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Mcqs On Nodes

1) The total number of nodes in the 5th shell of an atom is 100. The formula for calculating total nodes in a shell is Total Nodes=n^2(n-1), where n is the shell number. 2) The number of radial nodes in the 4th shell of an atom is 14. The total nodes in the 4th shell is 48, calculated using the same formula. The total angular nodes is 34. Subtracting the angular nodes from the total nodes gives the radial nodes. 3) The total nodes in the 5d subshell is 20. The formula used is Total Nodes=(2l+1)(n-1), where l is the orbital angular momentum quantum number

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820 views3 pages

Mcqs On Nodes

1) The total number of nodes in the 5th shell of an atom is 100. The formula for calculating total nodes in a shell is Total Nodes=n^2(n-1), where n is the shell number. 2) The number of radial nodes in the 4th shell of an atom is 14. The total nodes in the 4th shell is 48, calculated using the same formula. The total angular nodes is 34. Subtracting the angular nodes from the total nodes gives the radial nodes. 3) The total nodes in the 5d subshell is 20. The formula used is Total Nodes=(2l+1)(n-1), where l is the orbital angular momentum quantum number

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Ihtisham Ul Haq
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Hints And Tricks In Chemistry

Mcqs On The Nodes Of An Atom


1) Total number of nodes in 5th shell will be
A) 5
B) 50
C) 100
D) 200
Solution:
Total Nodes in shell will be find by the following
formula
Total Nodes=n^2(n-1)
Here
n=5 so
T.N=5^2(5-1)
T.N=25(4)
T.N=100
2) What is the number of radial nodes in 4th shell
of an atom?
A) 48
B) 34
C) 14
D) 96
Solution:
First find T.N in 4th shell.
T.N=n^2(n-1)
T.N=4^2(4-1)
T.N=16×3
T.N=48
Now find total number of angular nodes in 4th
shell.
There are four sub shells in 4th shell, they are s, p,
d and f.
Angular nodes in sub shell will be find by the
following formula
A.N=(2l+1)l
So
Angular nodes for s sub shell=0
Angular nodes for p sub shell=3
Angular nodes for d sub shell=10
Angular nodes for f sub shell=21
So
Total angular nodes=0+3+10+21
Total angular nodes=34
Now
Radial nodes in the 4th shell will be find by just
subtracting angular nodes from total nodes, there
fore
Radial nodes=T.N - A.N
Radial nodes=48-34
Radial nodes=14
3) Number of total nodes and radial nodes in the 5d
sub shell will be
A) 10
B) 20
C) 25
D) 30
Solution:
For sub shell following formula will be used
T.N=(2l+1)(n-1)
T.N=(2×2+1)(5-1) (For d sub shell l=2)
T.N=(4+1)(4)
T.N=5×4
T.N=20
Now
Radial nodes=(2l+1)(n-1) - (2l+1)l
Radial nodes=(2×2+1)(5-1) -(2×2+1)×2
Radial nodes=(4+1)(4) - (4+1)×2
Radial nodes=5×4 - 5×2
Radial nodes=20-10
Radial nodes=10

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