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Tape Corrections 2

This document discusses corrections that need to be made when measuring distances with tapes due to factors like temperature, tension, and tape length. It provides examples of calculating corrections and determining true distances. Specifically, it shows how to calculate and apply corrections to account for tape length and temperature/tension differences between when a distance is measured and the tape is standardized.

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John Ray Cuevas
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278 views14 pages

Tape Corrections 2

This document discusses corrections that need to be made when measuring distances with tapes due to factors like temperature, tension, and tape length. It provides examples of calculating corrections and determining true distances. Specifically, it shows how to calculate and apply corrections to account for tape length and temperature/tension differences between when a distance is measured and the tape is standardized.

Uploaded by

John Ray Cuevas
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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Due to temperature and tension

When measuring the distance between two existing


points:
With a tape too long, the reading distance
will be short, add the correction
With a tape too short, the reading distance
will be long, subtract the correction
When laying out a line or establishing a point:
With a tape too long, subtract the correction
With a tape too short, add the correction
(Lay-out)
Example
A distance is measured with a 100-ft steel tape and
is found to be 9667.32 ft. Later the tape is
standardized and is found to have an actual length
of 100.07 ft. What is the correct distance
measured?
Ca= (9667.32*(100-100.07)/(100)
Ca= -6.7671m
Correct length = 9667.32 + (-6.7671) = 9660.5529m
A known distance of points A and B and is re-measured with a
50-m steel tape and is found to be 1240.24 m.. Later the tape
is standardized and is found to have an actual length of
49.9004 m. What is the correct distance measured?

Ca= (1240.24*(50-49.9004)/(50)
Ca= +2.4706m
Correct length = 1240.24 - (+2.4706) = 1237.7694m
Steel tape 30 m Po= 10 kg
To= 20 deg C. P= 15 kg
L= 1650 m A= 0.025 cm^2
Tm= 30 deg C. E= 2.1 x 10^6 kg/cm^2
= 3.5 x 10^-6 /deg C
Ct=(3.5 x 10^-6)(30-20)(1650)
Ct=0.05775 m

Cp=((15-10)/((.025)(2.1x10^6)))(1650)
Cp=0.157142857 m

True length of the line = 1650m-0.05775 m-0.157142857m


True length of the line = 1649.7851m

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