TED(10)-1003 B                                            Reg No..................
(REVISION-2010)                                           Signature...............
                 FIRST SEMESTER DIPLOMA EXAMINATION IN ENGINEERING
                              TECHNOLOGY-OCTOBER,2011
                             APPLIED SCIENCE-1 (Chemistry)
                            (Common except DCP and CABM)
                               [Time:11/2 hours]
                 (Maximum marks:50)
                                        PART-A
                 (Maximum marks: 4)             Marks
I) answer the following questions in one or two sentences. Each question carries 2 marks.
      (a)Write down the molecular formula of                     (2)
              1) Aluminium phosphate 2) Ammonium carbonate
      (b)Mention plasma process                          (2)
                                    (2x2=4)
                                         Answers
I)    a)
           1) Al3(PO4)3
           = Al( PO4)
           2) (NH4)2(CO3)
      b) Plasma Process: Here CH4 Is passed through a plasma Torch (ie; high temperature
      producing substance).So that C-H bond breaks from 'c' atom binds with other 'c'
      atoms from nano tube lattice.
                               PART-B
                           (Maximum marks:16)
                 (Answer any two full questions. Each question carries 8 marks)
II)
           (a) Explain the terms
                   1) symbol                               2) molecular formula        4
           (b)Define equivalent weight of bases and acids .Calculate the equivalent weight of
                                             i) Sulphuric acid        ii) calcium hydroxide        (4)
III)
           (a) How do water become hard? Define degree of hardness.                4
           (b)Explain the application of carbon nano materials in medicine     4
IV)
           a) Account for the following                          4
                   (i) pH of the blood remain constant
                   (ii) When acid is added to water pH value of water decreases?
            b) Calculate the normality of HCl which contains 2.281g of the acid in 200ml. find out
      the volume of this solution required to neutralize exactly 50ml of 0.12 N sodium hydroxide
                                                    solution?                                   (4)
                                                Answers
II)
           a)
       i)Symbol =Short hand representation of an element eg: Hydrogen =H
       ii) Molecular formula(MF):
                Actual number of various elements in a molecular or symbolic representation of a
           molecule eg: for water is H2O
           b) Equivalent weight of acid=
              For H2SO4 it is =
                              =98/2
                              = 49
       Equivalent weight of BASE =
       For Ca(OH)2 It is      =
                              =74/2
                              =37
III)
       a) It is due to presence of dissolved impurities like HCO3-, Cl- & SO42- of Ca and Mg. It
       Form insoluble scum with soap. There are two types
       1) Temporary Hardness:- It is due to HCO3- of Ca and Mg.
       2) Permanent Hardness:- It is due to Cl-, SO42- of Ca and Mg.
       Degree of Hardness:
                It is the number of parts by weight of CaCO3 present in one million (106)
       parts by weights of water. Unit= PPM (Parts Per Million)
       b) 1. Act as molecular type test-tube and capsule for drug delivery
               2. As a tips for analysis of DNA and proteins by a atomic force microscopy.
               3. Can detect and locate tumors accurately.
               4. Nano shell attaching only to cancer shell and destroy tumor
              5. Can deliver right amount of medicine to exact spot of the body using nano
              technology.
IV)
       a)
               (i) Because Blood is buffer or due to combined action of HCO3-/CO32+ buffer
              (ii) When acid is added to water ,H+ ion concentration increases this cause
              decrease in pH of water
       b) N = =
                =
                =0.312N
      N1=0.312 V1=? N2= 0.12 V2= 50ml
         There for V1   =
                        = 19.23 ml
                                            PART -C
                  (Maximum marks : 30)
      (Answer one full question from each unit. Each question carries 15 marks)
                                            UNIT-1
V)
         (a) What are radicals? Classify them with two examples for each type 4
                                     (b)Balance the following equation:                      (4)
               (i) KMnO4 + HCl  KCl + MnCl2 + H2O +Cl2
               (ii) Fe+H2O Fe2O3+H2
         (c) Calculate the oxidation number of manganese in any tow compounds and in
         one radical.                           3
        (d)Explain redox reaction taking a suitable example. mention different concept also.(4)
                                               OR
VI)
         (a) Define ionic product of water. How will you arrive its value?        (3)
         (b) A solution is prepared by dissolving 0.49 of NaOH in 500 ml .What is the pH of the
                                                    solution?                                (4)
             (c)What is mean by indicator range? Give two example.                 (4)
       (d) How many moles how many grams of sodium chloride are present in 250ml of
           0.25 M NaCl solution ?                                                    4
                      Answers
V)
       a) Charged atom or atom groups are called Radical Ex: NH4+, Cl- etc. Radicals are classified as
       shown below
                                                            Radical
Positively charged/Cations                                                       Negatively charged/Anions
 Mono           Di                    Tri                                   Mono             Di               Tri
Ex: NH4+       Ca2+              Al3+
                                                                            NO3-             CO32-           PO43-
       b)
                 (i) 2KMnO4 + 16HCl 2 KCl + 2MnCl2 +8H2O +5Cl 2
                 (ii) 2Fe+3H2O  Fe2O3+3H2
            x -2                +1 x -2                            x     2- 1-
       c) Mn O2                K Mn O4                         (Mn     O4   )
           X – 4= 0          (+1)+ X – 8=0                     X –8=-1
             X=+4             X=+7                      X=+7
       d) Redox reaction:
       Oxidation and reduction together is known as redox reaction eg: Daniel cell(Zn-Cu
       galvanic cell)
                        2+
       Ie Zn  Zn +2e (Oxidation) …..(1)
          2+
       Cu + 2e   Cu (reduction)………….(2)
                          2+                2+
       (1)+(2)= Zn + Cu         Zn              + Cu
       Oxidation: Losing of electron is known as Oxidation. During Oxidation , Oxidation
                                                 2+
       number increases eg: Zn  Zn                   +2e
      Reduction: Gaining of electrons is called reduction. During reduction, Oxidation
                               2+
      number decreases eg: Cu + 2e  Cu
                                                OR
VI)
      a) Ionic product of water [Kw] is the product of concentration of H+ and OH- ions in
      water.
      It was experimentally found that at 250C , [H+]=[OH-]=10-7 mol/liter.
      So Kw =10-7 x 10-7 mol/liter at 250C
                OR
      Kw = 10-14 mol2/liter2
      b)          M=
                         =
                         =0.0245 mol/L
                                 -
                         =[OH ]
                           -14             -
           So   [H+]= 10         / [OH ]
                         -14
                  = 10         / 0.0245
                                     -13
                     =4.08 10
       pH = -log [H+]
                                      -13
                =-log[4.08 10               ]
              =12.38
       c) Indicator range: it is the range of pH in which an indicator changes the colour
       methyl orange 3.1 to 4.5
       Phenolphthalein 8.3 to 10
       d) we have M =
           or
                         W2=
                               =3.65g
       no. of moles =W2/M2
                         =3.65/58.5
                         =0 .0623
                                                     UNIT-II
VII)
        (a) What are the advantage and disadvantage of soft and hard water?          (4)
        (b) Describe two methords of synthesis of carbon nano tube            (4)
        (c) Explain different types of filtration used in water treatment      (4)
        (d) Give any tree application of carbon nano tube               (3)
                             OR
VIII)
         (a)Explain different methods of used for the removal of hardness in water. (4)
                    (b) What are the properties of carbon nano tubes?                 (3)
          (c)Give four characteristics of portable water. Draw a flow chat for the production of
                        portable water for municipal supply.                    (4)
         (d) What are carbon nano tube?Comment on its structure.              (4)
                                                     Answers
VII)
         a)
                 SOFT WATER                             HARD WATER
            Gives lather readily with           Gives lather readily with soap .it
             soap                                 contain dissolved impurities like
            Advantage:                               3- -       2-
             Used for                             HCO ,Cl ,SO4 ,Ca and Mg
                 Cooking                         Advantage:
                 Bathing
                 In boiler                        Form insoluble scum with
                 In laundry purpose                soap
                                                                 2+    2+
                     etc                           Contain Ca ,Mg ions
            Disadvantage:                           required for health
                 It dissolves Pb of             Disadvantage:
                     lead pipe which              Not Used for
                     cause poisness                   Cooking
                 Do not contain                      Bathing
                       2+     2+
                    Ca ,Mg ions                       In boiler
                    required for health               In laundry purpose etc
b)
        a) High pressure Carbon Monoxide Deposition Method (HiPCO):
CO(g)&atoms of iron cluster are heated in a chamber at high pressure. So that Fe
breaks the CO molecules as C&O2 by acting as a catalyst. This ‘C’ atom bind with
other ‘C’ atoms form nanotube lattice. O2 react with unburnt CO form CO2
       b) Chemical Vapor deposition Method (CVD): Here CH4 is heated in a
chamber containing Fe as catalyst at high temperature. So that C-H bond breaks
from ‘C’ atom. This ‘C’ atom binds with other ‘C’ atoms form nano tube lattice
c) Filtration: Used to remove colloidal and bacterial impurities from water. These are
       1. Operation of gravity sand filter method:
              It is done as shown below
        2. Operation of pressure filter method:
                          Here filtering medium is essentially same as above. Filtering materials
                  is kept in a closed cylinder and water is forced into filter under pressure. It is
                  used for hot water, require less space.
        d) i) It strengthen composite material. ii) Act as a molecular size test tube& capsules
        for drug delivary. iii) Can act as conductor & semiconductor based on their size. iv)
        As a tips for analysis of DNA &Proteins by Atomic force Microscopy.
                                                 OR
VIII)
        a) Different type of hardness are
           Temporary hardness: It is due to HCO3 of Ca and Mg. it can be removed by
           boiling.
           M(HCO3)2  MCO3 + H2O+ CO2 M= Ca/Mg
                                              -
           Permanent hardness: It is due to Cl , SO42-,Ca and Mg. It can be removed by using
           synthetic resins like Cation exchanger [E-H+] or anion exchanger [E-OH-] as shown
           below
           Step 1:
           Hard water passed through a tank containing [E-H+] so the following occur
            2 E-H+ + Ca2+  E2Ca + 2H+
        Step 2:
        This water coming out of cation exchanger is then passed through anion exchanger
        [E-OH-]
        ie     E-OH- + Cl-  ECl + OH-
 and H+ + OH-  H2O
b)     1.Very strong
       2. High tensile strength & thermal conductivity
       3.High Young’s modulus ( force required to bent a material)
       4. High electrical conductivity
c) Portable water: Water which safe to drink. it is need not be pure like distilled
water.
Characteristics:
1)It should be clear and odourless
2)it should free from micro organism like bacteria etc..
3)it should free from dissolved gases like H2S, CO2 and minerals like NO31- ,NO21—etc
                        Screening
                   Sedimentation
                   Coagulation
                       Filtration
                       Sterilization
                   Potable water
d) Its structure seemed to be formed by rolling the sheet of graphite in to the shape
of cylindrical tube either closed or open at the end.
 Two varieties of CNT are SWNT (Single Walled Carbon Nano Tube. It is like a single
cylinder) and MWNT (multi Wallled Carbon Nano Tube. It contains multiple
concentric nano tube cylinder)
 Based on orientation of lattice, nano tubes are classified in to three types
1) Arm Chair
2)Zig Zag
3)Chiral