Enrolment No. ae TECHNOLOGICAL UNIVERSITY 3R-VII (NEW) EXAMINATION = SUMMER 2022 , Date:03/06/2022 Design of Machine elements 02:30 PM TO 05:30 PM. * Total Mark: Anstructions: 1. Attempt all question: 1 2, Make suitable assumptions wherever necessary 3. Figures to the right indicate full marks, 4. Simple and no mmable scientific calculators are allowed, 5. Use of PSG design data book is permitted. 70 ManKs QA (a) It is required to standardize eleven shafts from 100 10 1000 mm diameter. 03 Specify their diameters. () Differentiate between 04 i, Rigid and exible coupling ji, Protected and unprotected flange couplin (©) Design and draw a protective type of cast iron flange coupling fora steel shaft 07 transmitting 15 KW at 200 r.p.m, and having an allowable shear stress of 40 MPa. The working stress in the bolts should not exceed 30 MPa. Assume that the same material is used for shaft and key and that the erushing stress is twice the value of its shear stress. The maximum torque is 25% greater than the full load torque, The shear stress for cast iron is [4 MPa. Q2 (a) What is nipping ina leaf spring? Discuss its rol. 03 (b) A mechanism used in printing machirery consists of a tension spring 0 assembled with a preload of 30 N. The wing diameter of spring is 2 mm with a spring index of 6. The spring has 18 activecoils. The spring wire is hard drawn and oil tempered having following materiel properties: Design shear stress = 680 MPa Modulus of rigidity = 80 kN/mm2 Determine : 1. the initial torsional shear stress in the wire: 2, spring rate: and3. the force to cause the body of the springto its yield strong (©) A pair of straight teeth spur gears, having 20° involute lull depth teeth is to 07 transmit 12 KW at 300 r.p.m, of the pinion, The speed ratio is 3+ 1. The allowable static stresses forgear of cast iron and pinion of steel are 60 MPa and teeth of pinion = 16; 1.3/4.5 +V),v being the 0,154-(0.912/No, of liameter of gears, Check the 600 MPa; Young's Moudulus for pinion = 200 KN/imm? and Young's Moudulus for gear=100 kN/am? 105 MPa respectively. Assuime the following: Number o! Face width = 14 times module; Velocity factor (Cv ) pitch fine velbeity in m/s; and tooth form factor (y) ecth)etermine the module, fave width and pitch « gears for wear: given aesn meshing with a 40 Ok ists of a 20 teeth pinio! Bere nonnal pressure ane 20°, The 0: rete diameters ofthe PINION and the geat distance: and Be hon Mend ant cen CHF}? diameters of the pi O8 ‘re the difference between Hydrodynamic and Hydrostatic Dearines. @ Journal Bearing design. 3 vernal consideration 1 4 360° hydrodynamic be: ‘yplain the th ‘The following « radial load = 3 2k Journal speed = 1490 rp" jata is given for ari journal diameter 50mm hearing lengtlr= 50mm radial clearance ~ 0. 05 mm 25eP viscosity of lubricant Assuming thatthe total heat eéner galoulate ated in the bearing is carried by the t flow in the beatin {(@) coetficient of friction: (ii) power lost in friction: (Git) minimum oil fim thickness: {iy) low requirement in Hitres/min; and (vy) temperature rise, OR Enlist causes of failure in rolling contact beatin {b) Selection procedure of rolling contact bearing from manufacturer's (©) The rolling contact ball beari ct ball bearing are to be selected to support th ountershahs The shall speed is720_ rp ia the. pen Me gees orrespondingto life of 24000 hours, The beatin (© an equivalent radial load of 1 kN. Consider | tment fe operating condition and material Me Geicy. and material as 0.9 and 0.85 respectivel BPE Gee eynansic load rang of th i cae logue, specified at 90% reliability a QA (a) What are the different types of wi ears in gear des! (b) Explain t lain the aspect of hent generatio form gears. : erie by cep prasecurs rconsncevngsnuene Exp ep prozedure for constructing structun Q4 (a) E aa ) Explain varipus types of of TocTeALSAtONS types of ends sed for pressure vess (H) Fxplan Clavarinos and ee A wom dive sansmis 1S kW at 2000 rps ton machine r.pan.The worm eres ine a span The worm is rp threaded RS aten dames br hart an of ed and has 65 mm piteh di te, Theoemers eles The tooth foam ist(b) Q5 (a) 0.10, Calculate ; 1. tangential force acting on the worm ; 2. axial thrust and separating force on worm: and 3. efficiency of the worm drive. What do you understand by 6 x 37 ropes? Explain with neat sketch the different rope section. What are the different types of ropes used in NOT cranes? How they are designated and selected in the hoisting mechanism. {c) «Discuss the stresses in wire ropes with formulas and explain the step by step Q.5 (a) (b) (c) procedure for wire rope design. OR Describe the basic objectives of material handling system. State the basic principles in selection of material handling equipment. Explain the different cross section being used for hook design, Discuss with neat sketches the valve gear mechanism for horizontal and vertical engines. Explain Poppet valve. 1 RO ei icici iieink: 03 o4 07 03 07z ze ee bate eee itis Aube to Stanauidize econ _“shalts linn oh PO diu_SPeats their diameters SB a as wea —_ : = — in i 0 ee een =O a a! “Ls & 425894) —5 4 = hi Goniw=ea snm Nees de = oo x (Lami? = 5 dh = 00 x (inset = oe Ne: | = cL. = > G03 nm, i = xX oo SB mo = Joo x ( Pi 2 Me iw x a Preis Casa Beene, T= B= sean xan PUY ee ONIONS fot = 446.20m) Seem NN ONE 16 KOT = 125 X70 7 os = mm |r dots din 7 = 15d? oY = Blo = fs mm ae Ek ail. poe ER Ar Re, a ho 103 ytoiit é Sh th _ ost ESS: Guu xl dy x Deo pei ——____—— Wo aes 3 exe f = 308 Gls X BGO x¥ § 3 XN0 : ae es Soc ss peo mm EE z f fe 20.5 XA = "D5 me Gp_ob Wp “0 = 2a > Toomm pe Ane = “Worn Pema ee oorm ae Veces “Ds =14p 2 10 mm __ FOR EDUCATIONAL USEean piace: it hers jn avduiciny, the sires ie ete! 0, Prryndirh the rife of the ‘Print oe D beter sok Abiiptan? Oni doe nen Ae Pring is Tocided , cm — | Ae (emves shore “the lon Goo sion Ten imerven ia ire pe gO ee eee | seis aeheoton Wndey wad peo oie eS eel “G2 20 MW Lins = Fig 0 Ane PE aivinian totionon chew Stress, “T= 2EGy Se ree 6.6 = kOe £2018 «= \.2626 a bo -v = J KOXE 9 \oms =e 14364 MP, MLS : ashing que, Ks GAN = gy 8 Ben SGA = Stun NimPRS FOR xo yy = Fx Keno —<- ee Sel => Woot. ad the sPiing_con anne, nes ab eS 5 Ae = a ees Feeeer XS K1.2525 = AG eet no= 45urnin, Merc, Ses = oo MPa Nae ok P =\2600w- Sh9= 6d MPG Kast No = PMU a Ke Myo fog ep bean fe = (a0 KA fmm | To =e Fe = 200% ymm> =the Sys bS fy sn) Y= -o16y - o4rfz noo, Num of pea, “on eur ese Tk 20 =. WH = 3x\6 = hg 4 Peewee in poa Ya = 0. 'sn ~ a9 [hx “= 0.135 A no byyoYa = @ xa4.196 = z Sie > = N06 xp a4 =10, 26 Shep 7 Sho Ip Yeur_t ~ al Gea taath, mM ym yO. /a FOR EDUCATIONAL USEnoo, tent Strentth of Paty dp = mp _= otro Qs 22 <--2NGR 1.5 ZqtZe Were R= Re ‘sind tosh | eel ~Ay) [ \.32 = fs | = 0.2" PG no 47 Ms Goat x Sie ovch sa | (0292) f CG -6.20)) |.2532. | ooo x10 loaxie LR = 1.2334 | — Dow wen “styentrth Fur = Oper) dp hOY = \fm atm “Ay. ae X15 + Fu = 30340 pnt __ FOR EDUCATIONAL USEeee eyuoee= NS WSN, {540.25 3%, Be 4 AR = fhe exe a 5130 es a j Ea SRS Re L u ay ee Z16 xe 4 ae “—_ 5 ro. 4 . Ni sroream) —— | | Bp 20.5 +0. 251m) x 94. crac ss h S19 é ; BP = (61 ey) 414% me IS) ie | ane: fl t — i ees aes z | 1 Ae i _ 2 Bm = 2 od 689. 6846 08) + mee _- » ‘ la. ” : = J 2. S64 Wf =-(y.6MC XO) + OSmuD ae 2 56.4 11? 4dr + (23939 1.8) 1 - Gy 6 160)=0 | 9 SaWinh Above, eduction, We es ‘i on FOR EDUCATIONAL USE : 7 7 IPee hive lidth, 4 = Ibm oth yr — de = 2p = BYE = 192 Mm dg = m7q = [2 M2 = SEC mM[Given dua: — Ze =30. On =26. ~ | Le =h0 My = 3mm ~ minimum il thins Che) F - Era Engi (o) = WG 2 yea: ie = Nai pa ns. th ak is 2 JQ = 33 x25 yong auto sa - roa) P= te rise _ol uid, aT = OND fe) oe : “Pace L&C Ho ee Pogglin Y9200%5 68 r © ¥ ROW X 6120.52 11.46 é. [ere 4amae |©). Given duo N= 420vPm, Lay = 2usod hrs W=ooaw,* , for PIX cunditions = a4, a matey 0.25 = _L,QY= o_22) (runes) = 1036 «8 —>_Conshaering _-adustment factors sopaxé — Anas) he 9 Laptaon rn ("fo.9) 2 : Teton = t009z x] an now, basic dynamic load turin, “ c= W ke toe ee ee c= daca xf loorg xl] : 7 of©)! Given datas P=1S,000w., Nw © Iooortin. No = tor? Dw = 0.0m, Pitch tine _vetacits of cian, Ctangenhat) Vay, = TD Nw = 1 .0.065 XaaGd = 3._ ea nis —& ES — nos, Teneindio, bicce Citein® Gator, t- feisty cas08 J 1.44 = ton! Cla) = tail (0. Load = 5 me t = noo, Bria 2 huns vase Pitch, L Sa =P > fly < yet . 6e.ace mm t Zw 3 t eid, Ls tw P. = 3 xi nee + = 201.204 mmtwa, leva date, fun = b= 200-20) et Nid NAGS. asus) thrust on cvsain,, eran am “jan tdya% tan (51.074) _ ee _—— > Yosion sx “sateratin’ Bre, on wan, — a rer [aang | aad * “tardy tan | Ain — wane pele ea Wo. Eo mie a 7. et. | otet! — Maen of forx; a a8 tanch, 40) _t.raaei