1845 New Hampshire gubernatorial election
Appearance
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County results Steele: 40–50% 50–60% 60–70% 70–80% Colby: 40–50% | |||||||||||||||||||||
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Elections in New Hampshire |
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The 1845 New Hampshire gubernatorial election was held on 11 March 1845 in order to elect the governor of New Hampshire. Incumbent Democratic governor John Hardy Steele won re-election against Whig nominee and former member of the New Hampshire House of Representatives Anthony Colby and Liberty nominee Daniel Hoit in a rematch of the previous election.[1]
General election
[edit]On election day, 11 March 1845, incumbent Democratic governor John Hardy Steele won re-election by a margin of 7,821 votes against his foremost opponent Whig nominee Anthony Colby, thereby retaining Democratic control over the office of governor. Steele was sworn in for his second term on 4 June 1845.[2]
Results
[edit]Party | Candidate | Votes | % | |
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Democratic | John Hardy Steele (incumbent) | 23,406 | 51.14 | |
Whig | Anthony Colby | 15,585 | 34.05 | |
Liberty | Daniel Hoit | 5,786 | 12.64 | |
Scattering | 988 | 2.17 | ||
Total votes | 45,765 | 100.00 | ||
Democratic hold |
References
[edit]- ^ "John Hardy Steele". National Governors Association. Retrieved 2 April 2024.
- ^ "NH Governor". ourcampaigns.com. 3 June 2005. Retrieved 2 April 2024.
Categories:
- 1845 New Hampshire elections
- New Hampshire gubernatorial elections
- 1845 United States gubernatorial elections
- March 1845 events
- 1845 in New Hampshire
- 1840s in New Hampshire
- 1840s New Hampshire elections
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- 1845 elections in North America
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- United States gubernatorial elections in the 1840s
- Government of New Hampshire