and In.
0,85
                                                                                                          A complete graph as provided above
0,80
       0       5   10   15   20   25    30    35       40   45   50   55   60   65   70    75     80      is more useful (see beside) as it
                                                                                                [kA]      allows for more precise coordination
                                                                                                          of the SPD and the withstand level
1. Up for 8/20 s waveshape (indirect lightning)
                                                                                                          of the equipment to be protected.
2. Up for 10/350 s waveshape (direct lightning)
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                       Selection of SPDs
                                                                                                                               13
6. At the MB (main-distribution board) install SPDs
of test class I.
Such devices are intended to protect equipment classified for installation
in categories I and II (6 kV and 4 kV).
Determine the distance between this SPD (MB) and the device to be protected.
If the condition Uprot  Ui/2 is not achieved, install an additional SPD.
7. At the SB (sub-distribution board) install SPDs
of test class II.
Such devices are installed to protect against the effects of induced voltages.
The SPDs must comply with the requirements of:
In  5 kA, NPE > 10 kA (for connection 1+1),
              NPE > 20 kA (for connection 3+1).
Test class II SPDs can only be used at the zone I / II boundary and must always
follow a test class I SPD.
8. Determine the distance between SPDs (class II) at the SB
and the device to be protected.
Condition for proper protection: Uprot2  Ui/2
If achieved the test class II SPD has successfully protected installation category
II and III.
Note: test class II SPDs can only be installed if the incoming utilities are within
the protected zone 0B.
9. At the SA (the point directly in front of the device
to be protected) install SPDs of test class III.
These should only be installed after a test class I and II SPD.
The correct order of SPD installation is required to ensure effective protection.
Flow chart showing how to select an SPD
             In point MB install SPD class I (LPZ 0B/1)
             Determine dielectric strength Ui of protected devices
                                                               YES
           Select Up (protection level SPD class I),                      PROTECTION
                   determine Uprot  Ui/2                                  COMPLETE
                                         NO
              At point SB install SPD class II (LPZ 1/2)
                                                                   YES
          Select Up2 (protection level SPD class II),
                  determine Uprot2  Ui/2
                                         NO
             At point SA install SPD class III (LPZ 1/2)
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