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Quiz All Sol

This document contains calculations and estimations for the materials needed for a construction project. It estimates excavation needs, foundation requirements, brick and mortar quantities for below and above the DPC, DPC and lintel materials, plastering inside and outside, roof slab, roof blanding, and roof tiles. For each element, it provides the volume, material quantities in bags or cubic meters, and sometimes counts such as number of bricks. The document aims to provide a full bill of materials for the described structure.

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محمد المهندس
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54 views4 pages

Quiz All Sol

This document contains calculations and estimations for the materials needed for a construction project. It estimates excavation needs, foundation requirements, brick and mortar quantities for below and above the DPC, DPC and lintel materials, plastering inside and outside, roof slab, roof blanding, and roof tiles. For each element, it provides the volume, material quantities in bags or cubic meters, and sometimes counts such as number of bricks. The document aims to provide a full bill of materials for the described structure.

Uploaded by

محمد المهندس
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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Estimation – Quiz – 2018 – 2nd.

Semester – Solution
Wisam Abdulla Najim AL–Halfi

1
Estimation – Quiz – 2018 – 2nd. Semester – Solution
Wisam Abdulla Najim AL–Halfi

1. Excavation :
Length = 2(8+0.24) + 2(6+0.24)
= 28.96 m.
Volume = length x width x height
= 28.96 x 0.6 x 0.6 = 10.4256 m3.
2. Foundation : ( 1:1.5:3):
V = 28.96 x 0.6 x 0.28 = 4.86528 m3.
V = 0.67(C+S+G)
4.86528 = 0.67 (1+1.5+3) C
C = 1.32029308 m3.
Cement = 37 bags.
Sand = 1.980 m3.
Gravel = 3.960 m3.
3. Bricks ( under D.P.C):
1st. V = 28.96 X 0.08 X 0.48 = 1.112064 m3.
2nd. V = 22.96 X 0.08 X 0.36 = 0.834048 m3.
3rd. V = 22.96 X 0.32 X 0.24 = 2.224128 m3.
Vtotal = 4.17024 m3.
No. of bricks = 450 X 4.17024 = 1877 bricks.
Morter :(1:3)
Vmorter = 0.23 X 4.17024 = 0.9591552 m3.
V = 0.75(C+S)
0.9591552 = 0.75 (1+3)C
C = 0.3197184 m3.
Cement = 9 bags.
Sand = 0.9591552 m3.
4. D.P.C.: (1:2:4):
V = 28.96 x 0.1 x 0.24 = 0.69504 m3.
V = 0.76 (1+2+4)C
C = 0.148196162 m3.
Cement = 5 bags.
Sand = 0.296 m3.
Gravel = 0.592 m3.

2
Estimation – Quiz – 2018 – 2nd. Semester – Solution
Wisam Abdulla Najim AL–Halfi

Lintel: (1:2:4)
V = 28.96 x 0.2 x 0.24 = 1.39008 m3.
C = 0.296 m3.
Cement = 9 bags.
Sand = 0.593 m3.
Gravel = 1.186 m3.
5. Bricks (above D.P.C.):
A = 28.96 x 4 = 115.84 m2.(+)
Adoor = 2.1 x 1 = 2.1 m2. (–)
A win. = 3(1.5 x 1) = 4.5 m2. (–)
Atotal = 115.84 – 2.1 – 4.5 = 109.24 m2.
V = Atotal X 0.24 = 109.24X0.24 = 26.2176 m3.
V lintel = 28.96 x 0.2 x 0.24 = 1.39008 m3. (–)
Vtotal = 24.82752 m3.
No. of bricks = 450 x 24.82752 = 11173 bricks.
Morter: (1:3):
Vmorter = 0.23 X 24.82752 = 5.7103296 m3.
V = 0.75(C+S)
5.7103296= 0.75 (1+3)C
C = 1.9034432 m3.
Cement = 54 bags.
Sand = 5.710 m3.
6. Plastering ( inside):
A = 2(8+6) x 4 = 112 m2.
Adoor = 2.1 x 1 = 2.1 m2. (–)
Awin.= 3(1.5 x 1) = 4.5 m2. (–)
Ar.door = (2.1+1+2.1) x 0.16 = 0.832 m2.(+)
Ar.win. = 3(1.5+1+1.5+1) x 0.08 = 1.2 m2.(+)
Atotal = 107.432 m2.
Vtotal = 107.432 x 0.02 = 2.14864 m3.
Quantity of lime = 1417 x 2.14864 = 3045 kg.
Vroof = 8 x 6 x 0.02 = 0.96 m3.
Quantity of lime = 1417 x 0.96 = 1361 kg.
Quantity of lime = 4406 kg.

3
Estimation – Quiz – 2018 – 2nd. Semester – Solution
Wisam Abdulla Najim AL–Halfi

7. Plastering (outside (1:3)):


A = 2(8.48+6.48) x 4.25 = 127.16 m2.
Adoor = 2.1 x 1 = 2.1 m2. (–)
Awin.= 3(1.5 x 1) = 4.5 m2. (–)
Ar.win. = 3(1.5+1+1.5+1) x 0.08 = 1.2 m2.(+)
Atotal = 121.76 m2.
Vtotal = 121.76 x 0.02 = 2.4352 m3.
C = 0.812 m3.
Cement = 23 bags.
Sand = 2.4352 m3.
8. Slab (roof): (1:2:4)
V = 8.48 x 6.48 x 0.15 = 8.24256 m3.
C = 1.757947548 m3.
Cement = 50 bags.
Sand = 3.515 m3.
Gravel = 7.030 m3.
9. Blanding: (1:2:4)
V = 8 x 6 x 0.05 = 2.4 m3.
C = 0.512 m3.
Cement = 15 bags.
Sand = 1.024 m3.
Gravel = 2.048 m3.
10. Tiles: (30X30)cm.
Aroom = 8X6 = 48 m2.
Atile = 0.303X0.303 = 0.091809 m2.
No. of tiles = (Aroom / Atile ) = 523 tiles

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