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Field Density Test: C D (Sand)

The sand cone test is used to determine the density of compacted soil in the field. The test involves excavating a hole in the compacted soil and measuring the weight of soil removed. The hole is then filled with calibrated sand using a cone-shaped container. The weight of sand required to fill the hole is measured and used to calculate the volume. The dry unit weight of the compacted soil can then be determined based on the dry weight and volume measurements.

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Dwight Mendoza Sr.
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44 views1 page

Field Density Test: C D (Sand)

The sand cone test is used to determine the density of compacted soil in the field. The test involves excavating a hole in the compacted soil and measuring the weight of soil removed. The hole is then filled with calibrated sand using a cone-shaped container. The weight of sand required to fill the hole is measured and used to calculate the volume. The dry unit weight of the compacted soil can then be determined based on the dry weight and volume measurements.

Uploaded by

Dwight Mendoza Sr.
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as DOCX, PDF, TXT or read online on Scribd
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Field Density Test

Procedures:
The sand cone device consists of a glass or plastic jar with a metal
cone attached at its top was filled with a uniform dry Ottawa sand. The
weight of the jar, cone and sand filling the jar was recorded as W 1. In the
field, a small hole on a compacted soil area was compacted. The moist soil
excavated from the hole was set aside and weighed as W2. Consequently, the
moisture content of the excavated soil was known and the dry unit weight of
the soil W3 was solved.
W 3=

W2
w( )
1+
100

where w=moisture content.

After the hole was excavated, it was filled with sand by inverting the
cone with the sand-filled jar. Sand was allowed to flow out of the jar into the
hole and the cone. Once the cone and hole were filled, the weight of the jar,
the cone, and the remaining Ottawa sand in the jar was determined, W4 .

So,

W 5=W 1W 4

where W5 is the weight of the sand to fill the cone and


hole.

The volume of the excavated hole was determined using:

W 5W C
d (sand)

Where,
Wc= weight of sand to fill the cone only
d (sand)

= dry unit weight of Ottawa sand used.

The dry unit weight of compaction made in the field is determined using;
dry weight of soil excavated
W

d = hole
= 3
volume of hole V

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