GROUP HOUSING BPTP PARK ELITE PREMIUM AT SECTOR-84,
FARIDABAD, HARYANA
I. FAULT LEVEL CALCULATIONS
A. FAULT LEVEL CALCULATION INCASE OF GRID SUPPLY OPERATION
The fault level calculations shall be done at 11KV end and separately at 415V end. The
system fault level at 11KV side has been assumed at 350 MVA.
By considering 350 MVA, The further calculations for 11KV end are as follows:
Fault Level in MVA = 350 MVA
Fault Level in KA = Fault Level MVA
Voltage X 1.732
= 350
11X1.732
= 18.37 KA
Say 18.4 KA.
II. Fault level Calculations at 415 Volt end :-
GRID supply is available and Two Transformers of 2250 KVA are operating
independently as envisaged.
Base MVA = 2.25 MVA
% Impedance of Transformer
at 2250 KVA base = 6.25%
Fault level MVA = 2.25 X 100 = 36 MVA
6.25
36
Fault level KA = = 48 KA
0.433 x 1.732
AMPOWER Page 29 6/4/2019
GROUP HOUSING BPTP PARK ELITE PREMIUM AT SECTOR-84,
FARIDABAD, HARYANA
B. Fault Current for DG Set in case of DG Set operation :-.
Total no of DG Set Proposed are Two Nos. 1000 KVA, One No. 750 KVA and One
No. 380 KVA.
Calculation of fault current for 1000 KVA DG Set.
If - (Full Load) = 2086 Amp
Xd’ - Sub Transient Reactance = 0.17 Per Unit (As Per Stamford)
Hence, Fault Current = If / Xd’
= 2086 / 0.17
=12.27 KA
Calculation of fault current for 750 KVA DG Set.
If - (Full Load) = 1043 Amp
Xd’ - Sub Transient reactance = 0.14 Per Unit ( As Per Stamford)
Hence, Fault current = If / Xd’
= 1043 / 0.14
= 7.45 KA
Calculation of fault current for 380 KVA DG Set.
If - (Full Load) = 528 Amp
Xd” - Sub Transient reactance = 0.14 Per Unit ( As Per Stamford)
Hence, Fault current = If / Xd”
= 528 / 0.14
= 3.77 KA
Fault Level of 2 No 1000 KVA 1 No. 750 KVA and 1 No. 380 KVA = 12.27 +
12.27+7.45+3.77=35.76KA
Hence fault level of 50 KA shall be considered for main L.T. / DG Panel design.
AMPOWER Page 30 6/4/2019