Integration Exercise 3
Integration Exercise 3
IE(III)
                                     KCITE CLASSROOM
                                 INTEGRATION EXERCISES 2025
INSTRUCTIONS
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          (2) Attempt ALL questions in this paper. Write your answers in the spaces
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          (6) No extra time will be given to candidates for writing their information or filling
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          © Kcite Classroom
          No Rights Reserved 2025
                                                                            1
             2025-KC-M2 1–1
                                                     1.   Evaluate the following integrals.
                                                                              1
                                                          (a)
                                                                  x+x        1000000
                                                                                        dx
                                                                       
                                                                   e2      cos ( ln x ) − sin ( ln x )
                                                          (b)
                                                                 1            x        2
                                                                                                         dx
                                                                  ln ( x + 1) dx
                                                                   1
                                                                              2
                                                          (c)
                                                                   0
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                                                                                                              2
                                                     2025-KC-M2 1–2
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                                                                                                          3
                                                     2025-KC-M2 1–3
                                                     2.   Given that a is a real constant and f :                      →       .
                                                          (a) Show that
                                                                                                                  2a                        a
                                                                 (i)         If f ( x ) = f ( 2a − x ) ,
                                                                                                              0
                                                                                                                       f ( x ) dx = 2
                                                                                                                                        
                                                                                                                                        0
                                                                                                                                                f ( x ) dx
                                                                                                                      2a
                                                                 (ii)        If f ( x ) = − f ( 2a − x ) ,
                                                                                                                  0
                                                                                                                           f ( x ) dx = 0
                                                                                                                   x
                                                                                                           4
                                                                                                               sin     ( x − 2)
                                                                                                                    2 
                                                          (b) Hence or otherwise, evaluate
                                                                                                         0                4x − x2
                                                                                                                                  dx
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                                                                                                                                                   4
                                                     2025-KC-M2 1–4
                                                     3.   (a) Show that
                                                                                                            
                                                                 (i)
                                                                              0
                                                                                  2 ln
                                                                                         (sin x ) dx =     0
                                                                                                             2 ln
                                                                                                                    ( cos x ) dx
                                                                                                                
                                                                                  
                                                                 (ii)
                                                                              0
                                                                                      ln ( sin x ) dx = 2
                                                                                                            0
                                                                                                                 2 ln
                                                                                                                        (sin x ) dx
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                                                                                                                                      5
                                                     2025-KC-M2 1–5
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                                                                                                          6
                                                     2025-KC-M2 1–6
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                                                                                                          7
                                                     2025-KC-M2 1–7
                                                     4.   Given that g and h are real functions defined on the interval − a, a  , where a is some real constant.
                                                          (a) Given that g ( x ) is an even function and h ( x ) is an odd function.
                                                                                                a    g ( x)                      a
                                                                 (i)         Show that
                                                                                             − a e h( x )      +1
                                                                                                                     dx =
                                                                                                                               0
                                                                                                                                     g ( x ) dx
                                                                                                                                                                     g ( x)e ( )
                                                                                                                                                                 a          k x                     a
                                                                 (ii)        Let k ( x ) be an odd function also defined on − a, a  , show that
                                                                                                                                                             
                                                                                                                                                             − a eh( x )   +e
                                                                                                                                                                                k ( x)
                                                                                                                                                                                         dx =
                                                                                                                                                                                                
                                                                                                                                                                                                0
                                                                                                                                                                                                        g ( x ) dx .
                                                          (b) Let f ( x ) = x3 − 9 x 2 + 29 x − 33 .
                                                                 (i)         Show that x − 3 is a factor of f ( x ) .
                                                                 (ii)        If f ( x ) = ( x − 3) Q ( x ) , find the x-coordinate of Q ( x ) .
                                                                 (iii)       Hence, express f ( u + 3) in terms of u .
                                                                                                         3
                                                                                                             −9 x 2 + 29 x −33
                                                                               6                    ex
                                                          (c) Evaluate
                                                                              (x
                                                                              0     2
                                                                                                    )(
                                                                                        − 6 x + 18 esin  x + e x
                                                                                                                            3
                                                                                                                                −9 x 2 + 29 x −33
                                                                                                                                                    )
                                                                                                                                                        dx
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                                                                                                                                                         8
                                                     2025-KC-M2 1–8
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                                                                                                          9
                                                     2025-KC-M2 1–9
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                                                                                                          10
                                                     2025-KC-M2 1–10
                                                                             
                                                     5.   Let I n =
                                                                         
                                                                         0
                                                                             2 sin n   x dx , where n           +
                                                                                                                     .
                                                                                                              ( 2 m!)
                                                                                                                             2
                                                                                                                m
                                                                 (ii)
                                                                                  0
                                                                                       2 sin 2 m +1   x dx =
                                                                                                            ( 2m + 1)!
                                                                                                                                 n +1
                                                                                                                                         1
                                                          (c) (i)                Show that I 0 I1I 2          I 2 n +1 =                            for all n        , where for all positive integers m ,
                                                                                                                         2            ( 2n + 1)!!                 0
                                                                                                                    ( 2m )!! = 2  4  6  8           ( 2m − 2 )  ( 2m )
                                                                                                                 ( 2m + 1)!! = 1 3  5  7            ( 2m − 1)  ( 2m + 1)
                                                                                                                                                                              
                                                                                                                                      
                                                                                            2 sin 7 x dx  2 sin8 x dx  2 sin 9 x dx 
                                                                                                                                                                                
                                                                                                                                                             2 sin19 x dx  2 sin 20 x dx 
                                                                                                           0            0                                               0
                                                                                                                                                                                    
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                                                                                                                                                 11
                                                     2025-KC-M2 1–11
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                                                                                                          12
                                                     2025-KC-M2 1–12
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                                                                                                          13
                                                     2025-KC-M2 1–13
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                                                                                                          END OF PAPER
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                                                                                                               14
                                                     2025-KC-M2 1–14