SSC Mock Test - Solution - 170 97
SSC Mock Test - Solution - 170 97
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                                                                       Required distance = AE = AB + BE
6. (A)                                                                  (Here, CD = BE = 5M) = 10 M + 5 M
                                                                                             = 15 M
                                                                18. (D) T R A I N S
                                                                19. (A)
7. (B)
Similarly,
                                                                20. (C)
8. (A)
                                                                21. (B)
                                                                22. (A)
9. (A)
                                                                23. (B)
10. (B)                                                         24. (B)
                                                                25. (D) According to dice I and III
11. (D) Except option (D), all are related to
        Indian Air Force.
12. (D) Except option (D), all are related to
        publication.
13. (B) Except option (B), all are the name of
        countries.                                              26. (D)
                                                                27. (A)
14. (C) (A)                      (B)
                                                                28. (B)
          (C)                    (D)
                                                                29. (D)
15. (B) (A)                      (B)
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        laboratory ladder landscape lavender     46. (D) 6 + 1 = 7
31. (B)                                                  3+x=6
             3        1          4          5
                                                         x=63
        lazarus
                                                            =3
           2
                                                 47. (A) (17 + 8)  5 = 5
32. (B)
                                                         (13 + 7)  5 = 4
33. (D)                                                  (6 + 12)  6 = 3
                                                         Similarly,
                                                            (10 + 6)  4 = 4
                                                 48. (C) 4 + 52 = 41
                                                           2
39. (C)
                                                                                    80 100 800
                                                                           C.P. =          
                                                                                       90    9
                                                                                             800
                                                                           Profit = 95 
                                                                                              9
                                                                                      855  800
                                                                                          9
                                                                                           800
                                                                                      95 
        Let AP1 and BP2 be two poles.                                                       9 100%
                                                                           % Profit      800
        Then, if BP2 = h meter (say)
                   AP1 = 2h meter (say)                                                   9
        The distance between the two poles,
                   P1 P2 = 40 m                                              55
        Let O be the middle point of P1P2, so,                                        55
                                                                           = 9 100     % = 6.9%
                   OP1 = OP2 = 20 m                                         800        8
        and     1OA =  ,  P2OB = 90   ,
                 P                                                            9
               because angular elevations are
                                                                59. (A) Let the side of longer square = a unit
               complementary (given)
                                                                                    Side of smaller square = m unit
        In right  AP1O
                                                                       ATQ,
                         2h
              tan  =        2h = 20 tan  ... (i)                         4a  4m = 100
                         20
        In right  BP2O,                                                      a  m = 25                       .... (i)
                                h                                      Again from question:-
              tan  (90   ) =                                             a2  3m2 = 325                    .... (ii)
                                20
         h = 20 tan (90   )          ... (ii)                      From (i) and (ii):-
        Multiplying (i) and (ii),                                           m = 30, 5
          2h2 = 202      [Since tan  .cot  = 1]                           (side cannot be negative)
            h = 10 2 metre/                                               m = 30
        Therefore, the height of the poles are 14.14 m          60. (B) Let OABCD be the right pyramid on a rect-
        and 28.28 m respectively.                                     angular base ABCD
55. (A)
56. (B) Let the Cost Price of of each cycle = ` x
        84% of 725 = 105 % of x
        (84/100)  725 = 105x/100
              84  725
         x=            = ` 580
                105
57. (D) Suppose the dealer weights x gm less for
        a kg
        then on (1000  x) gm he earns x gm.
                                  x
       on 1 gm he earns
                               1000  x                                AB = CD = 32 cm
                                                                       BC = AD = 10cm
                                 x             100
       on 100 he earns                  100 =                         Since it is a right pyramid,
                              1000  x          9
                            9x = 1000  x                               OXZ = 90 and
                            x = 100 gm                                 OX = h = 12cm
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       X is the midpoint of the base.                              62. (D)
       Now, in  OXZ ,  OXZ = 90
       OZ =     OX2  XZ 2
            = 122  162
                                                                                                  9
                                        1                                       A's share =         370 = ` 90
                             (since XZ = DC = 16)                                                37
                                        2
            = 20cm                                                                                             100 100
                                                                   63.(C) Required profit = (100 + 65)                100
                                                                                                               120 125
       In  OXY ,  OXY = 90                                              = 110  100 = 10%
            OY =         2
                      OX  XY   2
                                                                   64.(B)        Let total number of men = x
                                                1                          and total number of women = y
                = 122  52              (XY =     BC = 4)
                                                2
                                                                                                             45 x
                = 13 cm                                                   Number of married men =
                                                                                                             100
       Now , since the base is a rectangle ,
                                                                                                                     25y
        OBC =  OAD and  OAB =  ODC                                   and number of married women =
                                                                                                                     100
                  1                    1                                 A.T.Q,
        OBC =  BC  OZ =                10 20 = 100cm2
                  2                    2
                                                                            45 x 25y     9x
                                                                                    y=                             (i)
              1         1                                                   100 100      5
        OAB = AB  OY =  32 13 = 208cm2
              2         2
                                                                         also,
       Slant surface of pyramid
                                                                                                                     45x 25y
            = 2 (  OBC+  OAB)                                          Total number of married adults =               
                                                                                                                     100 100
            = 2 (100 + 208) = 616 cm2
     whole surface of pyramid                                                  9x 9 x
                                                                           =                    [from eq.           (i)]
                                                                               20 20
            = Slant surface + Base area
            = 616 + (32  10) = 936 cm2                                        9x
                                                                           =
61. (C) Let     A     = (x1, y1) = (t, t  2)                                  10
                B     = (x2, y2) = (t + 2, t + 2)                   and total population in city = x + y
               C = (x3, y3) = (t + 3, t)
                                                                                     9x
        The vertices of the vertices of the given                          =x+                   [from eq.           (ii)]
                                                                                      5
        triangle.
                                                                               14x
                                    1                                      =
         Area of  ABC =             |x (y  y3) + x2(y3  y1)                 5
                                    2 1 2
                                    + x3(y1  y2)|                                                9x
                                                                                                 100
                                                                          Required percentage = 14x 100 = 32.14%
                                    1
          Area of  ABC =            |{t(t + 2  t) + (t + 2)                                     5
                                    2
                                    (t  t + 2) + (t + 3)          65.(A) Let the individual ration be x
                                    (t  2  t  2)}|                      According to the question,
                                    1                                                                                90
          Area of  ABC =            [{2t + 2t + 4  4t  12)}]                 72  54  x = 90  D2  x 
                                                                                                                    100
                                    2
                               = |4| = 4 sq. units                                 72  54  100
                                                                      D2 =                       = 48
                                                                                      90  90
        Clearly, area of  ABC is independent of t.                        Hence the required number of days = 48
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66.(A) Let the total number of candidates = x                   70.(D)
      Number of candidates who answered all the
                           5x
        5 questions =
                          100
        Also, Number of candidates who answered                        Work done by A in 4 days = 3  4 = 12
                                                                       Work done by B in 8 days = 2  18 = 36
                                            5x
        not a single question =                                        Remaining work = 60  (12 + 36) = 12
                                           100
                                                                       Work done by C in 18 days = 12
                                             5x   5x    9x           Time required by C to complete work
     Remaining students = x -          =
                                1 00 100  10
                                                                                       18
    Number of candidates who answered only one                                    =       60 = 90 days
                                                                                       12
                        9x 25    9x
        question =            =
                        10 100   40                             71.(D)
       Number of candidates who answered four
        questions
                        9x 20    9x
                    =         =
                        10 100   50
                                    7                                                                   xd                                              xd
        Length of AB = 44                                                86.(D)       d        d  b a                d c a   +        d       d a b
                                    11                                              x x                        x                     x x                      xa c b
                           = 16 cm                                                                                                                 xd
                                                                                                                         +    d            d  a c
                                28  16                                                                                       x x                       x d b c
                      ED = 16 +
                                   2                                                                1                             1                             1
                                                                                   =                                +                              +            a
                           = 22 cm                                                              x   b
                                                                                                            x   c
                                                                                                                              x   a
                                                                                                                                           x   c
                                                                                                                                                            x           xb
                                                                                       1                               1                           1           
                      BE = 8cm                                                                  xa          xa                xb           xb               xc          xc
                                                                                                xa                                xb                            xc
        Length of diagonal (BD)                  =    (22)2  (8)2             =                                    +                              +
                                                                                    xa  x b  x c                      xa  x b  x c                 xa  x b  x c
                                                 = 2 137 cm                            xa  x b  x c
                                                                               =                                    =1
83. (C)                                                                                xa  x b  x c
84. (D)                                                                              x    y    z
                                                                          87. (D)      =    =     =a
                                                                                    y     z    w
                                                                                    x = a3w, y = a2w and z = aw
                                                                                           x m  ym  z m  wm
                                                                                           m
                                                                                       x         y m  z m  w m
                                                                                                a 3m wm  a 2m wm  a m wm  wm
                                                                                   =
                                                                                        a 3m w m  a 2m w m  a m w m  w m
                                                                                         wm (a 3m  a 2m  a m  1)
                                                                                   =
                                                                                               1     1      1      
                               1            1                                           w  w  3m  2m  m  1
        Area of  ABC =           AB  AC =  BC  AD                                        a    a       a       
                               2            2
        AB  AC = BC  AD                                                              w 2m (a 3m  a 2m  a m  1)
                                                                               =
                                                                                           1  a m  a 2m  a 3m
                        AB   AC
        cot B + cot C =    +                                                                                a 3m
                        AC   AB
                                                                                       a 3m  w2m (1  a m  a 2m  a 3m )
                             AB 2  AC 2    BC 2                               =
                           =             =                                                       1  am  a 2m  a 3m
                              AB  AC      BC  AD
                                                                                   = (a6 . w4 )m/2 = (a3.w. a2.w. a. w. w)m/2
                                12                                                 = (x. y. z .w)m/2
                           =       = 3 cm
                                 4
                                                                                          1     1    2        1 
85.(C) a + b + c = 0                                                      88. (D)  x  1    x   1  x  1  2 
                                                                                          x     x            x 
        Squaring both side
        a2 + b2 + c2 + 2ab + 2bc + 2ca = 0                                          4     1 
                                                                                   x 1  4 
        a + b + c =  (2ab + 2bc + 2ca)
          2     2    2
                                                                ... (i)                  x 
        (a  b) + (b  c) + (c  a)
                2           2            2
                                                                                  1       1  2 1         4 1      
                    = 2(a2 + b2 + c2) (2ab + 2bc + 2ca)                    =  x  1  x   1 x  2 1  x  4  1
                                                                                  x       x       x         x     
                    = 3(a2 + b2 + c2)
                                                                                        2    
                                                                                      1                  1                1
                a2  b2  c 2                        a2  b2  c 2          =   x        1  x 2                      
                                                                                                               1  x 4  4  1
                                             =                                        x                     2
                                                                                                   x             x     
        (a  b )2  (b  c )2  (c  a )2        3(a 2  b 2  c 2 )
                                                 1                             2   1      2   1     4    1    
                                             =                              =  x  2  1  x  2  1  x  4  1
                                                 3                                x          x          x     
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                  2                        92. (C)
      2    1           
                         2  4     1     
   =   x         (1)    x      1
          x2                x4    
                                                     2
       4   1     4    1      2     1 
    =  x  4  1  x  4  1 =  x  4   (1)2
          x          x            x 
             1
    = x8 +     +1                                                         Let DL  BC,
          x8
89. (C) Let the Ist part be ` x.                                                                  1
        Then, 2nd part = ` (4350  x)                                  So, Area of ABE =            AB  DF
                                                                                                  2
          SI 1    =   SI2
         x  9 1   (4350  x )  10  2                                                          1   1     
                  =                                                                           =        AC   DE
           100             100                                                                    2   2     
        9x + 20x = 4350  20
                                                                          Area of      BCDE= BC  DF
                     4350  20
                x=                                                                        1      
                        29                                                              =   AC   DF
                  = ` 3000                                                                2      
        Ist part = ` 3000                                                               = 2  Area of ABE
        2nd part = ` 1350
                                                                       ATQ, Area of ACDE
90. (A) Let the sum be = ` x
        ATQ,                                                                       = Area of ABE + Area of           BCDE
                                  n                                          3  Area of ABE = 36 cm2
                            r 
              A    = P 1                                                      Area of ABE= 12 cm2
                           100                                93. (C)
                           r 
                                  15                            94. (C) ABC        = 180  (65 + 75)= 40
                     
              2x = x 1                                               ORB        = OQB = 90
                         100                                       ROQ          = 360  (90 + 90  40)
                                15                                   ROQ          = 140
                      r 
             2 = 1      
                     100                                      95. (C)
         Again A = 8x
                                  n
                          r 
              8x = x 1      
                         100 
                   15     3
                                 n
               r            r 
        1        = 1      
           100       100                                       Let               AB = a units
               n = 15  3                                                                         3
                                                                                         BE =        a units
                    = 45 years                                                                     2
                          16                                                                                 3 2
91. (B) R = 16% p.a. =       % quarterly.                                 AB2 + BC2 + CA2 = 3a2 = 4           a
                           4                                                                                 4
         The amount of ` 17576, paid at the end
         of first quarter has its principal equal to                                                             2
                                                                                                  3 
                               25 
                                         1                                                = 4     a
                                                                                                       
                  = 17576         = ` 16900                                                    2 
                               26 
                                                                                          = 4BE2
         Similarly, the principle at the end of 2nd
                                                                96. (C) Required number of persons
                                         2
                               25                                       = 450 + 250 + 150 + 75 + 50 + 25 = 1000
         quarter = 17576          = `16250
                                                                97. (B) Required number of persons
                               26 
         and at the end of 3rd quarter                                    = 250 + 150 = 400
                                         3                      98. (C) Required Ratio = 250 : 75 = 10 : 3
                              25                              99. (C) Required Ratio = 450 : 1000 = 9 : 20
                  = 17576        = ` 15625
                              26 
                                                                                                          25
         Net principal = `(16900 + 16250 +15625)                100. (D) Required percentage =                100
                       = ` 48775                                                                         500
                                                                                                       = 5%
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101. (A) The Tebhaga movement was a militant             There can be no surplus or deficit in
         campaign initiated in Bengal by Kisan           a countrys balance of payments as a
         Sabha (peasants from Communist                  whole (as distinguished from its
         Party of India) in 1946. At that time,          balance of trade) because every payment
         share-cropping peasants (essentially            will have an offsetting receipt.
         tenants) had to give half of their 108. (A) Heavy wateris used in certain types
         harvest to the owner of the land. The           ofnuclear reactors, where it acts as
         demand of the Tebhaga movement                  a neutron moderator to slow down
         was to reduce the share given to                neutrons so that they are more likely
         landlords to one-third.                         to react with the fissile uranium-235
102. (B) In Preamble three justice: social,              than with uranium-238, which captures
         economic and political are given.               neutrons without fissioning.
         According to Section 38(1), the state 109. (D) Darwins struggle for existence in
         shall strive to promote the welfare of          natural history is analogous to the
         people by securing and protecting as            class struggle in human History. So
         effectively as it may a social order in         option C stands incorrect. The sketch
         which justice social, economic and              of dialectical materialism given by
         political, shall inform all the institutions    Karl Marx explains that Dialectical
         of national life.                               principle is of universal application
103. (C) The Genetic Engineering Appraisal               and all the development is struggle
         Committee (GEAC) is the apex body               of opposites or conflict of opposites.
         consti tut ed in t he Minist ry o f             Thus option D stands correct in this
         Environment and Forests under                   question.
         'Rules for Manufacture, Use, Import, 110. (A) A Money Bill can be introduced only
         Export and Storage of Hazardous                 in the Lok sabha on the recommen
         Microorganisms/Genetically Engineered           dations of the President. The Rajya
         Organisms or Cells 1989, under the              sabha cannot initiate a Money Bill nor
         Environment Protection Act, 1986.               can it reject or amend it after passage
         (Source: websit e o f M inistry o f             by the Lok sabha. The Rajya sabha
         Environment, Forest and Climate                 must return a Money Bill within 14
         Change)                                         days of receipt, after which the Lok
104. (A) The Extremists wanted to extend the             s abha may accept a ny of its
         Boycott and Swadeshi Movement to                recommendations.
         regions outside Bengal and also to 111. (C) Disguised unemployment indicates
         include all forms of associations (such         the marginal productivity of labor is
         as government service, law courts,              zero.
         legislative councils, etc.) within the          Disguised unemployment is a kind of
         boycott programme and thus start a              unemployment in which some people
         nationwide mass movement.                       look like being employed but are
         The Extremists wanted a strong                  actually not employed fully. This
         resolution supporting their programme           situation is also known as Hidden
         at the Benaras session. The Moderates,          Unemployment. In such a situation
         on the other hand were not in favour            more people are engaged in a work
         of extending the movement beyond                than required. For example in rural
         Bengal and were totally opposed to              areas, this type of unemployment is
         boycott of councils and similar associations.   generally found in agricultural sector,
105. (B) Jordan has Israel on its West and               e.g., in a family of nine people who are
         Syria on its North. Henceforth out of           all working in the same agricultural
         all these countries Jordan does not             plot, even if four of them are withdrawn,
         open out to the Mediterranean Sea.              there is no reduction in the output
106. (D) It is due to the revolution of the earth        from the plot. So, these four people are
         on a tilted axis that the length of the         actually disguisedly employed. In
         day and night from season to season             urban areas, this type of unemployment
         differs due to the Aphelion and                 can be seen mostly in service sector.
         Perihelion stages of the earth.                 An example is of a family, whose all
107. (C) Balance of paymentsis a systematic             members are working in one shop or
         record of all economic transactions             a small business, but which can
         between residents of one country and            actually be manag ed by a fewer
         residents of other countries (including         number of members of the family.
         the governments). The transactions are 112. (A)
         presented in the form ofdouble- 113. (D) The Office of the Advocate General is
         entrybookkeeping.                              a constitutional office created under
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         Article 165 of the Constitution of 127. (B) White clothes are cooler than black
         India. The Governor of the State                   ones because they reflect all the
         appoints a person who is qualified to              light that reaches them.
         be appointed as a judge of the High 128. (B) When detergent is added to water, the
         Court as Advocate General of the                   detergent molecules break down the
         State. A person shall not be qualified             cohesive attractive forces of the water
         for appointment as a judge of a High               molecules at the surface. Thus, the
         Court unless he is a citizen of India-             surface tension is broken.
         and has for at least 10 years held a 129. (D) The rarest member of the bear family,
         judicial office in the territory of India          pandas live mainly in bamboo forests
         or has for at least ten years been                 high in the mountains of western
         advocate of a High Court or of two or              China, where they subsist almost
         more such Courts in succession.                    entirely on bamboo.
         The post of Advocate General is a 130. (C) The Nagara, the Dravida and the
         public office and he is the foremost               Vesara are the three main styles of
         Law Officer of the State.                          Indian temple architecture.
114. (A) River Narmada occupies the linear rift    131. (A) As  an export item of India, Pepper
         valleys and flows towards the West.                occupies  the top position in value.
                                                   132. (A) Banihal PassAt 2,832m (9,291ft)
115. (D)                                                    elevation,thePir Panjalmountains
116. (B)                                                    connect Banihal with Qazigund on the
117. (B) My Lifeis a 2004 autobiography                    other side of the mountains. The Pir
         written by formerPresident of the                 Panjal mountain range separates the
         United StatesBill Clinton, who left               Kashmir valley in the Indian state
         office on January 20, 2001. It was                 Jammu and Kashmir from the outer
         released on June 22, 2004. The book                Himalaya and plains to the south.
         was published by theKnopf Publishing              Banihal pass was the only passage
         Group.                                             fro m Jammu t o Srinagar af ter
118. (A) Himadri Stationis Indias first Arctic            i ndepen dence unt il 1956 w hen
         research station located at Spitsbergen,           Jawahar Tunnelwas bored through
         Svalbard, Norway. It is located at the             thePir Panjal range. The pass is
         Int ernational Arctic Re search                    a ccessibl e only in summ er and
         base,Ny-Alesund. It was inaugurated               remains closed for the rest of the year
         on the 1st of July, 2008 by the Minister           due to heavy snow.
         of Earth Sciences.It was set up during 133. (A) It is generally said that India can reap
         Indias second Arctic expedition in                the advantages of "Demographic
         June 2008.It is located at a distance             Dividend because more than 55 per
         of 1,200 kilometres from theNorth Pole.           cent of India's population is in the age
119. (C)                                                    group 15-16 years.
                                                   134. (D) With the nationalisation of banks in
120. (A)                                                    India, certain sectors of the economy
121. (C) Open market operations(OMO) refer                 h ave been ident ified as prio rity
         to the buying and selling of government            sectors for the purpose of lending by
         securities in theopen marketin                   commercial banks.
         order to expand or contract the amount             These areas are
         of money in the banking system,                    1. Direct and indirect advances to
         facilitated by the Federal Reserve (Fed).              agriculture and allied activities.
122. (A) Right to vote is a Legal Right.                    2. Direct and indirect finance to
123. (D) These Words of preamble of Indian                      micro and small enterprises.
         Constitution - WE, THE PEOPLE OF                   3. Advances to weaker sections of the
         INDIA. emphasize that the ultimate                     society.
         power lies in the hands of the people 135. (D) Creating new money to finance a
         of India.                                          budget deficit, means the printing of
124. (A) The adjournment mo tio n is an                     additional currency and releasing the
         extraordinary procedure, which, if                 same in the market. It results in an
         admitted, leads to setting aside the               increase in money supply without any
         normal business of the House for                   increase in the supply of goods in the
         discussing a definite matter of                    real economy. The result is price rise.
         urgent public importance                  136. (B) Nitrogen is a naturally occurring
125. (B)                                                    element that is essential for growth
126. (A) The head mirror used by ENT doctors                and reproduction in both plants and
         is Concave.                                        animals. It is found in amino acids
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         that make up proteins, in nucleic           clover (Trifo lium) species. Clo ver
         acids, that comprise the hereditary         dodder is native to Europe, but occurs
         material and lifes blueprint for all       almost worldwide. It is a member of
         cells, and in many other organic and        the Convolvulaceae family, which
         inorganic compounds. In addition,           includes Ipomoea and Convolvulus
         nitrogen comprises about 80% of the         species, many of which are commonly
         Earths atmosphere.                         known as bindweed and morning
                                                     glory.
137. (A) National income of a country is defined
         as the sum of total factor incomes 144. (B) Step. 1 : write the formula = (NH4)2SO4.
         accruing to the residents of that           Step. 2 : Calculate the formula mass
         country from the production activity
                                                     = (2  14) + (1  32 ) + (4  16) = 132.
         performed by them both within and
         outside the economic territory in a         Step. 3 : Work out the mass of the
         year.                                       required element (nitrogen) = 28.
138. (A)      Remote sensingis the acquisition of                            Step. 4 : Calculate the percentage of
              informat ion about an o bject or                                                    28
              phenomenon without making physical                              the element =           100 = 21.2%.
              contact with the object and thus in                                                132
              co nt rast to on sit e obse rv at io n.           145. (B)      Titanium can be alloyed with iron,
              Remote sensing is used in numerous                              aluminium, vanadium, and molybdenum,
              fields, includinggeographyand most                            among other elements, to produce
              Earth Science disciplines (for example,                         strong, lightweight alloys for aerospace
              hydrology, ecology, oceanography,                               (jet engines,missiles, andspacecraft),
              gla ciolog y, g eolog y); it al so has                          military, industrial process (chemicals
              military, intelligence, commercial,                             and petro-chemicals, desalination
              economic, planning, and humanitarian                            plants, pulp, and paper), automotive,
              applications.                                                   agri-f o o d , m e d i c al p r o s t h e s e s ,
139. (B)                                                                      o rt ho pe dic implants, dental and
                                                                              endodontic instruments and files,
140. (B)      Parliament gives statutory authority                            dental implants, sporting goods,
              for the Government to draw funds from                           jewellery, mobile phones, and other
              the Consolidated Fund by Acts of                                applications.
              Parliament known asAppropriation
              ActsandConsolidated Fund Acts.                  146. (D)      Ohm s Law i s the mathema ti cal
              Funds are made available under the                              relationship among electric current,
              Acts only for a specifiedfinancial year,                       resistance, andvoltage. The principle
              a concept known asannuality,                                   is named after the German scientist
              although an individual Act can cover                            George Simon Ohm.
              more than one financial year, listing             147. (C)
              separate amounts for each. Often a
              tw o-ye ar period is cov ered by a                148. (A)      Benito Mussoliniconsolidated control
              Consolidated Fund Act, and roughly                              over the Fascist movement in 1919
              two or three are passed in each                                 with the founding of the Fasci italiani
              parliamentary year.                                             di combattimento, whose opposition to
                                                                              socialism he declared: We declare war
141. (B)      Eachkidneyis made up of about a                               against socialism, not because it is
              million filtering units called nephrons.                        socialism, but because it has opposed
              Each nephron filters a small amount                             nationalism.
              of blood. The nephron includes a filter,          149. (B)      Pakhui Tiger Reserve, also known as
              called the glomerulus, and a tubule. The                        'Pakke Tiger Reserve', is a Project
              nephrons work through a two-step                                tiger reserve in the East Kameng
              process.                                                        district of Arunachal Pradesh in
142. (A)      It is an excellent source of protein and                        northeastern India. The 862 square
              vitamins, especially theB-complex                              kilometres reserve is protected by the
              vitamins,as well as other minerals                             Department of Environment and
              andcofactorsrequired for growth. It is                        Forest of Arunachal Pradesh.
              also naturally low in fat andsodium.             150. (D)      TheNational League for Democracy
143. (C)      Cuscuta epithymumis a rootless,                                is ademocratic socialist and liberal
              wholly parasitic plant that occurs                              democratic political party in Myanmar
              most commonly on heather (Calluna                               (Burma), currently serving as the co-
              vulgaris), gorse (Ulex europaeus) and                           ruling party in Parliament alongside the
                                                                              military.
                                                                                                                           11
 Centres at: MUKHERJEE NAGAR  MUNIRKA  UTTAM NAGAR  DILSHAD GARDEN  ROHINI        BADARPUR  JAIPUR  GURGAON  NOIDA
  LAXMI NAGAR  GHAZIABAD  MEERUT  VARANASI  ROHTAK  PANIPAT  SONEPAT  PATNA  AGRA  CHANDIGARH  LUCKNOW  ALLAHABAD
                                                                                                                          12
 Centres at: MUKHERJEE NAGAR  MUNIRKA  UTTAM NAGAR  DILSHAD GARDEN  ROHINI        BADARPUR  JAIPUR  GURGAON  NOIDA
  LAXMI NAGAR  GHAZIABAD  MEERUT  VARANASI  ROHTAK  PANIPAT  SONEPAT  PATNA  AGRA  CHANDIGARH  LUCKNOW  ALLAHABAD
                                                                                                                          13
 Centres at: MUKHERJEE NAGAR  MUNIRKA  UTTAM NAGAR  DILSHAD GARDEN  ROHINI        BADARPUR  JAIPUR  GURGAON  NOIDA
  LAXMI NAGAR  GHAZIABAD  MEERUT  VARANASI  ROHTAK  PANIPAT  SONEPAT  PATNA  AGRA  CHANDIGARH  LUCKNOW  ALLAHABAD
==================================================================================
  1.     (A)      26.    (D)       51.   (B)        76.    (A)     101.   (A)       126.   (A)    151.   (B)     176.   (C)
  2.     (B)      27.    (A)       52.   (A)        77.    (A)     102.   (B)       127.   (B)    152.   (B)     177.   (B)
  3.     (A)      28.    (B)       53.   (C)        78.    (B)     103.   (C)       128.   (B)    153.   (B)     178.   (C)
  4.     (B)      29.    (D)       54.   (C)        79.    (D)     104.   (A)       129.   (D)    154.   (B)     179.   (B)
  5.     (A)      30.    (D)       55.   (A)        80.    (D)     105.   (B)       130.   (C)    155.   (C)     180.   (B)
  6.     (A)      31.    (B)       56.   (B)        81.    (C)     106.   (D)       131.   (A)    156.   (C)     181.   (B)
  7.     (B)      32.    (B)       57.   (D)        82.    (D)     107.   (C)       132.   (A)    157.   (D)     182.   (B)
  8.     (A)      33.    (D)       58.   (A)        83.    (C)     108.   (A)       133.   (A)    158.   (A)     183.   (A)
  9.     (A)      34.    (C)       59.   (A)        84.    (D)     109.   (D)       134.   (D)    159.   (B)     184.   (B)
  10.    (B)      35.    (*)       60.   (B)        85.    (C)     110.   (A)       135.   (D)    160.   (D)     185.   (B)
  11.    (D)      36.    (D)       61.   (C)        86.    (D)     111.   (C)       136.   (B)    161.   (B)     186.   (B)
  12.    (D)      37.    (C)       62.   (D)        87.    (D)     112.   (A)       137.   (A)    162.   (A)     187.   (A)
  13.    (B)      38.    (D)       63.   (C)        88.    (D)     113.   (D)       138.   (A)    163.   (B)     188.   (B)
  14.    (C)      39.    (C)       64.   (B)        89.    (C)     114.   (A)       139.   (B)    164.   (D)     189.   (B)
  15.    (B)      40.    (B)       65.   (A)        90.    (A)     115.   (D)       140.   (B)    165.   (A)     190.   (C)
  16.    (A)      41.    (C)       66.   (A)        91.    (B)     116.   (B)       141.   (B)    166.   (C)     191.   (A)
  17.    (A)      42.    (B)       67.   (D)        92.    (C)     117.   (B)       142.   (A)    167.   (B)     192.   (C)
  18.    (D)      43.    (B)       68.   (A)        93.    (C)     118.   (A)       143.   (C)    168.   (C)     193.   (B)
  19.    (A)      44.    (D)       69.   (A)        94.    (C)     119.   (C)       144.   (B)    169.   (B)     194.   (B)
  20.    (C)      45.    (B)       70.   (D)        95.    (C)     120.   (A)       145.   (B)    170.   (D)     195.   (C)
  21.    (B)      46.    (D)       71.   (D)        96.    (C)     121.   (C)       146.   (D)    171.   (A)     196.   (B)
  22.    (A)      47.    (A)       72.   (C)        97.    (B)     122.   (A)       147.   (C)    172.   (A)     197.   (C)
  23.    (B)      48.    (C)       73.   (B)        98.    (C)     123.   (D)       148.   (A)    173.   (C)     198.   (D)
  24.    (B)      49.    (B)       74.   (C)        99.    (C)     124.   (A)       149.   (B)    174.   (A)     199.   (A)
  25.    (D)      50.    (B)       75.   (B)        100.   (D)     125.   (B)       150.   (D)    175.   (D)     200.   (C)
                    Explanation                                                   CORRECTION-170
151. (B) Replace 'is ' with 'ar e'. Th e wo rd                    161. Newspapers are a dynamic product where
         'spectacles' is treated as plural in number,                  constant change in approach seeming to
         so 'are' should be used.
                                                                       be the rule rather than the exception.
152. (B) Replace 'have' with 'has'. When two
         subject nouns are connected using 'as                         (A) in approach seemed to be
         well as' then the singularity or plurality                    (B) in approach seems to be
         of the verb depends on the first subject                      (C) in approach seem be
         noun.                                                         (D) No Improvement
         Since 'teacher' is singular, so singular
                                                                  Ans (B).
         verb-'has' should be used.
153. (B) Add 'as' after 'good'.
154. (B) Replace 'or' with 'nor'.
155. (C) Replace 'among' with 'between'.
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