SECTION 4: MOSFETS
ECE 322 – Electronics I
2 MOSFET Device Introduction
K. Webb ECE 322
MOSFETs
3
We now turn our attention to another type of transistor, the
MOSFET:
Metal Oxide Semiconductor Field Effect Transistor
Many similarities to the BJT:
Three terminals
Voltage at one terminal controls current between the other two
◼ A transconductance device
Two polarities: N-channel and P-channel MOSFETS
◼ Our focus will primarily be N-channel MOSFETs (NMOS devices)
N-Channel P-Channel
(NMOS): (PMOS):
K. Webb ECE 322
MOSFETs
4
MOSFETs are actually four-terminal devices
Fourth terminal is the body, substrate, or bulk
The body is often tied to the source, and we can mostly
ignore it
Discrete devices
Other times we must account for the body potential effect
on device behavior
Often the case in integrated circuits
NMOS: PMOS:
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Physical Structure - NMOS
5
Sedra/Smith
P-type substrate
N+ source and drain
Metal gate electrode, and source/drain/body contacts
Thin oxide insulates the gate from the rest of the device
Region of substrate between the drain and source is the channel
Channel dimensions: W and L
We’ll see later why this is called an n-channel (NMOS) device
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Terminal Voltages and Currents
6
Terminal voltages and currents named
as shown
Again, lower-case 𝑣/𝑖 and upper-case
subscript represents total (AC and DC)
voltage and current
For an NMOS device in typical
operation:
𝑣𝐺𝑆 ≥ 0
𝑣𝐷𝑆 ≥ 0
Gate oxide does not allow current to
flow, so
𝑖𝐺 = 0
and
𝑖𝐷 = 𝑖𝑆
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MOSFET Operating Regions
7
Three MOSFET operating regions:
Cut-off
Triode
Saturation
A MOSFET’s operating region is determined by its
terminal voltages
Next, we will look in detail at each of these three
regions, along with their 𝑖 − 𝑣 characteristics
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8 Cut-Off Region
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Cut-Off Region
9
Gate and source both
grounded
𝑣𝐺𝑆 = 0
Drain-to-source pathway looks
like two back-to-back diodes
Very high drain-source
resistance (𝑟𝐷𝑆 = ∞)
Even for 𝑣𝐷𝑆 > 0, no current
will flow
𝑖𝐷 = 0
Looks like an open switch
Similar to BJT cut-off operation
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10 Triode Region
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Triode Region – Inversion
11
Now, 𝑣𝐺𝑆 is increased, while 𝑣𝐷𝑆 is kept small
Electric field established across gate oxide
Holes in p-type substrate repelled deeper into substrate
Electrons from drain and source attracted to region below the gate
For large enough 𝑣𝐺𝑆 , p-type material below the gate is inverted to n-type
An inversion layer
Induced n-type channel connects drain to source
Now, current can flow in response to 𝑣𝐷𝑆 , 𝑖𝐷 > 0
K. Webb ECE 322
Threshold Voltage
12
Channel is induced once 𝑣𝐺𝑆 exceeds a certain voltage:
The threshold voltage
𝑣𝐺𝑆 ≥ 𝑉𝑡
A device parameter
Typically, 𝑉𝑡 = 300 𝑚𝑉 … 1 𝑉
As 𝑣𝐺𝑆 increases beyond 𝑉𝑡 , the induced channel gets deeper
As long as 𝑣𝐷𝑆 is small (𝑣𝐷𝑆 ≪ 𝑉𝑡 ), channel depth is uniform
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Overdrive Voltage
13
A channel is induced once 𝑣𝐺𝑆 exceeds the threshold voltage
𝑣𝐺𝑆 in excess of the threshold voltage is called the overdrive voltage
or effective voltage:
𝑣𝑂𝑉 = 𝑣𝐺𝑆 − 𝑉𝑡
As we will soon see, 𝑣𝑂𝑉 plays an important role in determining
device behavior
K. Webb ECE 322
Triode Region
14
As 𝑣𝐷𝑆 increases:
Voltage varies along the channel
◼ 𝑣𝑆 near the source, 𝑣𝐷 near the drain
Gate-to-channel voltage decreases closer to the drain
Channel depth decreases closer to the drain
◼ Channel is tapered
More current flows with increasing 𝑣𝐷𝑆 , but channel
resistance increases as channel becomes more tapered
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Triode Region - 𝑖-𝑣 Relationship
15
Drain current in the triode region:
𝑊 1
𝑖𝐷 = 𝜇𝑛 𝐶𝑜𝑥 𝑣𝐺𝑆 − 𝑉𝑡 − 𝑣𝐷𝑆 𝑣𝐷𝑆
𝐿 2
𝑊 1
𝑖𝐷 = 𝜇𝑛 𝐶𝑜𝑥 𝑣𝑂𝑉 − 𝑣𝐷𝑆 𝑣𝐷𝑆
𝐿 2
where:
◼ 𝜇𝑛 : electron mobility
◼ 𝐶𝑜𝑥 : oxide capacitance
◼ 𝑊: channel width
◼ 𝐿: channel length
We can also express the drain current as
𝑊 1 𝑊 1 2
𝑖𝐷 = 𝑘𝑛′ 𝑣𝑂𝑉 − 𝑣𝐷𝑆 𝑣𝐷𝑆 = 𝑘𝑛′ 𝑣𝑂𝑉 𝑣𝐷𝑆 − 𝑣𝐷𝑆
𝐿 2 𝐿 2
where:
◼ 𝑘𝑛′ = 𝜇𝑛 𝐶𝑜𝑥 is the process transconductance parameter
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Triode Region - 𝑖-𝑣 Relationship
16
Triode region:
𝑣𝐺𝑆 > 𝑉𝑡
𝑣𝐷𝑆 < 𝑣𝑂𝑉
For 𝑣𝐷𝑆 ≪ 𝑣𝑜𝑣
Nearly a linear resistance
Resistance linearly
proportional to 𝑣𝑂𝑉
1
𝑟𝐷𝑆 =
𝑊
𝑘𝑛′ 𝑣
𝐿 𝑂𝑉
As 𝑣𝐷𝑆 increases
Channel taper increases
𝑟𝐷𝑆 increases
𝑖𝐷 -𝑣𝐷𝑆 slope decreases
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17 Saturation Region
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Device Operation – Channel Pinch-Off
18
Eventually, for large enough 𝑣𝐷𝑆
Gate-to-channel voltage near the drain no longer exceeds 𝑉𝑡
Channel pinch-off occurs
Channel disappears at the edge of the drain
Pinch-off occurs when:
𝑣𝐺𝐷 = 𝑉𝑡 = 𝑣𝐺𝑆 − 𝑣𝐷𝑆
𝑣𝐷𝑆 = 𝑣𝐺𝑆 − 𝑉𝑡
𝑣𝐷𝑆 = 𝑣𝑂𝑉
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Saturation Region
19
Once channel pinch-off
occurs:
Voltage at the drain-end of
the channel remains 𝑣𝑂𝑉 ,
even as 𝑣𝐷𝑆 increases
Any increase in 𝑣𝐷𝑆 beyond
𝑣𝑂𝑉 is dropped across the
depletion region surrounding
the drain
Voltage across the length of the channel is fixed at 𝑣𝑂𝑉
Pinched-off channel shape does not change with 𝑣𝐷𝑆
Drain current saturates at a constant value for constant 𝑣𝐺𝑆
Analogous to the forward-active region for BJTs
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Saturation - 𝑖-𝑣 Relationship
20
Drain current in the saturation region still given by
𝑊 1 2
𝑖𝐷 = 𝑘𝑛′ 𝑣𝑂𝑉 𝑣𝐷𝑆 − 𝑣𝐷𝑆
𝐿 2
But now, the voltage from the drain-end to source-end of
the channel is 𝑣𝑂𝑉
Replacing 𝑣𝐷𝑆 with 𝑣𝑂𝑉 , the drain current relationship
becomes
1 ′ 𝑊 2 1 ′ 𝑊 2
𝑖𝐷 = 𝑘𝑛 𝑣 = 𝑘 𝑣𝐺𝑆 − 𝑉𝑡
2 𝐿 𝑂𝑉 2 𝑛 𝐿
Purely a function of 𝑣𝐺𝑆 (or 𝑣𝑂𝑉 )
Independent of 𝑣𝐷𝑆
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Input I-V Characteristic
21
In saturation, drain current
has a quadratic dependence
on 𝑣𝐺𝑆 (𝑣𝑂𝑉 )
1 ′𝑊 2
𝑖𝐷 = 𝑘𝑛 𝑣 − 𝑉𝑡
2 𝐿 𝐺𝑆
1 ′𝑊 2
𝑖𝐷 = 𝑘𝑛 𝑣𝑂𝑉
2 𝐿
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Output I-V Characteristic
22
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NMOS Operating Regions – Summary
23
Cutoff:
𝑣𝐺𝑆 < 𝑉𝑡
𝑖𝐷 = 0
Triode:
𝑣𝐺𝑆 > 𝑉𝑡
𝑣𝐷𝑆 < 𝑣𝑂𝑉 or 𝑣𝐺𝐷 > 𝑉𝑡
𝑊 12 𝑊 1 2
𝑖𝐷 = 𝜇𝑛 𝐶𝑜𝑥 𝐿
𝑣𝑂𝑉 𝑣𝐷𝑆 − 2 𝑣𝐷𝑆 = 𝑘𝑛′ 𝐿
𝑣𝑂𝑉 𝑣𝐷𝑆 − 2 𝑣𝐷𝑆
Saturation:
𝑣𝐺𝑆 > 𝑉𝑡
𝑣𝐷𝑆 > 𝑣𝑂𝑉 or 𝑣𝐺𝐷 < 𝑉𝑡
1 𝑊 2 1 𝑊 2
𝑖𝐷 = 2 𝑘𝑛′ 𝑣𝐺𝑆 − 𝑉𝑡𝑝 = 2 𝑘𝑛′ 𝑣
𝐿 𝐿 𝑂𝑉
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24 P-Channel MOSFETs
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P-Channel MOSFETs
25
Voltage polarities and doping types reversed relative to NMOS
N-type substrate
P+ drain and source
Negative threshold voltage: 𝑉𝑡𝑝 < 0
Negative overdrive voltage: 𝑣𝑂𝑉 = 𝑣𝐺𝑆 − 𝑉𝑡𝑝 < 0
Channel induced for 𝑣𝐺𝑆 ≤ 𝑉𝑡𝑝
Substrate connected to source or most positive circuit voltage
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PMOS – Operating Regions
26
Cutoff:
𝑣𝐺𝑆 > 𝑉𝑡𝑝
𝑖𝐷 = 0
Triode:
𝑣𝐺𝑆 < 𝑉𝑡𝑝 , 𝑣𝐺𝑆 > 𝑉𝑡𝑝
𝑣𝐷𝑆 > 𝑣𝑂𝑉 , 𝑣𝐷𝑆 < 𝑣𝑂𝑉
𝑊 12 𝑊 1 2
𝑖𝐷 = 𝜇𝑝 𝐶𝑜𝑥 𝐿
𝑣𝑂𝑉 𝑣𝐷𝑆 − 2 𝑣𝐷𝑆 = 𝑘𝑝′ 𝐿
𝑣𝑂𝑉 𝑣𝐷𝑆 − 2 𝑣𝐷𝑆
Saturation:
𝑣𝐺𝑆 < 𝑉𝑡𝑝 , 𝑣𝐺𝑆 > 𝑉𝑡𝑝
𝑣𝐷𝑆 < 𝑣𝑂𝑉 , 𝑣𝐷𝑆 > 𝑣𝑂𝑉
1 𝑊 2 1 𝑊 2
𝑖𝐷 = 2 𝑘𝑝′ 𝑣𝐺𝑆 − 𝑉𝑡𝑝 = 2 𝑘𝑝′ 𝑣
𝐿 𝐿 𝑂𝑉
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CMOS
27
Complementary MOS or CMOS
Both NMOS and PMOS fabricated on the same chip
P-type substrate
PMOS devices fabricated in n wells
Most modern MOS chips are fabricated using CMOS technology
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28 Large-Signal MOSFET Model
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Equivalent Circuit Models
29
As was the case for BJTs, we use two types of
equivalent-circuit models for MOSFETs:
Large-signal model
Models the transistor’s behavior to DC signals
Used to determine the transistor’s DC operating point
Small-signal model
Models the behavior in response to small signals
Describes the response to the AC signals to be
amplified
Properties of the small-signal model determined by the
DC operating point
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Large-Signal Model – Saturation
30
Large-signal behavior in the saturation region is modeled by the
following circuit:
Replace the transistor with the appropriate model to determine the
DC operating point (Q-point)
Saturation-region bias assumed
If incorrect, model will say otherwise
Because 𝑖𝐺 = 0, we generally do not need to explicitly use the
equivalent circuit model for large-signal analysis for MOSFETs
Often just use the I-V model
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DC Operating Point – Example 1
31
Determine 𝐼𝐷 and 𝑉𝐷 for 𝜇𝑛 = 500
𝑐𝑚2
the following circuit 𝑉⋅𝑠
𝑓𝐹
Is the device operating in 𝐶𝑜𝑥 = 3.8
𝜇𝑚2
the saturation region?
𝑉𝑡 = 500 𝑚𝑉
𝐿 = 0.5 𝜇𝑚
The process 𝑊 = 50 𝜇𝑚
transconductance
parameter:
2 −15
𝑚 3.8 × 10 𝐹 𝜇𝐴
𝑘𝑛′ = 𝜇𝑛 𝐶𝑜𝑥 = 500 × 10 −4
⋅ = 190 2
𝑉 ⋅ 𝑠 1 × 10−12 𝑚2 𝑉
Use the saturation region large-signal model
I-V model, not necessarily the equivalent-circuit model
Analysis will indicate if saturation assumption is incorrect
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DC Operating Point – Example 1
32
Drain current in saturation:
1 ′ 𝑊 2
𝐼𝐷 = 𝑘𝑛 𝑉𝐺𝑆 − 𝑉𝑡
2 𝐿
1 𝜇𝐴 50 𝜇𝑚 2
𝐼𝐷 = ⋅ 190 2 ⋅ 800 𝑚𝑉 − 500 𝑚𝑉
2 𝑉 0.5 𝜇𝑚
𝐼𝐷 = 855 𝜇𝐴
Voltage at the drain:
𝑉𝐷 = 𝑉𝐷𝐷 − 𝐼𝐷 𝑅𝐷
𝑉𝐷 = 3.3 𝑉 − 855 𝜇𝐴 ⋅ 1.8 𝑘Ω
𝑉𝐷 = 1.76 𝑉
The device is operating in the saturation region
The drain-to-source voltage exceeds the overdrive voltage
𝑉𝐷𝑆 = 𝑉𝐷 = 1.76 𝑉 > 𝑉𝑂𝑉 = 𝑉𝐺𝑆 − 𝑉𝑡 = 300 𝑚𝑉
K. Webb ECE 322
DC Operating Point – Example 2
33
For the same circuit, determine
𝑉𝐺𝑆 for 𝑉𝐷 = 1 𝑉 𝑐𝑚2
𝜇𝑛 = 500
Is the device still operating in the 𝑉⋅𝑠
saturation region? 𝑓𝐹
𝐶𝑜𝑥 = 3.8
𝜇𝑚2
For 𝑉𝐷 = 1 𝑉 𝑉𝑡 = 500 𝑚𝑉
𝑉𝐷𝐷 − 𝑉𝐷 3.3 𝑉 − 1 𝑉 𝐿 = 0.5 𝜇𝑚
𝐼𝐷 = =
𝑅𝐷 1.8 𝑘Ω
𝑊 = 50 𝜇𝑚
2.3 𝑉
𝐼𝐷 = = 1.28 𝑚𝐴
1.8 𝑘Ω
Assuming saturation-region operation
1 𝑊 2 1 𝜇𝐴 50 𝜇𝑚 2
𝐼𝐷 = 𝑘𝑛′ 𝑉𝑂𝑉 = ⋅ 190 2 ⋅ ⋅ 𝑉𝑂𝑉 = 1.28 𝑚𝐴
2 𝐿 2 𝑉 0.5 𝜇𝑚
Solving for the overdrive voltage
𝑉𝑂𝑉 = 367 𝑚𝑉
K. Webb ECE 322
DC Operating Point – Example 2
34
The required gate-to-source voltage is
𝑉𝐺𝑆 = 𝑉𝑡 + 𝑉𝑂𝑉
𝑉𝐺𝑆 = 500 𝑚𝑉 + 367 𝑚𝑉
𝑉𝐺𝑆 = 867 𝑚𝑉
The drain-to-source voltage exceeds
the overdrive voltage
The transistor is operating in the
saturation region
𝑉𝐷𝑆 = 1𝑉 > 𝑉𝑂𝑉 = 367 𝑚𝑉
K. Webb ECE 322
DC Operating Point – Example 3
35
Find 𝑅𝐷 and 𝑅𝑆 for
𝜇𝐴
𝑘𝑛′ = 400
𝐼𝐷 = 200 𝜇𝐴 and 𝑉𝐷 = 200 𝑚𝑉 𝑉2
𝑉𝑡 = 500 𝑚𝑉
First, determine 𝑅𝐷
𝐿 = 0.5 𝜇𝑚
𝑉𝐷𝐷 − 𝑉𝐷 1 𝑉 − 200 𝑚𝑉
𝑅𝐷 = = 𝑊 = 15 𝜇𝑚
𝐼𝐷 200 𝜇𝐴
𝑅𝐷 = 4 𝑘Ω
Drain current in saturation is given by
1 𝑊 2 2𝐼𝐷 𝐿
𝐼𝐷 = 𝑘𝑛′ 𝑉 → 𝑉𝑂𝑉 =
2 𝐿 𝑂𝑉 𝑘𝑛′ 𝑊
2 ⋅ 200 𝜇𝐴 0.5𝜇𝑚
𝑉𝑂𝑉 = = 182.6 𝑚𝑉
400 𝜇𝐴/𝑉 2 15 𝜇𝑚
K. Webb ECE 322
DC Operating Point – Example 3
36
The gate-to-source voltage is
𝑉𝐺𝑆 = 𝑉𝑡 + 𝑉𝑂𝑉 = 500 𝑚𝑉 + 182.6 𝑚𝑉
𝑉𝐺𝑆 = 683 𝑚𝑉
The gate is grounded, so the source
voltage is
𝑉𝑆 = 𝑉𝐺 − 𝑉𝐺𝑆 = −683 𝑚𝑉
The source resistance is given by
𝑉𝑆 − 𝑉𝑆𝑆 −683 𝑚𝑉 − −1 𝑉
𝑅𝑆 = =
𝐼𝐷 200 𝜇𝐴
𝑅𝑆 = 1.59 𝑘Ω
K. Webb ECE 322
DC Operating Point – Example 4
37
Find 𝐼𝐷 and 𝑅𝐷 for 𝑉𝐷 = 100 𝑚𝑉 𝑊 𝑚𝐴
What is the drain-to-source 𝑘𝑛′ =2 2
𝐿 𝑉
resistance, 𝑟𝐷𝑆 ? 𝑉𝑡 = 500 𝑚𝑉
The device is in the triode region:
𝑉𝑂𝑉 = 𝑉𝐺𝑆 − 𝑉𝑡 = 2 𝑉 − 500 𝑚𝑉 = 1.5 𝑉
𝑉𝐷𝑆 = 100 𝑚𝑉 < 𝑉𝑂𝑉
Drain current in triode is given by
𝑊 1
𝐼𝐷 = 𝑘𝑛′ 𝑉𝑂𝑉 − 𝑉𝐷𝑆 𝑉𝐷𝑆
𝐿 2
𝑚𝐴
𝐼𝐷 = 2 1.5 𝑉 − 50 𝑚𝑉 100 𝑚𝑉
𝑉2
𝐼𝐷 = 290 𝜇𝐴
K. Webb ECE 322
DC Operating Point – Example 4
38
The required drain resistance:
𝑉𝐷𝐷 − 𝑉𝐷 1.9 𝑉
𝑅𝐷 = =
𝐼𝐷 290 𝜇𝐴
𝑅𝐷 = 6.55 𝑘Ω
The drain-to-source resistance in the triode
region is given by:
1
𝑟𝐷𝑆 =
𝑊
𝑘𝑛′ 𝐿 𝑉𝑂𝑉
1
𝑟𝐷𝑆 =
𝑚𝐴
2 2 1.5 𝑉
𝑉
𝑟𝐷𝑆 = 333 Ω
K. Webb ECE 322
DC Operating Point – Example 5
39
Find 𝐼𝐷 , 𝑉𝐺 , 𝑉𝐷 , and 𝑉𝑆 for the
following circuit
The gate voltage is simply set by the 𝑘𝑛′
𝑊 𝑚𝐴
=1 2
voltage divider 𝐿 𝑉
10 𝑀Ω 𝑉𝑡 = 1 𝑉
𝑉𝐺 = 10 𝑉
10 𝑀Ω + 10 𝑀Ω
𝑉𝐺 = 5 𝑉
Assuming operation in the saturation region, drain current is
1 ′ 𝑊 2
1 ′ 𝑊 2
𝐼𝐷 = 𝑘𝑛 𝑉𝐺𝑆 − 𝑉𝑡 = 𝑘𝑛 𝑉𝐺 − 𝐼𝐷 𝑅𝑆 − 𝑉𝑡
2 𝐿 2 𝐿
𝑚𝐴 2
𝐼𝐷 = 0.5 5 𝑉 − 𝐼𝐷 𝑅𝑆 − 1 𝑉
𝑉2
K. Webb ECE 322
DC Operating Point – Example 5
40
𝑚𝐴 2
𝐼𝐷 = 0.5 2 4 𝑉 − 𝐼𝐷 ⋅ 6 𝑘Ω
𝑉
This is a quadratic equation for 𝐼𝐷
𝐼𝐷 = 18𝐸3 𝐼𝐷2 − 24 𝐼𝐷 + 8𝐸 − 3
Two possible solutions:
𝐼𝐷 = 889 𝜇𝐴 or 𝐼𝐷 = 500 𝜇𝐴
For 𝐼𝐷 = 889 𝜇𝐴
𝑉𝐷 = 𝑉𝐷𝐷 − 𝐼𝐷 𝑅𝐷 = 10 𝑉 − 889 𝜇𝐴 ⋅ 6 𝑘Ω = 4.67 𝑉
𝑉𝑆 = 𝐼𝐷 ⋅ 𝑅𝑆 = 889 𝜇𝐴 ⋅ 6 𝑘Ω = 5.33 𝑉
𝑉𝐺𝑆 = 𝑉𝐺 − 𝑉𝑆 = −333 𝑚𝑉
K. Webb ECE 322
DC Operating Point – Example 5
41
For 𝐼𝐷 = 889 𝜇𝐴
𝑉𝐺𝑆 < 0
The transistor is in the cut-off region
The valid solution to the quadratic equation
must be
𝐼𝐷 = 500 𝜇𝐴
The drain and source voltages are
𝑉𝐷 = 𝑉𝐷𝐷 − 𝐼𝐷 𝑅𝐷 = 10 𝑉 − 500 𝜇𝐴 ⋅ 6 𝑘Ω
𝑉𝐷 = 7 𝑉
𝑉𝑆 = 𝐼𝐷 ⋅ 𝑅𝑆 = 500 𝜇𝐴 ⋅ 6 𝑘Ω
𝑉𝑆 = 3 𝑉
K. Webb ECE 322
42 Channel-Length Modulation
K. Webb ECE 322
Channel-Length Modulation
43
So far, our MOSFET model in the saturation region models drain
current as independent of 𝑣𝐷𝑆
1 ′ 𝑊 2
𝑖𝐷 = 𝑘𝑛 𝑣𝑂𝑉
2 𝐿
Flat I-V characteristic in the saturation region
In reality, current increases as 𝑣𝐷𝑆 increases
Increase in 𝑖𝐷 due to channel-length modulation
K. Webb ECE 322
Channel-Length Modulation
44
Justification for constant saturation current was:
Channel shape does not change after pinch-off occurs
Any additional 𝑣𝐷𝑆 is dropped across the depletion region
surrounding the drain
But, as 𝑣𝐷𝑆 increases, the drain depletion region increases,
and the channel length decreases
K. Webb ECE 322
Channel-Length Modulation
45
Drain current is inversely proportional to channel length
1
𝑖𝐷 ∝
𝐿
So, as 𝑣𝐷𝑆 increases, 𝐿 decreases, and 𝑖𝐷 increases
Non-zero slope in the saturation region of the 𝑖𝐷 -𝑣𝐷𝑆 curve:
K. Webb ECE 322
Channel-Length Modulation
46
This effect is accounted for by the channel-length
modulation parameter, 𝜆
1 ′𝑊 2
𝑖𝐷 = 𝑘𝑛 𝑣𝐺𝑆 − 𝑉𝑡 1 + 𝜆𝑣𝐷𝑆
2 𝐿
𝜆 is inversely proportional to channel length, 𝐿
1
𝜆 related to the Early voltage: 𝜆 =
𝑉𝐴
K. Webb ECE 322
Output Resistance
47
Slope of the 𝑖𝐷 -𝑣𝐷𝑆 characteristic is the inverse of the
transistor’s output resistance
Resistance seen looking into the drain
Constant saturation current implies infinite output
resistance
K. Webb ECE 322
Output Resistance
48
Output resistance given by
−1
𝜕𝑖𝐷
𝑟𝑜 =
𝜕𝑣𝐷𝑆
The inverse of the slope of the 𝑖𝐷 -𝑣𝐷𝑆 characteristic
Channel-length modulation results in finite output resistance
K. Webb ECE 322
Output Resistance
49
Model the finite output resistance due to channel-length modulation
by adding a resistor to our large-signal model
Output resistance given by
−1 −1
𝜕𝑖𝐷 𝜕 1 ′𝑊 2
𝑟𝑜 = = 𝑘 𝑣 − 𝑉𝑡 1 + 𝜆𝑣𝐷𝑆
𝜕𝑣𝐷𝑆 𝜕𝑣𝐷𝑆 2 𝑛 𝐿 𝐺𝑆
−1
𝜆 ′𝑊 2
𝑟𝑜 = 𝑘𝑛 𝑣 − 𝑉𝑡
2 𝐿 𝐺𝑆
1 𝑉𝐴
𝑟𝑜 = =
𝜆𝐼𝐷′ 𝐼𝐷′
K. Webb ECE 322
50 The Body Effect
K. Webb ECE 322
The Body Effect
51
So far, we have largely ignored the connection to the
substrate
Equivalently, we have assumed it to be tied to the source:
NMOS: PMOS:
This a valid assumption for discrete devices
Not so for MOSFETs on integrated circuits (ICs)
K. Webb ECE 322
The Body Effect
52
For integrated circuits, the substrate is typically tied
to the most negative supply voltage for NMOS
devices
PMOS n-wells tied to the most positive supply voltage
Substrate for a given device may well be biased
below its source voltage (above for PMOS)
This is the bias voltage for the channel region
For 𝑉𝑆𝐵 > 0 (𝑉𝑆𝐵 < 0 for PMOS), the threshold
voltage is effectively increased
This is the body effect
K. Webb ECE 322
53 MOSFETs as Switches
K. Webb ECE 322
MOSFETs as Switches
54
Our focus is on the use of MOSFETs for linear
amplifiers in analog circuits
Operation in the saturation region
MOSFETs are also useful as switches in digital
circuits
Microprocessors contain billions of MOSFETs used as
switches on a single chip
When operating as a switch, MOSFETs alternate
between the triode (on, closed) and cutoff (off,
open) regions
K. Webb ECE 322
Triode/Cutoff Region Models
55
MOSFETs used as switches operate alternately in the triode (closed)
and cutoff (open) regions
Equivalent circuit models:
Triode Region (ON): Cutoff Region (OFF):
𝑉𝐺𝑆 > 𝑉𝑡 𝑉𝐺𝑆 < 𝑉𝑡
◼ 𝑉𝐺𝑆 = 𝑉𝐷𝐷 ◼ 𝑉𝐺𝑆 = 0
Switch is on Switch is off
𝐼𝐷 ≥ 0 𝐼𝐷 = 0
𝑉𝐷𝑆 = 𝐼𝐷 𝑟𝐷𝑆 < 𝑉𝑂𝑉 𝑉𝐷𝑆 = 𝑉𝐷𝐷
K. Webb ECE 322
Inverters
56
The inverter is a fundamental building block of digital
logic circuits
Output is the inverse of the input
When the input is a logic high (1/T) the output is low (0/F)
When the input is low (0/F) the output is high (1/T)
K. Webb ECE 322
CMOS Inverter
57
CMOS inverters make use of
NMOS and PMOS devices
acting as switches
Input applied to gate of each
device
Output taken from their drain
terminals
When one switch is on, the
other is off
Output connected to either
VDD or ground
K. Webb ECE 322
CMOS Inverter
58
Input is high:
𝑉𝐼 = 𝑉𝐷𝐷
𝑉𝐺𝑆𝑝 = 0 𝑉 < 𝑉𝑡𝑝
◼ PMOS device is off
𝑉𝐺𝑆𝑛 = 𝑉𝐷𝐷 > 𝑉𝑡𝑛
◼ NMOS device is on
𝑉𝑂 ≈ 0 𝑉
K. Webb ECE 322
CMOS Inverter
59
Input is low:
𝑉𝐼 =0𝑉
𝑉𝐺𝑆𝑝 = 𝑉𝐷𝐷 > 𝑉𝑡𝑝
◼ PMOS device is on
𝑉𝐺𝑆𝑛 = 0 𝑉 < 𝑉𝑡𝑛
◼ NMOS device is off
𝑉𝑂 ≈ 𝑉𝐷𝐷
K. Webb ECE 322
60 Small-Signal Models
K. Webb ECE 322
MOSFET Small-Signal Hybrid-𝜋 Model
61
Just as with BJTs, we use the large-signal model to determine
the MOSFET’s DC operating point
DC terminal voltages and drain
current
Need a small-signal model to
describes the MOSFETs
response to small signals
To describe its behavior as an
amplifier
Small-signal model parameters
determined by the DC
operating point
K. Webb ECE 322
MOSFET Small-Signal Hybrid-𝜋 Model
62
Similar to the BJT hybrid-𝜋 model
But, input resistance at the gate is infinite:
𝑖𝑔 = 0
Transconductance, 𝑔𝑚 , defined as
𝜕𝑖𝑑
𝑔𝑚 ≡
𝜕𝑣𝑔𝑠
Where 𝑖𝑑 and 𝑣𝑔𝑠 are the small-signal components of the drain current
and gate-source voltage , respectively
Transconductance determined by the DC operating point:
𝑊
𝑔𝑚 = 𝜇𝑛 𝐶𝑜𝑥 𝑉𝐺𝑆 − 𝑉𝑡
𝐿
𝑊
𝑔𝑚 = 𝑘𝑛′ 𝑉
𝐿 𝑂𝑉
K. Webb ECE 322
MOSFET Small-Signal Hybrid-𝜋 Model
63
𝑊
𝑔𝑚 = 𝑘𝑛′ 𝑉
𝐿 𝑂𝑉
Recall that DC drain current is given by
1 ′ 𝑊 2
𝐼𝐷 = 𝑘𝑛 𝑉
2 𝐿 𝑂𝑉
Solving for 𝑉𝑂𝑉 :
2𝐼𝐷
𝑉𝑂𝑉 =
𝑊
𝑘𝑛′ 𝐿
Substituting the 𝑉𝑂𝑉 expression into the 𝑔𝑚 expression:
𝑊 2𝐼𝐷 𝑊
𝑔𝑚 = 𝑘𝑛′ = 2𝑘𝑛′ 𝐼
𝐿 𝑊
𝑘𝑛′ 𝐿 𝐿 𝐷
K. Webb ECE 322
MOSFET Small-Signal T-Model
64
An alternative small-signal
MOSFET model is the T-model
As with the BJT T-model, useful
when there is source resistance
Though not immediately
obvious, note that 𝑖𝑔 = 0
𝑖𝑑 = 𝑖𝑠 = 𝑔𝑚 𝑣𝑔𝑠
Resistance seen looking into
the source:
1
𝑅𝑠 =
𝑔𝑚
K. Webb ECE 322
MOSFET Small-Signal Models
65
In summary:
Transconductance in terms
of overdrive voltage:
𝑊
𝑔𝑚 = 𝑘𝑛′ 𝑉
𝐿 𝑂𝑉
Transconductance in terms
of drain current:
𝑊
𝑔𝑚 = 2𝑘𝑛′ 𝐼𝐷
𝐿
K. Webb ECE 322
Small-Signal Models – Finite 𝑟𝑜
66
We have seen that we can add output resistance to the
large-signal model to account for channel-length
modulation
Can do the same for the small-signal model
Will rarely, if ever, do this for the large signal model, but often will
for the small-signal model
𝑉𝐴
𝑟𝑜 =
𝐼𝐷
1
𝑉𝐴 =
𝜆
1 𝑊 2
𝐼𝐷 = 𝑘𝑛′ 𝑉
2 𝐿 𝑂𝑉
K. Webb ECE 322
Using the MOSFET Models
67
In the next section of the course, we will look at the
analysis and design of MOSFET amplifiers
Biasnetwork and DC operating point
Signal-path
As was the case for BJT amplifiers, our general
procedure will be:
Large-signal analysis
◼ DCoperating point
◼ Small-signal model parameters
Small-signal analysis
◼ Circuit gain
K. Webb ECE 322