Solution
Solution
1001CMD303056250001 MD
PHYSICS
(1)
(2)
(3)
(4)
(1)
(2)
(3)
(4)           if angle between    &    is 90°
(1)
(2)
(3)
4) If the resultant of vectors         and          is a unit vector along y-axis then the values of p &
q are respectively :–
(1) –3, 5
(2) 3, –5
(3) 3, –3
(4) 5, –5
(1)
(2) 0
(3) 1
(4) 2
(1)
(2)
(3)
(4)
7) Which of the following set of three vectors can't produce a zero resultant :-
(1)
            ,           ,
(2)
            ,           ,
(3)
                ,           ,
(4)
                ,           ,
8) =
(1) 0
(2)
(3)
(4) All
(1)
(2)
(3)
(4) All of the above
(1)
(2) A2 – B2
(3)
(4) zero
11) If vectors and are mutually perpendicular then what is the value of c ?
(1) 4
(2) 2
(3) 1
(4) – 4
12) A rocket of mass 5000 kg is set for vertical firing. If the exhaust speed be 1 km/sec, how much
gas must be ejected per sec to given the rocket an upward acceleration of 10 m/sec2 ? (g = 10m/s2)
(1) 20 kg/sec
(2) 1000 kg/sec
(3) 100 kg/sec
(4) 10 kg/sec
13) An object is in equilibrium under four concurrent forces in the direction shown in figure. The
magnitude of       and   are:-
(1) Zero,
(2)           , Zero
(3) ,
14) Three blocks of masses 2 kg, 3 kg and 5 kg are connected to each other with light string and are
then placed on a frictionless surface as shown in the figure. The system is pulled by a force F = 10
N, then tension T1 =
(1) 1 N
(2) 5 N
(3) 8 N
(4) 10 N
15) With what force must a man pull on the rope to hold the plank in position if the man weights
60kg? Neglect the weight of the plank, rope and pulley. (Take g = 10 m/s2)
(1) 100 N
(2) 150 N
(3) 125 N
(4) 130 N
16)
If acceleration of B is 2 ms2 find acceleration of A.
(1) 6 m/s2
(2) 3/2 m/s2
(3) 3 m/s2
(4) 2 m/s2
17) In Fig., the pulley P1 is fixed and pulley P2 is movable. If W1 = W2 = 100 N, what is the
angle AP2P1 ? The pulleys are frictionless :-
(1) 30°
(2) 60°
(3) 90°
(4) 120°
18) A monkey of mass 30 kg climbs a rope which can withstand a maximum tension of 360 N. The
maximum acceleration which this rope can tolerate for the climbing of monkey is :-
(g = 10 ms–2)
(1) 2 ms–2
(2) 3 ms–2
(3) 4 ms–2
(4) 5 ms–2
19) A piece of wire is bent in the shape of a parabola y=kx2 (y-axis vertical) with a bead of mass m on
it. The bead can slide on the wire without friction. It stays at the lowest point of the parabola when
the wire is at rest. The wire is now accelerated parallel to the x-axis with a constant acceleration a.
The distance of the new equilibrium position of the bead, where the bead can stay at rest with
respect to the wire, from the y-axis is :-
(1)
(2)
(3)
(4)
20) A block of mass 2 kg is suspended from a string, is released from a height of 5m as shown in
figure then what will be the impulse when string. Just becomes tight :-
(1) 2 N-s
(2) 0.2 N-s
(3) 20 N-s
(4) 200 N-s
21) The graph shows the force time plot for a particle of mass 0.5 kg. If the particle starts from rest
then its final velocity after 20 ms (milliseconds) is:-
22) Two blocks A (5 kg) and B(3 kg) are connected with a spring (force constant k) and the
combination is pulled by force F = 10 N, as shown, if at any instant acceleration of block A is 4 m/s2,
then acceleration of block B will be : –
(1) 5 m/s2
(2) 10 m/s2
(3) 4 m/s2
(4) 12 m/s2
23) When a beam of light is incident on plane mirror, it is found that a real image is formed. The
incident beam must be :-
(1) Converging
(2) Diverging
(3) Parallel
(4) Formation of real image by plane mirror is imposible
24) Figure shows a plane mirror onto which a light ray is incident. If the incident light ray is turned
by 10° and the mirror by 20°, as shown, then the angle turned by the reflected ray is :
(1) 60° clockwise
(2) 50° clockwise
(3) 30° clockwise
(4) 40° clockwise
25) An observer is moving along the line AB as shown. When image of object O is first visible to
observer, he starts from rest with the acceleration of 2cm/sec2, then the time for which image is
visible to observer is
(1) 3 sec
(2) 9 sec
(3) 12 sec
(4) None of the above
26) At what distance from a concave mirror of focal length 10 cm must an object be placed in order
that an image double its size may be obtained ?
(1) 5 cm only
(2) 15 cm only
(3) either 5 cm or 15 cm
(4) at 10 cm
27) A square card of side length 1 mm is being seen through a magnifying lens of focal length 10 cm.
The card is placed at a distance of 9 cm from the lens. The apparent area of the card through the
lens is :-
(1) 1 cm2
(2) 0.81 cm2
(3) 0.27 cm2
(4) 0.60 cm2
28) A convex mirror of focal length 10 cm is shown in fig. A linear object AB = 5 cm is placed along
the optical axis. Point B is at distance 20 cm from the pole of mirror. Then size of image of AB will be
:-
(1)
(2) 2.5 cm
(3)
(4)
29) A point object is moving towards a concave mirror of focal length 25cm. When it is at a distance
of 20cm from the mirror, its velocity is 5cm/sec. Find velocity of image at that instant :-
(1) 10 cm/sec
(2) 125 cm/sec
(3) 25 cm/sec
(4) 5 cm/sec
30)
A fish at a depth of 12 cm in water is viewed by an observer on the bank of a lake. To what height
the image of the fish is raised ?
(μ = 4/3) :-
 (1) 9 cm
(2) 12 cm
(3) 3.8 cm
(4) 3 cm
31) A ray of light passes through four transparent media with refractive indices µ1, µ2, µ3 and µ4 as
shown in the figure. The surfaces of all media are parallel. If the emergent ray CD is parallel to the
(1) µ1 = µ2
(2) µ2 = µ3
(3) µ3 = µ4
(4) µ4 = µ1
32) A microscope is focused on a mark, then a glass slab of refractive index 1.5 and thickness of 6
cm is placed on the mark to get the mark again in focus, the microscope should be moved
(1) 4 cm
(2) 2 cm
(3) 6 cm
(4) 8 cm
33) A ray of light enters a rectangular glass slab of refractive index   at angle of incidence 60°. It
travel a distance of 5 cm inside the slabe and emerges out of the slab. The perpendicular distance
between the incident and the emergent rays it.
(1)
(2)
(3)
(4) 5 cm
34) The image of point P when viewed from top of the slabs will be
35) A point source of light is placed 4m below the surface of water of refractive index 5/3. The
minimum diameter of a disc which should be placed over the source on the surface of water to cut-
off all light coming out of water is
(1) 2 m
(2) 6 m
(3) 4 m
(4) 3 m
36) A light ray falls on a square glass slab as shown in the diagram. The index of refraction of the
glass, if total internal reflection is to occur at the vertical face, is equal to :
(1)
(2)
(3)
(4)
(1) 4 m/s
(2) 0 m/s
(3) 16 m/s
(4) –8 m/s
38) A convergent beam of light is incident on a convex mirror of radius of curvature R as shown in
figure. A real image is formed at a distance 0.4 m from the mirror. The radius of curvature of the
mirror is :
(1) 0.4 m
(2) 1.4 m
(3) 0.8 m
(4) 1.8 m
39) A transparent solid cylinder rod has refractive index of     . It is surrounded by air. The incident
angle 'θ' for which the light ray grazes along the wall of the rod is -
(1)
(2)
(3)
(4)
40) The minimum deviation produced by a prism of prism angle 60° is 30°, When placed in air. Then
refractive index of the material of prism:
(1) 2
(2)
(3)
(4) 3
41) A prism of refractive index µ and angle A is placed in the minimum deviation position. If the
angle of minimum deviation is A, then the value of A in terms of µ is :-
(1) sin–1(µ/2)
(2)
(3) 2cos–1(µ/2)
(4) cos–1(µ/2)
42) A horizontal light ray passes through a prism (µ = 1.5) of angle 4°. Further, it is incident on a
plane mirror M, that has been placed vertically. By what angle the mirror is rotated so that the ray
(1) 1°
(2) 2°
(3) 4°
(4) 8°
43) STATEMENT-1 : The formula connecting u, v and f for a spherical mirror is valid only for
mirrors whose sizes are very small compared to their radii of curvature.
because
STATEMENT-2 : Laws of reflection are strictly valid for plane surfaces, but not for large spherical
surfaces.
(1) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
      Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for
(2)
      Statement-1
(3) Statement-1 is True, Statement-2 is False
(4) Statement-1 is False, Statement-2 is True
44) The image formed after two reflection (first at x then at y) will be :-
45) A light ray is incident perpendicularly to one face to a 90º prism and is totally internally
reflected at the glass-air interface. If the angle of reflection is 45º, we conclude that the refractive
index n is
(1)
(2)
(3)
(4)
                                            CHEMISTRY
1) Transition element from Z = 39 to Z = 48 belong to :-
(1) 3d series
(2) 4d series
(3) 5d series
(4) 6d series
2)
3)
Column-I Column-II
8)
Which of the following metal is expected to have the highest third ionization enthalpy
            +
(1) F(g) → F (g)
            +
(2) F(s) → F (g)
            2+
(3) F(s) → F (g)
            +
(4) N(g) → N (g)
10) The electronic configuration of an element is 1s2, 2s22p6, 3s23p4 .The atomic number of element
present just below the above element in periodic table is -
(1) 36
(2) 34
(3) 33
(4) 32
Column-I Column-II
13) S-1 :- The formation of     from      is Exothermic, whereas that       from O(g) is endothermic
S-2 :- The addition of second electron to a monovalent anion is difficult and experience more
repulsion
(1) S-1 and S-2 both are correct and S-2 is correct explanation for S-1
(2) S-1 and S-2 both are correct and S-2 is not correct explanation for S-1
(3) S-1 correct and S-2 is false
(4) S-1 false and S-2 is correct
Compound Shape
15)
16) From the following pairs of ions which one is not an iso-electronic pair ?
(1) O2–, F–
(2) Na+, Mg2+
(3) Mn2+, Fe3+
(4) Cu+, Zn+
17) Which of the following molecule has maximum number of lone pair -
(1) XeF2
(2) SO2
(3) SiF4
         –
(4) [BH4]
18)
List-I List-II
19) Statement-I : At Room temperature, nitrogen exist as N2 (N≡N) whereas phosphorous exist as
P4.
Statement-II : CO2 exist as discrete molecule whereas SiO2 is a network solid not exist as discrete
molecule.
(1) If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
(2) If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
(3) If Assertion is True but the Reason is False.
(4) If both Assertion & Reason are False.
Reason : Structure is not allowed because octet around 'O' can not be expanded.
(1) If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
(2) If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
(3) If Assertion is True but the Reason is False.
(4) If both Assertion & Reason are False.
(1) [Rn]6d27s2
(2) [Xe]4f75d16s2
(3) [Xe]5d16s2
(4) [Rn]5f76d17s2
Correct answer is :
(1) a-(i)    b-(iv)    c-(ii)    d-(iii)
(2) a-(ii)   b-(iii)    c-(iv)    d-(i)
(3) a-(i)    b-(iv)    c-(iii)   d-(ii)
(4) a-(iv)    b-(ii)   c-(iii)    d-(i)
(1) N2O3 > P2O3 > As2O3 > Sb2O3 > Bi2O3
(2) B2O3 < Al2O3 < Ga2O3 < In2O3 < Tl2O3
(3) HOCl < HOBr < HOI
(4) CrO < CrO3 < Cr2O3
(1) s-block metal oxides are basic in nature except BeO which is amphoteric.
(2) In general non metal oxides are acidic in nature
(3) In d-block all elements are metals
(4) d-block metal oxides are only basic in nature
29)
30)
(1) PCl5
(2) BrF5
(3) OF2
(4) OF6
(1) N2O
(2) Cl2O
(3) ClO2
(4) CO2
(1) C–C
(2) Si–Si
(3) Ge–Ge
(4) Sn–Sn
34)
(1) PCl5
(2) SF6
(3)
(4) Both (1) and (2)
(2)
(3)
(4)
36) The 'd' orbital involved in the hybridization in the PCl5 molecule is :-
(1) dx2
          –y2
(2)
(3) dxy
(4) dxz
37) Match Column-I with Column-II and Column-III and choose the correct option from the given
codes.
(1) K2O
(2) Al2O3
(3) BeO
(4) ZnO
39) Which of the following graphs shows correct trends in the size of +3 ions of lanthanides ?
(1)
(2)
(3)
(4)
41) For the elements B,C,N,F & Si, the correct order of their non-metallic character is :-
42) Radius of anion is always greater than its corresponding neutral atom-because of :-
43) The IUPAC name of the element which is placed after Db105 is the periodic table, will be :-
44)
BIOLOGY
2) Statement I : LH acts on the sertoli cells and stimulates secretion of some factors which helps in
the process of spermiogenesis.
Statement II : FSH acts at the leydig cells and stimulates synthesis and secretion of androgens.
Androgens, in turn, stimulate the process of spermatogenesis.
3) Statement-I : The mammary glands are one of the female secondary sexual organ.
Statement-II : After coitus, sperms are transported to the ampulla, where the sperm fertilised the
ovum leading to formation of a diploid zygote.
5) The ___A___ starts as the zygote move through the ___B___ of oviduct called cleavage toward
the ___C___.
(1) 2000
(2) 500
(3) 1000
(4) None of them
8) The blastomeres in the blastocyst are arranged into an outer layer called......A......and an inner
group of cells attached to......B.......called the........C...........
9) Ejaculation of human males contains about 200-300 million sperms, of which for normal fertility
___B___% sperms must have normal shape & size and at least ___A___% of them must show vigorous
motility.
Find A & B respectively.
(1) 60, 40
(2) 50, 50
(3) 40, 60
(4) 30, 70
10) The wall of the uterus has three layers of tissue. The .........A......membranous
perimetrium........B.........layer of smooth muscle, myometrium and.......C.......layer called
endometrium.
12) The Ovulatory phase is followed by the.........X........during which the remaining parts of the
.......Y.........transform as the...........Z.................
Identify 'X', 'Y', 'Z' choose the correct option :-
X Y Z
13) Read the following statements & choose the correct option.
Statement I : In the early phase of pregnancy relaxin is secreted by the ovary.
Statement II : hCG, hPL & relaxin are produced in women only after 6 month of pregnancy.
14) __"A"__ acts on the __"B"__ cells and stimulates secretion of some factors which help in the
process of spermatogenesis.
15) Statement I : Each testis has 250 compartment known as seminiferous tubule.
Statement II : Sperm are produced in seminiferous tubules.
17) The __"A"__ originates from the urinary bladder and extends through the penis to its external
opening called __"B"__.
(1) Perimetrium
(2) Myometrium
(3) Endometrium
(4) Germinal epithelium
21) Read the following statements carefully & select the incorrect one :-
(1) The sperm head contains an elongated & compact haploid nucleus.
(2) Movement of tail facilitates sperm motility essential for fertilisation.
(3) Middle piece provide energy for movement of tail.
(4) The middle piece is filled with enzymes that help fertilisation of the ovum.
23) Read the following statements and choose option having correct statements :-
(a) By the end of the second month of pregnancy, the foetus develops limbs and digits.
(b) By the end of 24th week the body is covered with fine hair.
(c) The first sign of growing foetus may be noticed by listening to the heart sound through the
stethoscope.
(1) a, b
(2) a, c
(3) b, c
(4) a, b, c
25) The corpus lutum secretes large amounts of......A.......which is essential for.....B......of
the.......C.......
26) If male is impotent and female is fertile then what possible assisted reproductive technology is
used for treating the infertility in particular couple?
(1) GIFT
(2) Intrauterine insemination
(3) ZIFT
(4) Embryo transfer
27)
How many of the contraceptive methods in the list given below are barrier method ?
Condoms, Diaphragm, Lactational amenorrhea, Cervical Cap, Pills, IUD, Periodic abstinence, Coitus
interruptus, Depoprovera, Norplant.
 (1) Six
(2) Three
(3) Four
(4) One
29) Which of the following contraceptive devices also protects against sexually transmitted diseases
?
(1) Condom
(2) Sponge
(3) IUDs
(4) LNG-20
31)
33) How many technologies in the list given below are showing invitro fertilisation :-
GIFT, ZIFT, IUT, AI, IUI
(1) Six
(2) Three
(3) Two
(4) One
34) The Test-tube Baby programme employs which one of the following techniques ?
35) Given below are four methods (A–D) and their modes of action (a–d) in achieving contraception.
Select their correct matching from the four options that follow
Matching :-
(1) A – (c), B – (d), C – (a), D – (b)
(2) A – (b), B – (c), C – (a), D – (d)
(3) A – (c), B – (a), C – (d), D – (b)
(4) A – (d), B – (a), C – (b), D – (c)
36)
Match the column-A with column-B, and choose the correct option :-
          Column-A                     Column-B
                                   Prevents
 (C)    IUD                  iii
                                   implantation
37) Given below are four statements (a-d) regarding assisted reproductive technologies:-
(a) ZIFT - The zygote or early embryo (with upto 8 blastomere) transferred into the fallopian tube
(b) ICSI - A sperm is directly injected into the fallopian tube to form an embryo in the laboratory
(c) IUI - The semen collected either from the husband or healthy donor is artificially introduced into
the uterus
(d) GIFT - Transfer of zygote collected from a donor into the fallopian tube of another female who
cannot produce one but can provide suitable environment for fertilisation and development
Which of the above statements are correct:
(1) a & d
(2) b & c
(3) a & c
(4) b & d
(1) 4
(2) 3
(3) 2
(4) 1
39) Identify the correct match from the columns I, II and III :-
                      Column-I
                                                          Column-II                  Column-III
                   (Contraceptive
                                                         (Mechanism)                 (Example)
                      method)
(1) Medical Termination of Pregnacy MTP during first trimester is generally safe
(2) Generally chances of conception are nil until mother breast-feeds the infant upto two years
(3) 'Saheli' is one of most widely accepted methods of contraception in India.
(4) Contraception pills may be taken upto one week after coitus to prevent conception
41) How many days, pregnancy last in dogs, elephants and cats ?
(1) c & e
(2) c & d
(3) b & e
(4) a & d
(1) by a
(2) by b
(3) by c
(4) by a and b mainly
47) Select the option which correctly identifies the structure marked as 'X' along with it's correct
function :-
49) Placenta act as endocrine tissue and produces several hormones like :-
50) Which of the following is not included in the female external gentilia ?
(1) Hymen
(2) Clitoris
(3) Infundibulum
(4) Labia majora
54) Given below are two statements : one is labelled as Assertion (A) and the other is labelled as
Reason (R).
Assertion (A) : Oxytocin is the main parturition hormone.
Reason (R) : Oxytocin acts on uterine myometrium and stimulates vigorous contractions in smooth
muscles leading to expulsion of foetus through the birth canal.
In the light of above statements, choose the most appropriate answer from the options given below
:
(1) Both (A) and (R) are correct but (R) is not the correct explanation of (A).
(2) (A) is correct but (R) is not correct.
(3) (A) is not correct but (R) is correct.
(4) Both (A) and (R) are correct and (R) is the correct explanation of (A).
56) The secondary spermatocytes undergo second meiotic division to produce four equal
(1) Spermatogonia
(2) Spermatids
(3) Primary spermatocytes
(4) Polar bodies
57) Which of the diploid cell produces first haploid cells during spermatogenesis.
(1) Spermatogonia
(2) Primary spermatocyte
(3) Secondary spermatocyte
(4) Spermatids
(1) Prophase-I
(2) Metaphase-I
(3) Anaphase-I
(4) Telophase-I
(1) Zygote
(2) Morula
(3) Blastocyst
(4) Trophoblast
62) A tiny finger like structure which lies at the upper junction of the two labia minora is -
(1) Clitoris
(2) Hymen
(3) Mons pubis
(4) Glans
63) The anterior structure of sperm head is covered by a cap like structure is called
(1) Acrosome
(2) Mitochondria
(3) Nucleus
(4) Both 2 and 3
(1) Oxygen
(2) Carbon dioxide
(3) Excretory material
(4) All of the above
65) In human beings, menstrual cycles ceases around _____A_____ of age; that is termed as
_____B_____.
66) The testes are situated outside the abdominal cavity within a pouch called :
(1) Coelom
(2) Scrotum
(3) Prostate
(4) Penis
(1) Epididymis
(2) Vas deferens
(3) Rete testis
(4) Ureter
68) In human being Ist sign of growing foetus noted in which month :-
(1) Menopause
(2) Menarche
(3) Spermiation
(4) Capacitation
71) The region outside the seminiferous tubule which contain small blood vessels, interstitial cells
and immunologically competent cells is present called:-
72) The seminal plasma along with the sperms constitute the
(1) Sebum
(2) Semen
(3) Serum
(4) Smegma
(1) Head
(2) Middle part
(3) Neck
(4) Tail
78) How many sperms and ova will be produced by 100 primary spermato cyte and 400 primary
oocytes ?
(1) Ovary
(2) Uterus
(3) Testes
(4) Epididymis
(1) Relaxin
(2) Oxytocin
(3) Progesterone
(4) Oestrogen
(1) Mala-D
(2) Mala-N
(3) Saheli
(4) Gossypol
(1) Z.I.F.T
(2) I.U.T.
(3) I.C.S.I
(4) G.I.F.T
87) Given below is a flow chart showing ovarian changes during menstrual cycle. Identify hormones
 (4)     FSH      LH          LH
(1) 1
(2) 2
(3) 3
(4) 4
88)
Identify the hormones A, B, C and D from the graph by observing their concentrations in blood
during the menstrual cycle of a female:
         A               B                C              D
89) Study the cycle shows below and select the option which gives correct words for all four blanks
A, B, C, D :-
A B C D
90) Following is diagrammatic sectional view of ovary with labelled parts A, B, C and D. Find out the
incorrect identification of the labelled part and its description.
                                       Mature
 (3) C             Graafian follicle
                                       follicle containing secondary oocyte
PHYSICS
 Q.         1          2         3        4     5     6     7        8          9     10        11     12     13     14     15    16   17    18    19    20
 A.         2          3         4        1     2     2     2        2          4     1         1      3      1      3      2     3    4     1     2     3
 Q.         21         22        23       24    25    26    27       28        29     30        31     32     33     34     35    36   37    38    39    40
 A.         2          2         1        3     2     3     1        4         2      4         4      2      2      4      2     1    2     3     4     3
 Q.         41         42        43       44    45
 A.         3          1         3        1     2
CHEMISTRY
 Q.         46         47        48       49    50    51    52        53        54        55     56     57     58     59    60    61    62    63   64    65
 A.         2          1         3        1     3     2     2         4         3         2      4      1      1      1     4     4     1     4    3     1
 Q.         66         67        68       69    70    71    72        73        74        75     76     77     78     79    80    81    82    83   84    85
 A.         2          3         3        2     1     1     4         3         1         3      4      3      1      3     3     2     2     1    2     3
 Q.         86         87        88       89    90
 A.         3          4         3        2     1
BIOLOGY
Q.    91         92         93       94    95   96    97        98        99        100        101    102    103    104    105   106   107   108   109   110
A.    3          4          3        1     1    2     1         3         3          3          1      2      4      4      4     4     4     1     3     3
Q.    111        112       113    114     115   116   117    118          119       120        121    122    123    124    125   126   127   128   129   130
A.     4          2         4      4       3     2     2      4            1         3          1      1      3      2      3     3     3     1     3     1
Q.    131        132       133    134     135   136   137    138          139       140        141    142    143    144    145   146   147   148   149   150
A.     3          4         1      1       4     3     4      4            1         3          4      2      4      4      2     2     2     1     2     3
Q.    151        152       153    154     155   156   157    158          159       160        161    162    163    164    165   166   167   168   169   170
A.     3          1         1      1       3     2     3      2            3         2          3      2      1      3      4     3     1     2     2     4
Q.    171        172       173    174     175   176   177    178          179       180
A.     3          3         4      4       3     2     4      2            2         2
                                          SOLUTIONS
PHYSICS
    1)              =
    =
    2)
    It is not necessary it always zero.
3)
4)
5)
    θ = 90°
= 2 × sin 45°
6)
                =
=
7)
|A – B | ≤ R ≤ |A + B|
8)
Polygon Law
9)
10)
=
11)
2+c–6=0
c–4=0
c=4
12)
=4+2
F1 = 0
14)
Fext = mT × a
10 = 10 × a
a = 1 m/s2
T1 = (3 + 5) × a
    = 8N
15)
N + T = 60 g ……(1)
                   → 37 = N ……(2)
From eq (1) and (2)
37 + 7 = 60g
47 = 60g
T = 15g
16)
2T × a – 3T × 2 = 0
2Ta = 6T
a = 3 m/s2
17)
W1 = W2           T = W1
System is in equilibrium
2T cos θ = W2
2W1 cos θ = W2
2 cos θ = 1
cos θ = ⇒ θ = 60°
2θ = 120°
18)
T – mg = ma
360 – 300 = 30 × a
60 = 30 × a
a = 2 m/s2
19)
tan θ =        ……(1)
y = kx2
2kx =
x=
20)
Just released vi = 0
vf =       =              = 10 m/s
= 2(10 – 0) = 20 N-S
21)
Area under F-t graph gives ΔP
ΔP = × 50 × 20 + 100 × 20
  = 500 + 2000 = 2500 gm/s
But time in milli second
∴ ΔP = 2500 × 10–3
  ΔP = 2.5 m/s
m × vf = 2.5
vf =
22)
fs = 5 × 4 = 20
23)
24) Due to 10° clockwise rotation of incident ray, reflected ray turns by 10° anti-clockwise,
Due to 20° clockwise rotation of the mirror, reflected ray turns by 40° clockwise. Hence, net
rotation is 30° clockwise.
25)
x = 27 × 3 = 81 cm
s = ut = at2
81 = 0 + × 2 × t2
t2 = 81 ⇒ t = 9 sec
26) m = +2 =
m = –2 =
28)
VB =
image of length =
29)
V1 = – m2 V0
=–
=–
= – 25 × 5 = – 125 cm/sec
30)
31)
μ 4 = μ1
(same medium)
32) Question explanation: When a glass slab is placed over an object, the apparent position
of the object shifts due to refraction.
Formula:
       Calculation:
       Concept: Snell's Law: n1sinθ1 = n2sinθ2, where n is the refractive index and θ is the angle.
       Subscript 1 refers to one medium and subscript 2 to the other.
        SOLUTION:
                      Calculation:
       1. Given:
= × sinθ2
sinθ2 =
2. θ2 = 30ο
Find the angle between the incident ray and the refracted ray inside the slab (let's call it α):
3. α = θ1 − θ2 = 60ο − 30ο = 30ο
4. Visualize a right triangle inside the slab:
  A. The hypotenuse of this triangle is the distance the light travels inside the slab (d = 5 cm).
  B. The angle between the hypotenuse and the longer side (parallel to the slab's surface) is α =
     30ο.
  C. Let 'x' be the perpendicular distance we are looking for. This is the side opposite to the angle
     α.
sin α =
sin 30∘ =
  =
5. x = = 2.5 cm
Answer:
Option (2) cm
35)
36)
Generated by Allie
     Problem Statement: The question asks us to find the minimum index of refraction of a
     square glass slab such that a light ray entering it at an angle of 45° from air will undergo
     total internal reflection when it hits the vertical face inside the glass.
     Underlying Concept: The problem involves the concept of refraction of light and total
     internal reflection. When light passes from one medium to another, it bends according to
     Snell's law. Total internal reflection happens when light tries to move from a denser medium
     to a rarer one at an angle greater than the critical angle, causing the light to reflect
     completely inside the denser medium.
     Critical angle relation:            when total internal reflection occurs from a medium of
     refractive index to .
     Step-by-Step Calculation: Step 1: The light ray enters the glass slab at          to the horizontal
     surface.
     Step 2: At the vertical face inside the glass, the ray's angle to the vertical must be at least the
     critical angle    to get total internal reflection. This means the incident angle inside the glass
     at the vertical face is          .
Common Mistakes: Confusing the angle of incidence and refraction inside the glass slab.
Forgetting to apply the critical angle condition correctly at the vertical face. Using sine
instead of cosine when applying the angle complementary identity.
Why Other Options Are Incorrect?: Options that do not match             fail to satisfy the
condition for total internal reflection at the vertical face. Some other choices might arise from
arithmetic errors or incorrect application of trigonometric identities.
37)
VI = 2 × 4 – 8 = 0
⇒
f = 0.4
∴ R = 0.4 × 2 = 0.8 m
39)
40)
41)
42)
δ = (μ – 1) A
  = (1.5 – 1) × 4
  = 2°
Mirror rotated by 1° would given a deflection of 2° by which the ray becomes horizontal.
43) Question Explanation: To find out correct statement as per given question.
Concept : validation of laws of reflection and mirror formula.
Formula :
Solution :
Statement-I mirror formula            , valid for small mirrors, because of paraxial rays do not
produce aberration, for large mirror this is not application.
Statement-I Correct
    Statement-II Laws of reflection and valid for all reflecting surface depends on position of
    normal incorrect.
    Final Answer : option (3)
44)
⇒ v1 = –40 cm
    ∴ m1 =
    also u2 = 40 – 15 = 25
⇒ v2 = –150 cm
m2 =
    Mnet = m1 × m2 =
    (Image is erect enlarged two times)
45)
    i > θc
    sin i > sin θc
μ>
CHEMISTRY
46)
47)
Lanthanoid Contraction
48)
50)
51)
52)
IP2
53)
54)
56)
C+ B+ N+ O+
IP B < C < O < N
EA B+ < C+ < O+ < N+
57)
58)
O– has more es– – es– repulsion.
60)
sp2, 1pπ – pπ
61)
62)
63)
64)
66)
67)
Generated by Allie
Problem Statement: The question asks which given electron configurations correspond to
transition elements. In simpler terms, it wants us to identify which atoms have electrons in
their d orbitals in such a way that they are considered transition metals, excluding inner-
transition elements like lanthanoids and actinoids.
Underlying Concept: Transition elements are defined as elements whose atoms or common
ions have an incomplete (n-1)d subshell. These elements generally fall in the d-block of the
periodic table. Inner-transition elements, which involve filling of f orbitals (lanthanoids and
actinoids), are not counted as traditional transition elements despite sometimes having d
electrons.
Tips and Tricks: Remember: Transition metals have partially filled d orbitals but are not
lanthanoids or actinoids (which fill f orbitals). Checking the noble gas core and counting d
electrons can quickly identify the element's block.
Why Other Options Are Incorrect?: Configurations with f-electrons ([Xe] 4fâ· and [Rn]
5fâ·) belong to lanthanoids and actinoids, which are inner-transition elements, so they are not
counted as d-block transition metals. Although they have d electrons, their primary electron
filling occurs in f orbitals.
68)
(i) Cl–      F–
EA Cl > F
IP Cl– > F–
(ii)
     Cr+     Mn+
     d5 > d 6
IP Cr+ > Mn+
69)
70)
71)
Acidic strength α EN
72)
73)
Eu > Gd
75)
76)
Explanation
       A. The central atom's ability to expand its octet depends on the availability of d-orbitals and
          the electronegativity of the surrounding atoms. Oxygen is highly electronegative and
          small, limiting its ability to be a central atom with a high coordination number.
Concept
       A. Oxygen has no d-orbitals in its valence shell. It can expand its octet only to a limited
          extent, primarily forming a maximum of two bonds in stable compounds with highly
          electronegative elements like fluorine. While OF₂ is a known stable compound, OF₆
          would require oxygen to have an oxidation state of +6 and form six bonds, which is not
          energetically feasible due to the lack of d-orbitals and steric hindrance.
77)
78)
79)
80)
81)
Solution/Explanation/Calculation :
NaOH (basic in nature) it can dissolve acidic/amphoteric oxide.
K2O (basic oxide) it is not dissolve in NaOH
Hence, the correct answer is option (1).
84) Asking for: Which of the following graphs shows correct trends in the size of +3 ions of
lanthanides
Concept: Lanthanide contraction, ionic radii, periodic trends.
Formula: N/A, but understanding the concept of lanthanide contraction.
Solution/Explanation:
1. Lanthanides: The lanthanide series consists of elements from lanthanum (La) to lutetium
(Lu).
2. Lanthanide Contraction: As we move across the lanthanide series, the effective nuclear
charge increases due to the poor shielding of 4f electrons. This leads to a gradual decrease in
the ionic radii of the L n^ 3- ions.
3. Trend: The size of L n3+ ions decreases from L a3+ Lu3+
4. Correct Graph: The graph that shows a gradual decrease in ionic size from La3+ to is the
correct representation. Ln3+
Analyzing the Options:
• Option 1: Shows an increase in ionic size, which is incorrect.
• Option 2: Shows a decrease in ionic size, which is correct.
• Option 3: Shows a linear increase in ionic size, which is incorrect,
• Option 4: Shows a V-shaped trend, which is incorrect.
Therefore, the correct graph is the one that shows a gradual decrease in ionic size from La to
Lu
Answer:
Option: 2
.
85) NCERT Pg # 88
86)
I.P = F > N > C > B > Si
Non- metallic = F > N > C > B > Si
character
    Concept : the knowledge of the iupac nomenclature periodic table in chemistry should be .
    Explanation :
    The element that comes after Dubnium (Db, atomic number 105) in the periodic table is
    Seaborgium (Sg, atomic number 106). The IUPAC systematic name for element 106 is
    Unnilhexium (Unh), which corresponds to the name 'Un nil hexium'.
    Determine the IUPAC name for Seaborgium, which is Unnilhexium (Unh).
    Final Answer :Unnilhexium
89)
90)
BIOLOGY
92)
105) NCERT Pg # 23
106)
113)
NCERT Pg. # 38
114)
Question Explanation :
What is the effect on sperm function or fertility if the epididymis is absent?
Concept :
     This question is based on Male reproductive system.
     Solution :
     The correct answer is option 4.
  A. The epididymis is crucial for functional maturation, storage, and transport of sperms.
  B. Without it, sperms do not mature properly and become incapable of fertilization, even though
     they may still be produced in the testes.
     Hence,
     Option (4) is correct : Sperms are incapable for fertilization.
     116) Intrauterine insemination (IUI) Correct. IUI is a procedure where sperm (obtained
     through a donor or sperm bank) is directly placed into the uterus, bypassing the male's
     impotence. Since the female partner is fertile, IUI is a viable option. Correct Answer:
  A. To identify and count the contraceptive methods that are characterized by minimal to no
     adverse side effects on the user's health.
Solution Explanation:
       A. Lactational amenorrhea: Natural method; generally few side effects, but dependent on
          consistent breastfeeding.
       B. Periodic abstinence: Natural method; no direct physical side effects.
       C. Coitus interruptus: Natural method; no direct physical side effects.
  B. Methods with "almost no side effects":
       A. Lactational amenorrhea
       B. Periodic abstinence
       C. Coitus interruptus
Answer:
The correct answer is option 2: THREE.
118)
Solution:
119)
Question Is Asking:
     ● Which contraceptive device offers protection against both pregnancy and sexually
     transmitted diseases (STDs).
Solution Explanation
     ● Condoms are barrier methods that physically prevent the exchange of bodily fluids, thus
     offering protection against STDs.
● Other methods like sponges offer some very limited protection, but not reliably.
● IUDs and hormonal methods like LNG-20 do not provide any protection against STDs.
     Answer:
     The correct answer is option 1: Condom.
120)
     The question presents four pairs matching contraceptive methods with their modes of action.
     You need to identify the pair that is incorrectly matched.
  A. (3) Lippes loop - Make cervix hostile to the sperm: This is an incorrect match. Lippes
     loop is a non-hormonal IUD that primarily works by causing a foreign body reaction in the
     uterus, which prevents sperm from reaching the fallopian tubes. It doesn't specifically make
     the cervix hostile to sperm.
     Correct Answer:
     Option 3 (Lippes loop - Make cervix hostile to the sperm) is the incorrect match.
121)
NCERT-XII Pg. # 44
123) Solution :
  A. ZIFT (Zygote Intra Fallopian Transfer) and IUT (Intra Uterine tranfer) involve in vitra
      fertilization, where fortilization occurs outside the body. GIFT, AI and IUI involve in vivo
      methods.
125)
   A. A. The pill: The pill contains hormones that primarily prevent ovulation (c).
   B. B. Condom: Condoms act as a barrier, preventing sperm from reaching the cervix (a).
   C. C. Vasectomy: Vasectomy involves cutting or blocking the vas deferens, so the semen
      contains no sperm (d).
   D. D. Copper T: Copper T (IUD) decreases sperm motility and viability (b).
Final Answers:
A – (c), B – (a), C – (d), D – (b)
127)
NCERT-XII Pg. # 48
128) NCERT - Pg # 60
130)
132)
135)
152)
NCERT-XII Pg. # 30
158)
NCERT-XII Pg. # 38
160)
NCERT-XII Pg. # 33
161)
NCERT Pg. # 27
162)
NCERT-XII Pg#32
164)
NCERT Pg. # 33
165)
NCERT Pg. # 32
Module-7, Pg. No. 17
167)
168)
170)
NCERT Pg. # 34
173)
Solution/Explanation:
  A. GIFT is the only option where the gametes (sperm and ovum) are placed into the
     fallopian tubes, allowing fertilization to occur naturally within the female's reproductive
     tract
        B. Correct Answer is option (4)
174)
NCERT XIIth Pg # 60
175)
176)
NCERT-XIIth Pg. 33
177)
NCERT-XII Pg#34
179)
180)