0% found this document useful (0 votes)
109 views9 pages

Answer Key & Explanations - IIFT 2016 (All Sets)

The document provides the answer key and explanations for a test called IIFT 2016. It lists the correct answer choices for 10 multiple choice questions from the test across 4 sets (Sets A, B, C, and D) and provides brief explanations for each answer. The explanations reference concepts like solving inequalities, infinite geometric progressions, logarithms, combinations, ratios, and geometry of shapes.

Uploaded by

ST
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
0% found this document useful (0 votes)
109 views9 pages

Answer Key & Explanations - IIFT 2016 (All Sets)

The document provides the answer key and explanations for a test called IIFT 2016. It lists the correct answer choices for 10 multiple choice questions from the test across 4 sets (Sets A, B, C, and D) and provides brief explanations for each answer. The explanations reference concepts like solving inequalities, infinite geometric progressions, logarithms, combinations, ratios, and geometry of shapes.

Uploaded by

ST
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
You are on page 1/ 9

IIFT - 2016

Answer key &


Explanations

Answer key & Explanations - IIFT 2016 (All Sets)

Question No’s key


Set Set Set Set Explanations
A B C D
x−7
We have >0
x 2 + 5x − 36
x−7 +
>0 +
1. 104. 62. 26. D ( x + 9)( x − 4)
9 7
4
The solution set is x ε (-9,4) ∪ (7, ∞)
The least integral value of x is -8.
 4
Taking the first term (a) to be 280  350 ×  and applying the formula for infinite G.P.
 5
a 280
⇒ = = 1400.
1− r 4
2. 105. 63. 27. C 1−
5
Now since the ball travels any distance twice, once up and next down, we take 2(1400) =
2800.
Hence, total distance will be 2800 + 350 (as the ball was thrown from a height of 350 mtr.
Initially and only this distance is covered once) = 3150.
We have 4 log 7 (x – 8) = log 3 81 ⇒ 4 log 7 (x – 8) = log 3 3 ⇒ 4 log 7 (x – 8) = 4
4
3. 106. 64. 28. D
⇒ log 7 (x – 8) = 1 ⇒ x – 8 = 7 ⇒ x = 15
5 students out of 4 boys and y girls can be chosen in 2 ways:
4 y
(i) 3 Boys & 2 Girls = C 3 × C 2
4 y
(ii) 4 Boys & 1 Girl = C 4 × C 1
Since only boys are given a ball, thus
4. 107. 65. 29. D st nd
Total balls given to 3 boys each in 1 case + Total balls given to 4 boys each in 2 case =
y( y − 1)
368 ⇒ 3 × C 3 × C 2 + 4 × C 4 × C 1 = 368 ⇒ 3 × 4 ×
4 y 4 y
+ 4 × 1 × y = 368
2
⇒ 6y (y -1) + 4y = 368 ⇒ 6y – 6y + 4y = 368 ⇒ 3y – y = 184 ⇒ y(3y – 1) = 184
2 2

Using options, we can check that only option (D) satisfies the above equation.
There are two vowels I and A in RIYADH
(i) Let these two vowels IA as one unit.
∴ No. of ways in which 2 vowels can be arranged together = 5! × 2! = 240
5. 108. 66. 30. D Hence statement (i) is false
(ii) Total no. of arrangements = 6! = 720.
No. of ways in which vowels do not occur together = 720 – 240 = 480
Hence statement (ii) is false.
Let farmer A has ‘x’ hectare land. ∴ Total production of A = 20x
Farmer B has x + 7 hectare land ∴ Total production of B = (x + 15) × 30
6. 109. 67. 31. C
Given that (x + 15) × 30 – 20x = 530 ⇒ 30x + 450 – 20x = 530 ⇒ 10x = 80 ⇒ x = 8.
∴ Production of farmer A = 20x = 20 × 8 = 160 bushels.
A B
d d
Delhi Noida
2
Let the distance between Delhi and Noida is x km.
Let they first meet at point A after one hour.
Distance covered by Shruti = 2x – d
7. 110. 68. 32. A Distance covered by Krishna = d
∴ Ratio of speeds of Shruti and Krishna is 2x- d : d …………. (i)
Let next they meet at B after half an hour. As Krishna covered distance ‘d’ in one hour, so
' d' d
he will cover distance in half an hour.∴ AB =
2 2
 3d  5d
Distance covered by Shruti in second meeting =x – d +  x −  =2x-
 2 2
IIFT - 2016
Answer key &
Explanations
5d d
∴ratio of speeds of Shruti and Krishna is 2x - : ……………… (ii)
2 2
5d
2x −
2x − d 2 ⇒ 2x –d = 4x – 5d ⇒ 2x = 4d ⇒ x = 2d.
=
d d
2
Now Krishna covered distance‘d’ in one hour, so he will cover distance x in 2 hours.
Let SP of each article be Rs. 100
100 100
Thus, CP 1 will be × 100 = 115, CP 2 = × 100 = 81.3
87 123
100
8. 111. 69. 33. A CP 3 = × 100 = 135.1
74
Hence, total CP = 331.4.
331.4 − 300
% by which CP is lower/higher than SP = × 100 = 10.5% higher.
300
If I do 2 units per day, my roommate will do 1 unit per day.
Together we do 3 units per day.
9. 112. 70. 34. A Since, we take 30 days to finish the complete work, so total work must be 30 × 3 = 90
units. Now working @ 2 units/day, I will take 45 days for 90 units and my roommate will
take 90 days.
Let the side of hexagon PQRSTU is ‘a’ Q
3
∴ Area of hexagon = 6× ×a2
4 a
a 60° 60°

30°
P R
3a 3a
2 2
10. 113. 71. 35. B

The side of triangle PRT = 3a

∴ Area of ∆PRT =
4
3
( )
× 3a =
2 3 3 2
4
a .
S
U
3 3 2 4 3 1
∴ Reqd. ratio is a × = = = 0.5 T
4 6 3a 2 6 2
Total students = 290. Let 80 students do not study either Spanish or Mandarin.
∴ No. of students who study Spanish or Mandarin or both = 290 – 80 = 210.
11. 114. 72. 36. D ∴ n(S∪M) = n(S) + n (M) – n(S∩M) ⇒ 210 = 120 +100 – n(S∩M) ⇒ n(S∩M) = 10
∴ Number of students who study Spanish but not Mandarin = 120 -10 = 110.
As 110 is given in option D, hence it is the answer.
The Volume of Cylinder = 15 × 49π
The rectangle solid is placed in cylinder such that each of the corners of solid is
tangent to walls of cylinder. Hence the diameter of cylinder will be diagonal to the
square base.
As the diameter of cylinder is 14, so diagonal of square is 14 and hence side of
square is 7√2.
12. 115. 73. 37. A
14 7√2

The volume of solid = 7√2 × 7√2 × 12 = 98 × 12


∴ The volume of the liquid = 15 × 49π - 98 × 12 = 147 (5π - 8) 7√2
15!
15
13. 116. 74. 38. B The total no. of arrangement = P 3 = = 15 × 14× 13 = 2730
12!
143
14. 117. 75. 39. D We have 54 + 55 + 56 + ………. + 196 = [54 + 196] = 17875
2
IIFT - 2016
Answer key &
Explanations

1 1
P(P) = 1 − n
( when all males) − n ( when all females)
2 2
1 n ×1 1
P(Q) = n ( when all males) + × n −1 ( when one female and rest males)
2 2 2
P(P ∩ Q) = exactly one female
1 1
15. 118. 76. 40. B =n× ×
2 2 n −1
For independent events
P(P ∩ Q) = P (P) × P (Q)
n  1 1  1 n 
= 1 − n − n  n + n 
 2  2 2 
n
2 2
Solving we get n = 3
The number of parking spaces
16 
16. 119. 77. 41. C = 20 +21 + 23 + ……… = 20 +  2 [2 × 21 + 15 × 2]
= 20 + [8[72]] = 20 + 576 = 596
We have
1 1 1
,
2 3 4
2 3 ,4
1 1 1
17. 120. 78. 42. B ×12 ×12 ×12
=2 2
,3 3
,4 4
6 4 3
= 2 , 3 , 4 = 64, 81, 64. As 81 is the largest number among the above numbers
1
so 3 3 is the highest number.
Number of ways in which a candidate can fail to secure cut offs.
18. 121. 79. 43. D 6 6 6 6 6
= C 0 + C 1 + C 2 + ........ C 5 = 2 – 1 = 63.
4 + 44 + 444 + -------------- n terms
= 4 (1 + 11 + 111 + -------------- n terms)
4
= (9 + 99 + 999 + -------------- n terms)
9
4
= [(10-1) + (100-1) + (1000-1) +-------------- + n terms]
19. 122. 80. 44. C 9

=
4 4 10 10 n − 1
[10 + 100 + 1000 + -------------- - n]= 

− n
( )
9 9 9 
=
40 n
81
(
10 − 1 −
4n
9
)
The two sides of the square are
6x – 8y = 15 and 4y – 3x = 2
or 6x – 8y = 15 (1)
and 6x – 8y = - 4 (2)
These two lines are parallel. So the distance between these lines is the side of
20. 123. 81. 45. B 15 − (− 4 ) 19
the square. ∴ side of square = =
62 + 82 10
2
 19  361
∴ Area of square =   = = 3.61 sq.units
 10  100
CDB is 2 triangles ahead of GHF in clockwise order and both GHF, CDB have alphabets in
21. 1. 82. 46. A clockwise order in their respective triangles. So following this, we get the answer as A
option.
By observation, HNP & DLP are vertices of 2 different triangles. We are moving ACW from
HNP to DLP. This means we have to move ACW from PDA. While in option PHE we are
22. 2. 83. 47. B
moving clockwise from PDA. So PHE is not possible. Also answer has to start from P.
Answer can’t be PME because it’s a straight line. Hence answer is PJG.
23. 3. 84. 48. C By observation, line IO comes after AK in ACW direction. Thus CL must be after EM in
IIFT - 2016
Answer key &
Explanations
ACW direction. By observing closely the 2 options starting with EM, we get the answer as
EMDL.
By observation, BPM is not a triangle. Thus correct answer will not form a triangle. Thus
24. 4. 85. 49. A option D is eliminated. Further BPM is almost opposite to GN. So FP is almost opposite to
AK. Hence answer is FPO.
a) If the Maternal grandmother is from tribe A, then mother will be from tribe A and the
female in question is from tribe A. As given that the female is from tribe B, so
statement a is false.
25. 5. 86. 50. B
b) If paternal grandmother is from A, then father is from tribe A and after marriage, he will
become member of tribe B. His daughter, the female in question will be of tribe B.
Hence statement b is true.
We will check the options one by one.
a) If the boy is born in tribe B then he will marry in tribe A and his daughter will be in tribe
A. Hence option (a) is incorrect.
b) If the boy is born in tribe B, then he will marry in tribe A. His son will be in tribe A. So
26. 6. 87. 51. C his daughter in law will be from tribe B. Hence option (b) is incorrect.
c) If the boy is born in tribe B, then his mother’s brother can be from tribe B and his
father’s brother can be from tribe A. Hence option (c) is correct.
d) If the boy is born in tribe B, then he will marry in tribe A and his divorced son will be in
tribe A. Hence option (d) is incorrect.
a) Any widower will return to his tribe. So he can marry his wife’s sister which is from
other tribe. Hence this marriage is permissible.
b) This marriage is also permissible as the divorced husband will return to his tribe.
Hence the mother can marry the divorced husband of her daughter.
27. 7. 88. 52. C
c) The mother’s brother will be of same tribe as that of girl. Hence the girl cannot marry
him. Hence this marriage cannot take place.
d) Any widower will return to his own tribe A. His brother’s widow will be of tribe B. So he
can marry his brother’s widow.
This is debatable set and there are two interpretations possible for statement 5. A number
of students wasted quite a lot of time on this set in the exam because of this ambiguity.
Some institutes have given a key without considering this possibility. We have highlighted
both scenarios in our solution and we sincerely hope this clarifies the given problem set.

Figure (i)
Carpenter/ Tailor /
Ana Belle

Plumber/
Cook/ Diana Ferida

Hairdresser/ Washerwoman/
28- 8- 89- 53- Elsa Cinderella
31. 11. 92. 56.
The correct seating arrangement is given above : (One should be careful in the
th
interpretation of 5 condition according to which the correct arrangement is Cook-
Carpenter-Belle)
Tailor /
Figure (ii) Cook/ Ana Diana

Plumber/
Carpenter/ Ferida
Elsa

Hairdresser/ Washerwoman/
Belle Cinderella
IIFT - 2016
Answer key &
Explanations
28. 8. 89. 53. * None of option*
29. 9. 90. 54. * None of option*
30. 10. 91. 55. * None of option*
31. 11. 92. 56. C
From the given information
We can infer that
32- 12- 93- 57- Admin → E & G (female)
34. 14. 95. 59. Finance → C, A and one of B & E
Logistics → H and one of B & E.
Order of income → G > H > A > F, B, E > C
32. 12. 93. 57. * Finance department will have 3 people.
33. 13. 94. 58. A B earns less than A and H.
nd
34. 14. 95. 59. A H is at 2 position in descending order of income.
All fathers are males and some doctors are males as well as fathers. Also some doctors
35. 15. 96. 60. C rd
are females. Hence 3 option.
(2 + 6) × (15 – 5) = 80
36. 16. 97. 61. B (7 + 6) × (9 - 4) = 65
So answer will be (16 + 8) × (13 - 11) = 24 × 2 = 48.
10, 26, 74, 218, 654
10 × 3 – 4 = 26
26 × 3 – 4 = 74
37. 17. 98. 62. A
74 × 3 – 4 = 218
218 × 3 – 74 = 650
Hence 654 is wrong and should be replaced by 650.
st
Sum of alphabets position in 1 row = 1 + 4 + 1 + 3 + 2 + 2 + 4 + 3 + 3 = 23
nd
Similarly, sum of digits in 2 row = 1 + 3 + 1 + 2 + 4 + 2 = 13
rd
Since, these are prime numbers, so sum of all given and unknown alphabets in 3 row
38. 18. 99. 63. D
should also be a prime no.
rd
Thus, 3 row = 1 + 2 + 3 + 4 + 4 + 3 + 1 + 1 = 19 (taking D option as correct).
No other option gives a prime value in such manner, hence correct answer is (D)

L
F
B
39. 19. 100. 64. B

So conclusions which follow are


1) All branches are leaves
2) Some leaves are branches
Time slot Person Relation Profession
9 - 10 Q (male) Father Cardiologist
10 - 11 T (male) Mother’s Brother Radiologist
11 - 12 S (female) Mother Gynecologist
40- 20- 101- 65- 12 - 1 V (female) Father’s sister General Physician
42. 22. 103. 67. 1–2 LUNCH
2–3 W (male) Elder son Orthodontist
3–4 R (female) Younger daughter Urologist
4–5 P (male) Younger son Neurologist
5–6 U (female) Elder daughter Pediatrician
40. 20. 101. 65. B
41. 21. 102. 66. D
If lunch break and subsequent working are reduced by 15 min. then the new timings in
order will be 1 – 1:45 (lunch), 1:45 – 2:30, 2:30 – 3:15, 3:15 – 4 & 4 – 4:45.
42. 22. 103. 67. D
Since U is the last doctor and she is Pediatrician, daughter of Cardiologist will reach the
clinic at 4pm
Total Pass (all years)
Overall pass percentage for Anga = × 100
Total Appeared (all years)
43. 23. 104. 68. A
850 + 770 + 1200 + 750 + 1190 4760
= × 100 = × 100 = 16.7%
5000 + 5500 + 6000 + 5000 + 7000 28500
Calculating the total of passed candidates for the given years
2012 → 3503
44. 24. 105. 69. D
2013 → 3570
2014 → 4226
IIFT - 2016
Answer key &
Explanations
2015 → 3360
Hence, least is for 2015.
The pass percentage of Banga kingdom for the given years =
640
1) 2012 = × 100 = 16%
4000
810
2) 2013 = × 100 = 18%
45. 25. 106. 70.
4500
C
1235
3) 2014 = × 100 = 19%
6500
660
4) 2016 = × 100 = 11%
6000
Hence, it is highest for 2014
Overall pass percentage for 2013 of all kingdoms
46. 26. 107. 71. B 770 + 810 + 275 + 1120 + 595 3570
= × 100 = × 100 = 14.88%
5500 + 4500 + 2500 + 8000 + 3500 24000
Calculating the total of passed candidates for given kingdoms:
Anga : 4760 Gandhar = 3890
47. 27. 108. 72. D
Banga : 4225 Dwarka = 4880
Hence, it is highest for Dwarka.
Checking the visibility of given brands across the stores:
111 48 91 30 80
1. Astute : + + + + = 0.94(approx.)
450 440 280 350 480
128 55 79 111 65
2. Supreme : + + + + = 1.13(approx.)
450 440 280 350 480
48- 28- 109- 73- 69 116 50 101 105
49. 32. 113. 77. 3. Paramount : + + + + = 1.1(approx.)
450 440 280 350 480
85 137 30 60 108
4. Smash : + + + + = 1.06(approx.)
450 440 280 350 480
57 84 30 48 122
5. Ultimate : + + + + = 0.82(approx.)
450 440 280 350 480
48. 28. 109. 73. B Hence, brand Supreme has the highest visibility (shown above).
49. 29. 110. 74. D Hence, brand Ultimate has the lowest visibility (shown above).
22
Total T-shirts given = 2000. So, T-shirts of size M = × 200 = 440
100
50. 30. 111. 75. A Total T-shirts of size M in stores 1, 2 & 5 = 10% of 1370 = 137. Hence, the remaining T-
shirts of size M = 440 – 137 = 303.
Now, since we want to minimize size M in store 4, so we maximize size M in store 3 which
can be 280 only. Hence remaining will be in store 4 = 303 – 280 = 23
Share of Supreme brand in all the stores 128 + 55 + 79 + 111 + 65 = 438
51. 31. 112. 76. B 438
Percentage share = × 100 = 21.9%
2000
Smash T-shirts = 420
52. 32. 113. 77. D 79
Ultimate T-shirts = 341, difference = 79. Now % = × 100 = 23.16 %
341
Ratio of total investment in Energy sector to Financial services in all the years =
Energy = 800 + 1200 + 500 + 1400 + 700 + 2500 + 600 + 1000 + 1100 + 500 = 10300
53. 33. 114. 78. A
Financial = 1800 + 500 + 400 + 2000 + 1200 + 1600 + 1000 + 1500 + 700 + 1400 = 12100
Hence, ratio = 103 : 121 or 1 : 1.2
Difference for Basic Materials = 4800
Communications = 1300
Consumer Cyclical = 3900
Consumer Defensive = 1800
Energy = 2900
54. 34. 115. 79. A
Financial Services = 1900
Health care = 6600
Real Estate = 3400
Technology = 8100
Hence, answer is option (A)
IIFT - 2016
Answer key &
Explanations
Total DI for 2009 : 12400
2010 : 8100
2011 : 14500
55. 35. 116. 80. A
2013 : 16000
Since total is maximum for 2013
So, average will also be highest for 2013.
Total DI for Basic Materials = 10000
Communications = 6300
Consumer cyclical = 4700
Consumer Defensive = 7300
Energy = 3700
56. 36. 117. 81. A
Financial services = 5100
Health care = 7500
Real estate = 13500
Technology = 8200
nd
Hence, the 2 lowest is Consumer cyclical.
Total DI = 66300
57. 37. 118. 82. B Total FI = 78400
Hence, required ratio = 2 : 2.36 or option (B)
105 + 185 + 100 + 120 + 110 620
Company A: = = 124
5 5
135 + 115 + 130 + 125 + 135 640
58. 38. 119. 83. C
Company B: = = 128
5 5
165 + 155 + 190 + 100 + 100 710
Company C: = = 142
5 5
So company C has maximum average annual expenses.
120 + 180 + 150 450
For 2011: = = 150
3 3
165 + 150 + 180 495
For 2012: = = 165
3 3
59. 39. 120. 84. B 135 + 165 + 180 480
For 2013: = = 160
3 3
180 + 150 + 135 465
For 2014: = = 155
3 3
So maximum average annual revenue is in the year 2012.
Revenue of C in 2015 → 120
Revenue of C in 2012 → 180
60. 40. 121. 85. C 180 − 120
% decrease = × 100 = 33% . Hence option C.
180
120 + 165 + 135 420
Average revenue of A in 2011, 2012, 2013 = = = 140
3 3
61. 41. 122. 86. C 165 + 150 + 165 480
Average revenue of B in 2013, 2014, 2015 = = = 160
3 3
Difference = 20 × 1000 = 20000. Hence, option C.
Profit in 2011 = 120 – 105 = 15
Profit in 2012 = 165 – 185 = - 20 (loss)
Profit in 2013 = 135 – 100 = 35
Profit in 2014 = 180 – 120 = 60
62. 42. 123. 87. B Profit in 2015 = 150 – 110 = 40
35 − (− 20 ) 55
So by observation, % increase in 2013 = × 100 = × 100 = 275%
20 20
Hence it is maximum, so answer is B option.
This option has been directly quoted in lines 17-20 “The stag nation ------ acquisition
63. 43. 1. 88. B
norms.”
64. 44. 2. 89. C Line 21 – 22 “Between 1989 – 2010 ----- workers”.
65. 45. 3. 90. B From Last 6 lines of the passage, this option is justified
66. 46. 4. 91. B First 5 lines of the passage.
67. 47. 5. 92. A Lines “The company’s brands bumped ---------- for local means” Line 4 – 9.
68. 48. 6. 93. C Lines “Consumers interact ------ on the first”. Line 22 – 24
IIFT - 2016
Answer key &
Explanations
The passage mentions how Reverse Innovation helped Pepsico grow in emerging markets
69. 49. 7. 94. D
when glocalisation failed to do so.
Option B is rejected as the passage quotes “If those effects are ignored then it is
70. 50. 8. 95. B indulgence without any balance”. Option C is justified by the author’s example of Kurkure
and Aliva.
71. 51. 9. 96. B Lines “ The hurdles to women ----------- cultural norms”. From Last Line no. 13-14
The overall idea emphasized in the passage is to increase female labour force participation
72. 52. 10. 97. D
for better growth of the economy
73. 53. 11. 98. C Lines “The IMF says ------ next seven years” From Last, line no 11 – 13
74. 54. 12. 99. C Lines “According to data ------ to 25 percent”.
Option A & C are too specific and do not cover the overall idea of the passage. SLAM is a
tech which is discounted by the author & the author does not support this tech. C is ruled
75. 55. 13. 100. B
out as the passage is not about used of digital camera but is rather based on use of digital
cameras in the field of robotics. Hence, B is our best possible choice.
76. 56. 14. 101. C The first 5 lines of the passage quote the reason that justifies option C.
Point (i) & (iv) are directly quoted in the passage. Point (ii) is wrong and the given
77. 57. 15. 102. C
combinations do not have (iii) inclusive. This makes C the best possible.
Lens 17 – 22 “A camera captures this ------------ of the moving camera.. State option B
78. 58. 16. 103. B
clearly.
This is the only combination of words according to the given meanings that fits in the given
79. 59. 17. 104. C
word puzzle
80. 60. 18. 105. B Option B has the correct placement of words according to the given meanings
81. 61. 19. 106. A Option A has the correct placement of words according to the given meanings
82. 62. 20. 107. C Option C has the correct placement of words according to the given meanings
83. 63. 21. 108. A A is the only option that has the correct given antonym pair
84. 64. 22. 109. C C is the only option that has the correct given antonym pair
85. 65. 23. 110. D Early 19th century: from French débutante (feminine) ‘leading off’, from the verb débuter
Late 16th century (in the sense ‘frequently encountered’): from Latin obvius (from the
86. 66. 24. 111. A
phrase ob viam ‘in the way’)
87. 67. 25. 112. B Late 19th century: English origin: shortening of Assoc. + -er
88. 68. 26. 113. D The correct spelling is “Danseuse”
89. 69. 27. 114. D The correct spelling here is “Acoustic”
Sultry means “hot and humid” which goes with the context mentioned in the first line of the
90. 70. 28. 115. C
paragraph
Herald means “signal; announce”. This goes with the given statement that says
91. 71. 29. 116. A irrespective of the weather, people came out on the streets to announce the traditional
festival
Exhorting means “strongly encourage or call out someone to do something” which fits in
92. 72. 30. 117. B
the context here
93. 73. 31. 118. C As the context here talks about taking gifts home, the best possible choice here is bagful
(c) Starts the line as it introduces what Nelson Mandela did. It is followed by (d) as it
94. 74. 32. 119. B
carries the same idea. This is followed by (b) and (a)
(b) starts the line as it talks about where/what the difference is. (d) is followed by (c)
95. 75. 33. 120. C
because of the “not just……but… “ pair. Hence, the logical order is badc
To have a chip on one's shoulder refers to the act of holding a grudge or grievance that
96. 76. 34. 121. C
readily provokes disputation.
97. 77. 35. 122. D Snafu means “a confused or chaotic state; a mess.”
98. 78. 36. 123. C Doughboy means “A fat puffy boy or man! Extremely fat that his skin looks like dough. “
99. 79. 37. 1. D
100. 80. 38. 2. C
101. 81. 39. 3. D
102. 82. 40. 4. C
103. 83. 41. 5. A
104. 84. 42. 6. B
105. 85. 43. 7. A
106. 86. 44. 8. C
107. 87. 45. 9. D
108. 88. 46. 10. C
109. 89. 47. 11. A
110. 90. 48. 12. D
111. 91. 49. 13. C
112. 92. 50. 14. A
113. 93. 51. 15. D
114. 94. 52. 16. A
115. 95. 53. 17. A
116. 96. 54. 18. B
IIFT - 2016
Answer key &
Explanations
117. 97. 55. 19. D
118. 98. 56. 20. B
119. 99. 57. 21. D
120. 100. 58. 22. B
121. 101. 59. 23. C
122. 102. 60. 24. B
123. 103. 61. 25. D
* It seems that few of the questions have all the options wrong.

You might also like