1968 Delaware gubernatorial election
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Peterson: 50–60% 60–70% 70–80% Terry: 50–60% 60–70% 70–80% | |||||||||||||||||
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| Elections in Delaware |
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The 1968 Delaware gubernatorial election was held on November 5, 1968. Republican nominee Russell W. Peterson defeated incumbent Democratic Governor Charles L. Terry Jr. with 50.51% of the vote.
General election
Nominations
Nominations were made by party conventions.[1][2]
Candidates
- Russell W. Peterson, Republican, civic activist
- Charles L. Terry Jr., Democratic, incumbent Governor
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Russell W. Peterson | 104,474 | 50.51% | ||
| Democratic | Charles L. Terry Jr. (incumbent) | 102,360 | 49.49% | ||
| Majority | 2,114 | 1.02% | |||
| Turnout | 206,834 | 100.00% | |||
| Republican gain from Democratic | Swing | ||||
References
- ^ America Votes 8, p. 62.
- ^ Delaware Official Results 1968, p. 17.
- ^ "DE Governor, 1968". Our Campaigns. Retrieved June 4, 2020.
- ^ America Votes 8, p. 58.
- ^ Delaware Official Results 1968, p. 2.
- ^ Congressional Quarterly 1998, p. 46.
Bibliography
- George W. Cripps, Commissioner of Elections (1969). Official Results of General Election, 1968 (PDF). State of Delaware.
- Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
- Scammon, Richard M., ed. (1956). America Votes 8: a handbook of contemporary American election statistics, 1968. Washington, D.C.: Governmental Affairs Institute (published 1970).