Week 3 Assignment 3 Solution         Full Marks 20
Q.1    The effective length of butt weld should not be less than           1
       (a)      four times the size of weld
Solution hints:
       Lec 11 Design of Butt Welds, Slide No. 6.
Q.2    In case of incomplete penetration of butt weld the effective throat
       thickness is taken as                                              1
       (b)         th
                7/8 of the thickness of the thinner part.
Solution hints:
       Lec 11 Design of Butt Welds, Slide No. 5
Q.3    The size of butt weld is specified by                               1
       (a)      effective throat thickness
Solution Hints:
       Lec 11 Design of Butt Welds, Slide No. 3.
Q.4    An ISMC 300 @ 0.363 kN/m is connected to a 12mm thick gusset
       plate. The size of the weld is 6 mm. Assume site welding. The strength
       of the weld is                                                     2
       (c)      663 N/mm
Solution Hints:
       Throat thickness = 0.7×6 = 4.2 mm
       Strength of weld per mm run = tefu/√3×1.5 =4.2×410/√3×1.5 = 663
       N/mm
Q.5    A pipe of 100 mm diameter is connected to a plate with a fillet weld of
       size 5 mm. A vertical force of 10 kN is acting at a distance 0.5 m from
       welded end. Calculate shear stress due to direct load.                2
       (c)      9 N/mm  2
Solution hints:
       Effective throat thickness = 0.7×5 = 3.5 mm
                                              𝑃
                                       𝑞=
                                           2𝜋𝑟𝑡
       So, q = (10×103)/(2×π×50×3.5) = 9 N/mm2
Q.6     If moment (M) on the joint of eccentric connection is much high
        compare to the direct load, the required number of bolts n in one row
        in a bolt group with bolts having pitch p, number of rows nʹ and bolt
        value Bsd, is given by                                           2
                             𝟔𝑴
        (b)       𝒏=√
                           𝒑𝒏’𝑩𝒔𝒅
Solution hints:
                  See lecture 14 Design of eccentric connection, slide no 2.
Q.7     If moment (M) on the joint of eccentric connection is much less
        compare to the direct load (P), the approximate number of bolts in a
        bolt group with bolts having bolt value Bsd, is given by
                        𝑷
        (c)       𝒏=
                       𝑩𝒔𝒅
Solution hints:
              See lecture 14 Design of eccentric connection, slide no 2.Q.8
              Which one of the following is the most critical bolt in the joint
        shown in the figure given below?
              2
                                           300 kN
                       5     1
                       6     2
                       7     3
                       8     4
         (b) Bolt 4
Solution hints:
         In the case of inclined load, a bolt nearest to the load axis will be
critical. Extending the line of action of the load, the nearest bolt is bolt 4.
Q.9    Polar moment of inertia of weld, Ip is equal to                      1
       (c)      Ix + Iy
Solution hints:
                See lecture 15 Design of eccentric connection, slide no 4
Q.10   When the load line coincides with the centroid of the bolt group, the
       bolts are subjected to                                             1
       (a)     shear only
Q.11   If P is the load lying in the plane of welded joint of an eccentric
       connection with throat thickness t and total length of the weld is L, the
       direct shear stress in the weld                                     1
       (b)       P/Lt
Solution hints:
                 See lecture 15 Design of eccentric connection, slide no 3
Q.12 A moment M of magnitude 50 kN-m is transmitted to a column flange
       through a bracket by using four 20 mm diameter bolts as shown in the
       figure:
       The shear force induced in the bolt A is                           5
       (c) 214.4 kN
Solution hints:
       The centroid of bolt will be on the symmetric lines and each bolt will
be at
       𝑟 = √502 + 302 = 58.31 mm
Shear force in bolt A is given by
                𝑀𝑟       50×103 ×58.31
       𝐹𝑠 = ∑ 2 =                        = 214.4 kN
                 𝑟          4×58.312