NAME: Jhunbie Claire Revelo DATE: 11-18-24
Julie Mae Lucagbo SUBJECT: BT 4
COMPUTATION:
LENGTH WIDTH DEPTH CONCRETE SET MATBAR
COVER
F1 800 mm 800 mm 30mm 750mm 12 sets 12mm
BOTHWAYS
CONCRETE VOLUME= L x W x D
= (0.80) (0.80) (0.30)
= 0.192 cu. m
= 0.192 cu. m (12 sets)
= 2.304 cu. m
CUT LENGTH= W/L – (Concrete cover) (2) + (hook) (2)
= 0.80 – (0.75) (2) + (0.125) (2)
= 0.9 m
No. of mat pcs = 12 sets (5) (2 both ways)
= 120 pcs of 0.90m
No. of cut length per DRB= 6.00 / 0.90
= 6.67 or 6 pcs
WASTAGE= (excess %) ( cut length )
= ( .67) (0.90 m)
= 0.603 or 2,60 per DRG
No. cut length pre DRB= 7.50/0/090
= 8.33 M
WASTAGE= (excess %) (cut length)
= (.33) (0.90)
= 0.297 or 0.30 per DRB
F1 CUT LENGTH (CL): 12 PCS @ 0.90M
LENGTH OF CUT LENGTH # OF PCS PRODUCE WASTAGE
REBAR (m) PCS PCS LENGTH
(16mm) (m)
6.00 0.90 6.67 6.00 0.60
7.50 8.33 8.00 0.30
NO. OF PCS @ 12mm DIAMETER x 7.50 DRB= 120 pcs / 8pcs
= 15 pcs of DRB
WEIGTH @ 12mm DIAMETER x 7.50 DRB= 15 pcs (7.50) (0.888 kg/m)
= 99.9 kgs
TIRE WIRES
= 5 (horizontal) x 5 (vertical)
= 25 intersections
= 12 sets x 25 intersections
= 300 intersections
= 300 tying points x 0.30m
= 90 / 53 m/kl
= 1.698 kg or 1.7 kg of tire wire
SUMMARY:
FOOTING 1 (F-1): @ 12 SETS
Quantity of bar @ 12mm x 7.50 DRB = 15 pcs or 99.9 kgs
Quantity of tire wires = 1.7 kg or 1 ¾ kg
C1 @ 7.27m
MAIN VERTICL BAR CUT LENGTH
VBCL= (7.27M) (-0.075) (concrete cover footing) – (0.012m) (DB) (2) – (0.40) (concrete
cover column) + (0.20) (hook)
VBCL= 7.195 – 0.024 – 0.40 + 0.20
= 6.971 OR 7M
@ 10 sets of C1 @ 7.27 heigth
No. of VBCL pcs= (10 sets) (4pcs)
= 40pcs of 7.27m
C1 VERTICAL BAR CUT LENGTH (CL)= 40PCS @7.27M
No. of CL per DRB= 7.50 / 7.27
= 1.03
WASTAGE= (excess %) (cut length)
= (0.03) (7.27)
= 0.2181 or 0.22m
No. of pcs @ 12mm diameter x 7.50 DRB= 40 pcs (CL) / 1pc
= 40 pcs of DRB
WEIGTH @ 12mm DIAMETER x 7.50 DRB= 40 (7.50) (0.888 KG/M)
= 239.75 kgs
C1 LATEREAL TIES CUT LENGTH (LTCL)
A (side) 200 – (2) (40) = 120mm or 0.120mm
B (side) 200 – (2) (40) = 120mm or 0.120mm
LTCL= 2 (A (side)) + 2 (B (side)) + 2 (hooks)
= 2(0.120m) + 2 (0.120m) + 2 (0.10m)
= 0.68m
C1 effective Heigth @ GF:
= (3.90M) – (0.075) – (0.012 (2)) – 0.25
= 3.825 – 0.024 – 0.25
= 3.551 M
C1 EFFECTIVE HEIGTH @ 2F= (3.17) – (0.04M) – (0.00M)
= 3.13M
C1 MID-HEIGTH @ DF:
= (3.551M) – (4 (0.05M)) (2) – 6 (0.10) (2)
= 3.551M – 0.4 -1.2
= 1.951 or 2.00m
C1 MID-HEIGTH @ GF LATERAL TIE QUANTITY = 2.00M / 0.20M
= 10PCS
C1 MID-HEIGTH @ 2F = (3.13M) – (4 (0.05)) (2)
= 2.73M
C1 MID-HEIGTH @ 2F LATERAL TIE QUANTITY = 3.17 / 0.15
= 21.13 OR 21 PCS
QUANTITY LATERAL TIES /COLUMN @ GF:
= 1+4+6+10+6+4+1+3
= 35 PCS
QUANTITY LATERAL TIES/ COLUMN @ 2F= 1+4+10+4+1
= 20PCS
10 SETS OF C1 @ 7.27 M HEIGTH
No. of lateral ties (pcs) = (35pcs) + (20pcs) (10 sets)
= 550 pcs of 0.68 m
C1 lateral tie CL: 550 pcs @ 0/68m
No. of CL per DRB = 6.00 / 0.68M
= 8.82 PCS OR 8 PCS
WASTAGE:
= (0.03) (0.68M)
= 0.02 M
C1 VERTICAL BAR CUT LENGTH (CL): 550 PCS @ 0.68M
LENGTH OF CUT LENGTH # OF PCS PRODUCE WASTAGE
REBAR (m) PCS PCS LENGTH
(12mm) (m)
6.00 0.68 8.82 8.00 0.56
7.50 11.03 11.00 0.02
NO. OF PCS @ 12MM DIAMETER x 7.50M PER DRB= 550PCS /11 PCS
= 50 PCS OF DRB
WEIGHT OF 12MM DIAMETER x 7.50M = (50PCS) (7.50) (0.888 KG/M)
= 333 KGS
TIE WIRES:
For every intersection
= 4 (vertical bar) x 55 (lateral ties)
= 220 (intersections)
Add: 3 tie points @ hook / vertical bar
= 4 (vertical bar) x 3 (ties points)
= 220 + 12
= 232 intersections
For column 1 (c1) sets:
= 10 sets (232 intersections)
= 2,320 intersections
TOTAL THE WIRES NEEDED:
= 2,320 (tying points) x 0.30 m
= 696 / 53 m/kl
= 13.13 kgs of tie wires
C1 SUMMARY: @ 10 SETS
Quantity of vertical bar @ 12mm diameter x 7.50 m DRB
= 40 PCS OR 239.75 KGS
Quantity of lateral ties @ 12 mm diameter 7.50m DRB
= 50 PCS OR 333 KGS
Quantity of tie wire
= 13.13 kgs or 13 kgs
