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Strap Footing Calculation:: R1 428.6276 KN R2 320.24kN

This document summarizes the design of a strap footing to support multiple columns. It calculates the required footing areas and dimensions for two columns based on their service loads. It then analyzes the thickness, reinforcement, bending moments, and punching shear capacity of the footings. Finally, it evaluates a combined footing to support a grid of columns, calculating the forces, moments, stresses and checking that all values are within code limits.

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0% found this document useful (0 votes)
101 views6 pages

Strap Footing Calculation:: R1 428.6276 KN R2 320.24kN

This document summarizes the design of a strap footing to support multiple columns. It calculates the required footing areas and dimensions for two columns based on their service loads. It then analyzes the thickness, reinforcement, bending moments, and punching shear capacity of the footings. Finally, it evaluates a combined footing to support a grid of columns, calculating the forces, moments, stresses and checking that all values are within code limits.

Uploaded by

subhekshya
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as DOCX, PDF, TXT or read online on Scribd
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Strap footing calculation:

ColumnID,
Service
Load(DL+LL)
A1 342.622 kN
B1 406.2506 kN

Area of footing
required A1 3.02 m2
Area of footing
required A2 3.58 m2
Square Size Adopted ,L1xB1 1.8 m
Square Size Adopted ,L2xB2 1.905 m

R1= 428.6276 kN
R2= 320.24kN

eccentricity at footing
F1,e= 0.7492 m
Udl under footing F1 357.1897 kN/m
Udl under footing F2 252.1609 kN/m

Thickness of footing:

i)one way shear:

For footing F1:

Let us assume Pt=0.2% so from tble 16 of IS 456:2000,

Tc=0.2 Mpa

Shear=bdTc=qu(0.75-d)
Therefore,d=0.298 m

For footing F2:

Let us assume Pt=0.2% so from table 16 of Is 456:2000,

Tc=0.2 Mpa

Shear=bdTc=qu(0.8025-d)

Therefore,d=0.245 m

ii) Two way shear:

for column A1:

from clause 31.6.3.1 of IS 456-2000

βc=width of column/length =1

ks= βc+0.5=1.5≤1

Tc=ks(0.25)sqrt(fck)

=1.118 Mpa

Critical perimeterxdxTc=Pu-qu*(critical area-dotted area)

Assume d=363 mm

Hence Tc=0.646 Mpa <1.118 Mpa, safe in punching

Reinforcement for flexure for footings:

i)From bending moment diagram

Mmax=114.89*10^6 KN-m=114.89*10^6 N-mm

Mu/bd2 = 0.457

From Table 2 of SP-16, pt=0.106%

Ast required=733 mm2

Let us provide Ast 12 mm @ 150 mm c/c


Hence ,Ast provided=753.33 mm2

Design for bending in beam,

From bending moment diagram,

Max bending moment= 262*10^6 kN-m

Assume beam total depth=600 mm

Beam width= 300 mm

Mu/bd^2 = 2.994

From table 54,

Percentage of steel in tension=0.837 %

Percentage of steel in compression=0.086%

Hence provide 6-20mm dia @ top and 4-16 mm dia @ bottom.

Combined footing calculation:

Grid A-3,B-3, A-2, B-2

Geometry of
MAT:
Area, A = 19.773 m2
CG of Area in X-
Dir, x = 2.017 m
CG of Area in Y-
Dir, y = 1.8312 m
CG of Load in X-
Dir, x' = 1.751 m
CG of Load in Y-
Dir, y' = 1.564 m
ex = -0.266 m
ey = -0.117 m
Ixx = 30.95 m4
Iyy = 34.3 m4
-
Mxx = P*ex = 449.896 kNm
-
Myy = P*ey = 198.322 kNm
P/A = 85.630 kN/m2

Soil Bearing Capacity, SBC = 125 kN/m2


Moment of axial
From origin
load @ axes X co- Y co-
Stress
Joint P Factored ordinate ordinate =
(KN/Sq- CHECK
Name (KN) Load Distance Distance P*x P*y = x-x1 y-y1
m)
Along X Along Y KNm KNm (m) (m)
(x) (m) (y) (m)
2A 216.71 325.07 0.00 0.00 0.00 0.00 -2.02 -1.68 124.67 OK
2B 513.21 769.82 3.73 0.00 1916.23 0.00 1.72 -1.68 70.39 OK
3A 57.90 86.84 0.00 3.99 0.00 230.88 -2.02 2.31 101.61 OK
3B 121.84 182.77 3.73 3.99 454.94 485.89 1.72 2.31 47.34 OK
A62 50.14 75.22 0.00 3.32 0.00 166.64 -2.02 1.64 105.45 OK
A66 67.33 101.00 0.00 2.66 0.00 179.00 -2.02 0.98 109.30 OK
A68 90.33 135.50 0.00 1.99 0.00 180.11 -2.02 0.31 113.14 OK
A70 123.96 185.94 0.00 1.33 0.00 164.78 -2.02 -0.35 116.98 OK
A72 165.90 248.85 0.00 0.66 0.00 108.93 -2.02 -1.02 120.87 OK
3-167 38.16 57.24 0.62 3.99 23.75 152.19 -1.39 2.31 92.57 OK
3-169 47.32 70.99 1.24 3.97 58.90 187.92 -0.77 2.29 83.62 OK
3-171 56.72 85.08 1.87 3.96 105.89 224.74 -0.15 2.28 74.62 OK
3-173 66.71 100.07 2.49 3.95 166.06 263.78 0.47 2.27 65.62 OK
3-175 76.88 115.31 3.11 3.95 239.20 303.31 1.09 2.26 56.63 OK
1693.13 2964.97 2648.16
Maximum Bending moment calculation:
Max positive bending moment=46.93 kN-m/m
Max negative bending moment=143.08 kN-m/m
𝐵𝑀𝑚𝑎𝑥
Positive Moment: √
0.133𝜎𝑐𝑏 𝑏
Required effective depth =

= 231.93 mm
OK
Area of Reinforcement:
𝑓𝑦 ∗ 𝐴𝑠𝑡
𝑀 = 0.87 ∗ 𝑓𝑦 ∗ 𝐴𝑠𝑡 (𝑑 − )
𝑓𝑐𝑘 ∗ 𝑏

Ast required = 748 mm2

Provide 12 mm rebar @ 150 mm c/c

Punching depth check


Central Column, B2
Load on column,
= 769.817 kN
Pu
= 769817 N
Soil Pressure = 146.297 kN/m2
= 0.146297 N/mm2
Assuming, d = 369 mm
X-Dir Side
= 667.8 mm
Length
Y-Dir Side
= 667.8 mm
Length
Perimeter, bo = 2671.2 mm
τv = Vu
bo*d
= 0.73 N/mm2
0.25√𝑓𝑐𝑘
τc
=
= 1.118034 N/mm2

Corner Column,A2
Load on column,
= 391.3612 kN
Pu
= 391361.2 N
Soil Pressure = 169.72 kN/m2
= 0.16972 N/mm2
Assuming, d = 369 mm
X-Dir Side
= 486.3 mm
Length
Y-Dir Side
= 936.3 mm
Length
Perimeter, bo = 1422.6 mm
τv = Vu
bo*d
= 0.61 N/mm2
0.25√𝑓𝑐𝑘
τc
=
= 1.118 N/mm2

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