We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF or read online on Scribd
You are on page 1/ 4
PROBLEM SET (ME 514-FLAT BELT)
1. A20 hp, 1750 rpm, slip ring is to drive a ventilating fan at 330 rpm. The
horizontal center distance must be about 8 to 9 ft. for clearance, and
Operation is continuous, 24 hr./day. (a) What driving pulley size is needed
for a speed recommended as optimum in the text? (b) Decide upon a pulley
size (iron or steel) and belt thickness and determine the belt width by the
ALBA tables. (c) Compute the stress from the general belt equation
‘assuming that the applicable coefficient of friction is that suggested by the
text.
A100 hp squirrel cage, line starting electric motor is used to drive a Freon
reciprocating compressor and turns at 1140 rpm; for the cast-iron motor
pulley, D, = 16 in.; D, = 53 in., a flywheel; cemented joints; C = 8 ft. (a)
Choose an appropriate belt thickness and determine the belt width by the
ALBA tables. (b) Using the design stress, compute the coefficient of friction
that would be needed.
3. Amotor is driving a centrifugal compressor through a 6 in. heavy, single ply
leather belt in a dusty location. The 8 in. motor pulley turns 1750 rpm; D2 =
12 in. (compressor shaft); C = 5 ft. The belt has been designed for a net belt
pull of F; —F, 40 tb/in. of width and F,/F, = 3. Compute (a) the horsepower
(b) The stress in the tight side. (c) For this stress, what needed value of f is
indicated by the general belt equation? (d) Considering the original data,
what horsepower is obtained from the ALBA tables?
4. A25 hp, 870 rpm motor with a 12 in. pulley drives a centrifugal pump at
290 rpm by means of a medium double leather belt laced with wire by
hand. Determine the width and length of the belt required, allowing for
20% overload and 4 ft. center distance.
_
4d os pins, biel de Sek MAAN Ut
Bi ees cea nn) (15900-)
TPA Gs B= apt =} — TON i AO a5. 81-4 29h
a) Wi deh dete gpr = 4700 FPR Coxe Bore)
ee
Oak (Iso rahe)
te 4 AGS wef Ton Das $3 -0303 ing
GY tad deve, te -
nae mmem: We ae a
Tale OF: cms Od (MUM); 20-7 7) .
nes Me (8) Com) Cop) Cen? a —
7 {pes Mb
Ze mae(enconay
Deak + 320009, $3000 EC (apy 7 :
yr Pa + Seeothe ES (coke) ge Te, PMA, ay assy
Ta Fie to 4 ——
Rotor 4 iF ert AAT
we aii 75D)
= 9038 Tin : 7 =
7 ay
ae ee TM, 7 8ey
| ~ -
frotet EH oe
iy (0.08 aE
Le cain) (2
[p64 058 us = (5-00 (am) [= aie
“
Tips 21512140
=
om lip thin he
350% i
ii See
iors Toate PLY ay
U0 rpm Geter
om ett wh Me
» plea C00). ame seks perme 1 AES HT
fas TE? a O87 GEN;
a Seer tear tes tery
[oohp = TTY & (0-5) (0-9) O13
eens
bale tim | rm eT fe= ET
+) gy =p, > ReVehe . sr00 (Wobe)
% 4775 Tp ani
(P0035 Yat ge0- 2d, gS —
Ye ERP 74. 7 Fly : a - .
study 8) = tl) aaa a
2 4 00psi — =
Woictory Ca =
DATE
2 a —
“rn (0-036 Whips) (TF. ae) L =
60412) — a
te Daree re 0-817
4) pe mam wlsinnlirsotrn) | 7
mC |_|.
Pitas fe A, Coe cin] ps WN SUSI Hino)
a fomes 2406» oom J F000 ES _ =
ee iat
24-656 4p |
Fmt ele O, ig ng,
Re a
ae fee Tepe CCLY,
R~ Bs 240 mam
fe (i=) = 240 ——= Ee Sar L
ere fs - aera
Frespryggie tea eo)
Fie
#: 0.058 “Yiu SAS Guan laryy Tats = (om ae 1
a] z ae
Mauer Fay 2S ordirtay Tet
as
ete ona ps ie LEST
aa UM 449574 > FO
+I
FORO G] Cpe OTs
2) rom fete dt
fre 2-2. Ome
ty HO) Cen) ly lly) = 1 CONT) (0) C870)
jae Le. 4iddhp |
4) te oe ya> DAtqm
Wo Bim
tam) te7epr}
rebinm, dose pM
Teed oT Ghd
52788. 1956 Phew
a) PBS OA Sop
tld — eee eB nla et he)
Cams ra Sane
ae Hy
Vuicrory [are
can Bin,
0085 Mis, ys CBRE aria ry, — aa
<< titi” OM
(0) 359 psi + tune
tap 3 Crome), Z
oo 2
osm Fey a EBs 2 oneey Z
¢
CON. aay
cribele= ROT RH]
sur. 2ta7is: 6 (Sie) [as2rK - Exesh vag EEOPET —
Tae
bet 34S3in
st) sae E Gordy s Ga
eee a es
Firm
a—raeeareaeel
t Hee
