Department of Electrical Engineering
Internal Test- II Academic Years: 2024 - 25
Semester: 4TH Branch:EE
Subject Name:PE Subject Code:EEPC2005
Duration: 1Hr Max. Marks: 30
Q. No. Questions Marks CO BTL
PART-A (COMPULSORY)
1(a) Explain blanking time. 2 CO4 1
What is the rms value of fundamental component of single phase bridge inverter
1(b) 2 CO5 1
if the input voltage is V?
1(c) Why freewheeling diode is not required in a semi converter? 2 CO6 1
In a dc chopper, the average load current is 30 Amps, chopping frequency is 250
1(d) Hz. Supply voltage is 110 volts. Calculate the ON and OFF periods of the 2 CO4 1
chopper if the load resistance is 2ohms.
1(e) What is the purpose of over modulation? 2 CO5 2
1 (f) What is freewheeling diode and what is its purpose? 2 CO6 2
PART-B (COMPULSORY)
A single-phase full wave rectifier with R-L-E load has L = 6.5mH, R = 2,50, and 6 CO4 1
E = 10V.
2(a) The input voltage is Vs = 120Vat 60Hz. Determine (1) the steady state load
current at wt = 0, (II) the average diode current (III) the rms diode current (IV)
the rms output current.
-OR-
Describe the principle of step up chopper. Derive an expression for the average
2(b) 6 CO4 1
output voltage in terms of input voltage and duty cycle.
A single-phase Semi converter feed power to RLE load. For discontinuous load
current, draw the output voltage, loadcurrent, source current and freewheeling
3(a) diode current waveforms as a function of time when 6 CO5 2
(1) Extinction angle β > Π
(II) B < Π with Vm sin ẞ <E
-OR-
For a step-down chopper, input do voltage is 230V, load resistance=100. For the
3(b) duty cycle of 0.5, Calculate 1) the average and the rms values of output voltage 6 CO5 2
and (II) Chopper frequency.
A number of SCRs, each with rating of 2000V and 50A, are to be used in series-
parallel combination in a circuit to handle 11KV and 400A. For a derating factor
of 0.15, calculate the number of SCRs in series and parallel units. The maximum
4(a) 6 CO6 2
difference in their reverse recovery charge is 20 microcoulombs. Calculate (1)
the value of dynamic equalizing capacitance and (II) the voltage across each of
the slow thyristor in case one series connected SCR is fast.
-OR-
For a buck boost converter, the input dc voltage is 14V. The duty cycle is 0.6
with switching frequency of 25KHz. The inductance L = 180pH and filter
capacitance C = 220 µF. If the average load current is 1.5A, Compute
4(b) (i) The average output voltage 6 CO6 2
(ii) Peak to peak output voltage ripple
(iii) Peak to peak current in the inductor
(iv) The peak current of the device