1868 Georgia gubernatorial election
Appearance
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Results by County: Bullock: 50–60% 60–70% 70–80% 80–90% >90% Gordon: 50–60% 60–70% 70–80% 80–90% >90% No vote | |||||||||||||||||
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Elections in Georgia |
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The 1868 Georgia gubernatorial election was held on 20 April 1868 in order to elect the Governor of Georgia. Republican nominee and former Lieutenant colonel of the Confederate States Army Rufus Bullock defeated Democratic nominee and former Major general of the Confederate States Army John B. Gordon.[1]
General election
[edit]On election day, 20 April 1868, Republican nominee Rufus Bullock won the election by a margin of 7,171 votes against his opponent Democratic nominee John B. Gordon, thereby gaining Republican control over the office of Governor. Bullock was sworn in as the 46th Governor of Georgia on 21 July 1868.[2]
Results
[edit]Party | Candidate | Votes | % | |
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Republican | Rufus Bullock | 83,527 | 52.24 | |
Democratic | John B. Gordon | 76,356 | 47.76 | |
Total votes | 159,883 | 100.00 | ||
Republican gain from Democratic |
References
[edit]- ^ "Gov. Rufus Bullock". National Governors Association. Retrieved 1 January 2024.
- ^ "GA Governor". ourcampaigns.com. 6 November 2023. Retrieved 1 January 2024.
Categories:
- Georgia (U.S. state) gubernatorial elections
- 1868 United States gubernatorial elections
- 1868 Georgia (U.S. state) elections
- April 1868 events
- 1868 in Georgia (U.S. state)
- 1860s in Georgia (U.S. state)
- 1860s Georgia (U.S. state) elections
- 1868 elections
- 1868 elections in North America
- 1868 elections in the United States
- United States gubernatorial elections in the 1860s
- Government of Georgia (U.S. state)