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11kV Copper Busbar Design Calculations

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srinu nagaraju
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100% found this document useful (1 vote)
761 views4 pages

11kV Copper Busbar Design Calculations

Uploaded by

srinu nagaraju
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
You are on page 1/ 4

VEE VEE CONTROLS PVT. LTD.

Bangalore

DESIGN CALCULATIONS
FOR

THERMAL WITHSTAND CAPABLITY, TEMPERATURE RISE &


SHORT CIRCUIT RATING

11kV, 26.3kA FOR 3 Sec, 800A, COPPER BUSBAR

Prepared By Checked By Approved By


D.R.JAYARAM

Page 1 of 4
VEE VEE CONTROLS PVT. LTD. Bangalore

Design parameters

1 Rated Voltage - 11kV

2 Frequency - 50Hz

3 Rated Current - 800A

4 Enclosure Material - CRCA

5 Busbar Material - Copper (EC-Grade)

6 Busbar Size - 1Rx80x10mm Flat.

7 Cross Sectional Area of the busbar - 800 Sq. mm

8 Short Circuit Current (Isc) - 26.3 kA.

9 Duration of Short Circuit (T) - 3 Sec.

10 Altitude - less than 1000Mts

11 Design Ambient Temperature - 500 C

12 Temperature rise over specified ambient temp. - 350 C

13 Hot spot temperature of Conductor Carrying Rated Current - 850 C

14 Hot spot temperature of Enclosure - 700 C

15 Max. Temperature Rise of Conductor during fault condition

While carrying rated current - 2000 C Over design ambient temperature

Page 2 of 4
VEE VEE CONTROLS PVT. LTD. Bangalore

Thermal Withstand Capability


Continues Current Rating

LASCPT PANEL
50°C = Designed Ambient Temperature
85°C = Final Temperature.
Required current as per specification = 800A.
Bus bar size = 1Rx80x10mm Copper
Current carrying capacity of Copper bus bar after correction due to various factors
Correction factor- K= K1xK2xK3xK4xK5
Continuous current carrying capacity of 1Rx80x10mm Cu. Bus bar as per DIN 43671 for initial
ambient temperature of 50°C & Conductor temperature of 85°C = 1500A
K1:- Conductivity factor = 1.0 (for Copper Busbar load variations relating to conductivity is
56m/Ωmm2) (
K2:- Correction factor for initial temperature of 50°C and final temperature of 85° C = 1.05
K3:- Correction factor bus bar more than 2mtr. = 0.80 (considered minimum factor for 2 nos.)
K4:- Correction factor for bus bar layout = 1.0 (K4 is applicable for bubsar more than 1 run/phase,
we have consider deration factor 1 because we have used 1 run bus bar in Panel.
K5:- Correction factor for influence specific to location = 0.99 (reduction in load at altitude below
2000mts, height above sea level)
Correction factor- K= K1xK2xK3xK4xK5
Correction factor K= 1.0x1.05x0.8x1.0x0.99= 0.8316
Corrected current rating = K x 1500 = 0.8316x 1500= 1,247.4A
Current rating required = 800A.
Current rating arrived after considering correction factors = 1,247.4A

Conclusion: The bus bar 1Rx80x10mm carries current rating of 1247.4A. Which is more than the
requirement of 800A
Temperature Rise Calculation for Continuous Current Rating
Current Rating ( Ir ) = 800A
Continuous Current Rating of the Busbar ( Ic ) = 1247.4A
Final Temperature ( Tf) = 85ºC
Ambient Temperature (Ta ) = 50 ºC
Rise in Temperature ( Tr ) = ( Tf-Ta) = 35 ºC

Estimated = 35( Ir/Ic) ^1.7


35(800/1247.4) ^1.7
16.44 ºC

Page 3 of 4
VEE VEE CONTROLS PVT. LTD. Bangalore

Calculation of Short Circuit Rating:


Minimum Cross section required to rise the Temperature of conductor from 85 0 C to 2000 C is
calculated using the formula (Refer Annex A.3):
Icu
A = ------------------------------------------------------
0.22 x 104 x  log 2 -20 + (25400/G)
t 1 + 20 + (25400/G)

Where
Icu = Maximum rms amperes for copper conductor- 26300 A
A = cross-sectional area in square inches - -- sqin
t = the duration of the constant current flow - 3 Sec.
1 = Operating Temperature - 850 C
2 = Max. Temperature allowed on SC - 2000 C (Min.)
(Note: Max. Allowed is 3000 C)
G = the conductivity in percent IACS - 95% (Min.)

26300
A = ------------------------------------------------------
0.22 x 106 x  log  -20 + (25400/95)
3 + 20 + (25400/95)

26300
A = ------------------------------------------------------
0.22 x 106 x  log 
3 

A = 0.727522083 Sq.in

Minimum Area of conductor required = 0.7334745 Sq.in


Minimum Area of conductor required in mm = 0.7334745 * 645.16 Sq.mm
= 473.2 Sq.mm
The Cross section area actually adopted = 800 Sq. mm

Page 4 of 4

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