TED(10)-1003 B Reg No..................
(REVISION-2010) Signature...............
FIRST SEMESTER DIPLOMA EXAMINATION IN ENGINEERING
TECHNOLOGY-OCTOBER, 2013
APPLIED SCIENCE-1 (Chemistry)
(Common except DCP and CABM)
[Time:11/2 hours]
(Maximum marks:50)
PART-A
(Maximum marks:4) Marks
(Answer the question in one or two sentences. Each question carries 2 marks)
I)
a)Explain neutralization reaction. Give one example?
(b) Define soft water. ? (2x2=4)
Answers
I)
(a)According to Arrhenius concept Neutralisation is the reaction of H+ from acid and
OH- from base form water.
Ex: H+ + OH- H2O
OR
It is the reaction of acid with base form salt and water
Eg : NaOH + HCl NaCl + H2O
(b) Water which Gives lather readily with soap. It does not contains dissolved
impurities like Ca or Mg salt
PART-B
(Maximum marks: 16)
(Answer any two full question .Each question carries 8 marks)
II)
(a) Magnesium metal burns in oxygen to form Magnesium oxide (MgO) as per the
equation: Mg+O2 MgO
How many grams of oxygen are needed to react with 25 g of magnesium? How
many grams of magnesium oxide will result? 4
(b) Explain the electronic concept of oxidation and reduction .Give one example. 4
III)
(a) What are buffer solutions? Give two examples? 4
(b) What are carbon nanotubes? Explain the structure of carbon nanotubes. 4
IV)
(a) Describe chemical vapour deposition method for the carbon nanotube ? 4
(b) Explain ion exchange method. ? 4
Answers
II)
(a) 2Mg+O2 2MgO
48 32
25 ?
So amount of oxygen needed to react with 25g Mg is
= 25x32/48
=16.66g O2
Also consider 2Mg+O2 2MgO
48 g 80g
25 ?
So amount of MgO formed =25x20/48
=41.66g
(b) Oxidation: Losing of electron is called oxidation. During oxidation, oxidation
number increases ex: Zn Zn2+ +2e
Reduction: Gaining of electron is called reduction. During reduction, oxidation
number decreases Ex :Cu2+ + 2e Cu
III)
(a) Buffer solution: Solution which resist change in pH when small amount of acid or
base added to it. Ex: Blood, NH4OH + NH4Cl
(b) Its structure seemed to be formed by rolling the sheet of graphite in to the shape
of cylindrical tube either closed or open at the end.
Two varieties of CNT are SWNT (Single Walled Carbon Nano Tube.It is like a single
cylinder) and MWNT (multi Wallled Carbon Nano Tube.It contains multiple
concentric nano tube cylinder)
Based on orientation of lattice, nano tubes are Classified in to three types
1) Arm Chair
2)Zig Zag
3)Chiral
IV)
a) Chemical Vapor Deposition Method(C V D) : Here CH4 heated in a chamber
containing Fe as catalyst at high temperature. So that C-H bond breaks form ‘C’
atom. This C atom bind with other C atom form nanotube lattice.
b) It can be removed by using synthetic resins like Cation exchanger [E-H+] or anion
exchanger [E-OH-] as shown below
Step 1:
Hard water passed through a tank containing [E-H+] so the following occur
2 E-H+ + Ca2+ E2Ca + 2H+
Step 2:
This water coming out of cation exchanger is then passed through anion exchanger
[E-OH-]
ie E-OH- + Cl- ECl + OH-
and H+ + OH- H2O
PART-C
(Maximum marks:30)
(Answer one full question from each unit. Each question carries 15 marks)
V)
(a) Write down the molecular formula of following compounds :
(i) Sodium sulphate (iii) Potassium carbonate
(ii) Ammonium phosphate (iv) Aluminium chloride 4
(b) What is the volume of the solution that would result by diluting 70 ml of
0.0931 N NaOH to a concentration of 0.0150 N ? 4
(c) Explain the Lewis concept of acid and base with an example ? 4
(d) Which indicator you would adopt for the titration of Na2CO3 xH2SO4 ?
give reason ? 3
OR
VI)
(a) Explain the following terms with two example for each :
(i) Radical (ii) Valency 4
(b) What you understand about :
(i) Strong acid and strong bace (ii) Weak acid and weak base. 4
(c) The sterile saline solution used to rinse contact lenses can be made by dissolving
400 mg. of NaCl in sterile water and diluting to 100 ml .What is the molarity of the
solution ? 4
(d) Balance the following equations:
(i) C3H8 +O2 CO2 +H 2O
(ii) Mg +HNO3 H2 +Mg(NO3 )2 3
Answers
V)
a)
i) Na2(SO4) iii) K2CO3
ii) (NH4)3(PO4) iv) AlCl3
b) N1V1=N2V2
N1=6.0913N V1=70 ml N2=0.0150n V 2= ?
N2 =N1V1/N2
= 0.0913x70/0.0150
=426ml
c) Acid Base
electronic pair acceptor electronic pair donor
electron deficient electron rich
Ex:H+,BF3,AlCl3,FeCl3,all cations Ex: NH3,H2O,OH-,all anions
d) Methyl orange. Because here pH range at the point is 3.5 to 7.5
VI)
a)
i)Charged atom or atom groups are called radicals : NH4+,Cl- etc
ii) Combining capacity of an element is called valence.Ex:For Hydrogen it is 1
and for Oxygen it is 2.
b) i)
Strong Acids Strong Bases
Acids which dissociate Bases which dissociate
completely completely
Ex: HCl, H2SO4 Ex: NaOH, KOH etc
HCL H++Cl- NaOH Na++OH-
ii)
Weak Acid Weak Bases
Acids which dissociate Bases which dissociate partially
partially Ex: NH4OH, Na2CO3
Ex: CH3COOH,Oxalic acid
ie,NH4OH NH4++OH-
CH3COOH +
H +CH3COO -
c) M=W2x1000/M2xVolume in ml
W2=400 mg= 400x10-3g
M2=NaCl=23+35.5=58.5
Vol in ml=100
M=400x10-3x1000/58.5x100
=0.068 M
d) i) Common equation to balance combution of Hydro carbon is
Cx Hy +(x+y/4)O2 CO2+y/2 H2O
Here x=3 , y=8
So C3H8 +(3+8/4)O2 3CO2 +8/2 H2O
OR
C3H8+ 5O2 3CO2 + 4H2O. It is the balanced equation
ii) Mg +2HNO3 Mg (NO3)2 + H2
UNIT-II
VII)
(a)Draw a flow chart for the production of potable water for municipal supply. 4
(b) Explain the disadvantages of hard water.? 4
(c) What are the properties of carbon nanotubes ? 4
(d) Give any three applications of carbon nanotubes ? 3
OR
VIII)
(a) What are the application of nanomaterials in medicine? 4
(b) Explain the reason for temporary hardness and how it can be removed ? 4
(c) What is sterilization of water? Mention the different methods of sterilization
of water ? 4
(d) Explain Plasma process.? 4
Answers
VII)
a)
Screening
Sedimentation
Coagulation
Filtration
Sterilization
Potable water
b)
I) In laundry :
i)Wastage of soap: because While washing with hard water,soap from lather
only after removing all dissolved impurities, so cause wastage of soap.
ii) It cause spot and streak on the cloth.
II)In steam boiler :
i)Wastage of fuel:- Hard water cause a hard deposit on boiler called scale. It
cause wastage of fuel
ii)Cause explosion of boiler: Due to intense heat , the scale may crack and
Cause explosion of boiler (because it is a heat insulating one.)
iii) Cause corrosion of the boiler: Because of the formation of HCl as shown
below.
MgCl2 + H2O Mg(OH)2 + 2HCl
III) Not use for cooking, bathing etc.
c)
1. Very strong
2. High tensile strength & thermal conductivity
3.High Young’s modulus (for force required to bent a material)
4. High electrical conductivity
d) i) In strengthen composite material. ii) Act as a molecular type test tube&
capsules for drug delivary. iii) Can act as conductor & semiconductor based on their
size. iv) As a tips for analysis of DNA &Proteins by Atomic force Microscopy.
OR
VIII)
a)
1. Act as molecular type test. tube and capsule for drug delivery
2. As a tips for analysis DNA and proteins by a atomic force microscopy.
3. Can detect an locate tumors accurately.
4. Nano shell attaching only to cancer shell and destroy tumor
5. Can deliver right amount of medicine to exact spot of the body using nano
technology.
b) Temporary Hardness-It is due to HCO3- of Ca and Mg. it can be removed by boiling.
M(HCO3)2 MCO3 +H2O +CO2 M= Ca or Mg
c) Sterilization it is the destroying of disease causing bacteria and micro organism
using fertilizers or disinfectant like bleaching powder etc. These are
1. Chlorination : By passing chlorine gas or water. It need less space Cl2
available in pure form are advantages, but excess Cl2 cause unpleasant smell,
taste etc.
2 .Using bleaching powder : Mix 1Kg CaOCl2 with 1000kilo liter water. By
oxidizing action of Cl , It kills the germs.
3.By passing Ozone(O3). On passing O3 through water, following reaction
occur. O3 O2 + [O]
Here nascent oxygen produces killed the germs by oxidizing action. Its excess
is not armful]
d) Plasma Process: Here CH4 Is passed through a plasma Torch (ie; high temperature
producing substance).So that C-H bond breaks from 'c' atom binds with other 'c'
atoms from nano tube lattice.
