KSET Exam

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Test Paper : II

Test Booklet SERIAL No.

Test Subject : Chemical Sciences
Test Subject Code : K-2718

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Number of Pages in this Booklet : 16 Number of Questions in this Booklet : 100
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K-2718 1 ±Üâ.£.®æãà./P.T.O.
*K2718* Total Number of Pages : 16

Chemical Sciences
Paper – II
Note : This paper contains hundred (100) objective type questions. Each question carries
two (2) marks. All questions are compulsory.

1. Among the following : NH3 ; SO3 ; PBr3 ; 5. A thermogram of calcium oxalate

[SO4]2– ; [NO3]– ; AlCl3, the correct option monohydrate weighing 20.0 mg loses
showing species, containing a C3 axis 2.46 mg in the temperature range of
and a σh plane is 105 – 260°C. The residue product formed
(A) AlCl3, SO3 and [NO3]– is
(B) NH3, PBr3 and [SO4]2– (A) H2O (B) CaCO3
(C) AlCl3, NH3 and PBr3 (C) CaC2O4.H2O (D) CaC2O4
(D) SO3, [SO4]2– and NH3
6. The height equivalent of theoretical plates
2. For the lanthanide ion having f8 electronic and total number of plates if the elution
configuration, the ground state term peak of the sample is 9.34 minutes with
symbol and the number of microstates a base width of 0.43 minute and column
respectively are length of 18.3 cm respectively are
(A) 7F6 and 3003 (A) 2.42 × 10–2 and 7.55 × 103
(B) 6H15/2 and 2002
(B) 2.42 × 10–3 and 0.755 × 103
(C) 8S7/2 and 3003 (C) 2.42 × 10–3 and 7.55 × 103
(D) 5I8 and 2002 (D) 3.88 × 10–2 and 471.79
3. The reaction between potassium amide 7. In the coulometric titration of U4+ in the
and ammonium iodide in liquid ammonia
presence of excess Ce4+, it was found
is called as
to require 652 seconds to reach the
(A) redox reaction equivalence point using a constant
(B) precipitation reaction current of 100.0 mA. The number of
(C) acid-base reaction moles of U4+ present in the solution is
(D) complexometric reaction [Given : U4+ + 2Ce4+ + 2H2O 

 UO2+ +
2
2Ce + 4H ]
3+ +
4. The main difference between HPLC and
UPLC is (A) 1.35 × 10–3 (B) 6.76 × 10–4
(A) HPLC operates at higher mobile (C) 1.69 × 10–4 (D) 3.38 × 10–4
phase pressure and is reverse phase
always 8. The active site of metalloprotein,
(B) UPLC employs smaller stationary oxyhemocyanin contains
phase particle size 2−
(A) Fe (II) and O 2
(C) HPLC and UPLC employs different (B) Cu (II) and O 2
2−
mobile phases −
(D) HPLC and UPLC employs different (C) Fe (II) and O 2
2−
detection methods (D) Fe (III) and O 2

Paper II 2 K-2718
*K2718* Total Number of Pages : 16

9. N-methyl imidazole coordinated iron (II) – 13. The 13C NMR spectrum of CDCl3 consists
picket fence porphyrin was employed as of
a model compound for the active site of (A) a singlet
(A) rubredoxin (B) cytochromes (B) a doublet of 1 : 1 intensity
(C) peroxidase (D) myoglobin (C) a triplet of 1 : 2 : 1 intensity
(D) a triplet of 1 : 1 : 1 intensity
10. The functions of transferrin, cytochrome
and nitrogenase respectively are 14. Choose the correct statements about
(A) iron storage, electron transfer and CuI, AuCl2 and [Au(CN)2]– from the
nitrogen fixation following :
(B) iron transport, oxygen storage and i. CuI is white powder and AuCl2 is
nitrogen fixation unstable
(C) iron storage, electron transfer and ii. Both CuI and [Au(CN)2]– are
N2H4 fixation diamagnetic
(D) iron transfer, electron transfer and iii. Both AuCl2 and [Au(CN)2]– are
nitrogen fixation unstable
iv. CuI is diamagnetic but [Au(CN)2]–
11. A molecule shows two absorption peaks
is paramagnetic
( C) at 870 and 975 Hz in a magnetic
13
(A) i and iii (B) ii and iii
field of 3T. The corresponding chemical
(C) i and ii (D) i and iv

shifts in ppm are  Magnetogyric ratio for
 15. The absorption spectrum of [Ti(H2O)6]3+
1 shows a broad band with a shoulder
13
C = 6.7263×107 rad T–1s–1 ; for 13 C =  .
2 because
(A) 277.1 and 310.5 ppm
(A) The ground state of [Ti(H2O)6]3+ is
(B) 13.6 and 15.2 ppm Jahn-Teller distorted
(C) 27.1 and 30.4 ppm (B) Under UV light, [Ti(H2O)6]3+ is reduced
(D) 32.1 and 35.8 ppm to [Ti(H2O)6]2+
(C) The excited state of [Ti(H2O)6]3+
12. The order of carbonyl stretching undergoes Jahn-Teller distortion
frequency in the IR spectra of acetone,
(D) [Ti(H2O)6]3+ is a d2 ion and hence two
benzamide and acetic anhydride is
absorption bands are displayed
(A) Acetic anhydride > acetone >
benzamide 16. For the following, the correct option
(B) Acetone > benzamide > acetic containing species which shows color
anhydride that is NOT due to a d-d transition is :
(C) Benzamide > acetone > acetic VO2+ , Cr O24− , MnO24− & MnO4−
anhydride (A) MnO24− and Cr O24−
(D) Acetic anhydride > benzamide > (B) VO2+ and MnO4−
2− −
acetone (C) Cr O4 and MnO4
2+ 2−
(D) VO and Cr O 4
Paper II 3 K-2718
*K2718* Total Number of Pages : 16

17. The ‘d’ orbital(s) involved in the hybridisation 22. The product nucleus obtained as a result
representing square pyramidal geometry of β(beta) decay is
is (are) (A) One atomic number lower than the
(A) dx2 − y2 only original element
(B) dx2 − y2 and dz2
(B) Two atomic numbers higher than
(C) dz2 and dyz the original element
(D) dz2 only
(C) One atomic number higher than the
18. Among the following, the complex with original element
a magnetic moment of 5.9 BM and also (D) Two atomic numbers lower than the
both EPR and Mössbauer active is original element
(A) [Fe(CN)6]3– (B) [Mn(H2O)6]2+
23. Use the following data to calculate the
(C) [Fe(H2O)6]2+ (D) [Fe(H2O)6]3+
lattice enthalpy of KI(s) at 298 K. All
19. The complexes having square planar values are given in KJ/mol.
geometry and 16 valence electrons are Enthalpy of sublimation of K(s) = 81
(A) Pd (PPh3)4 and Ni (CO)4 Ionization enthalpy of K(g) = 418
(B) Pd (PPh3)4 and PtCl2 (PPh3)2 Enthalpy of dissociation of I2(g) = 214
(C) RhCl (CO) (PPh3)2 and Ni (CO)4
Enthalpy of electron attachment to
(D) PtCl2 (PPh3)2 and RhCl (CO) (PPh3)2 I(g) = – 295
20. In the following catalytic reaction, the Enthalpy of formation of KI(s) from K(s)
1
products obtained are and I2(g) − 328
Ni Catalyst
2
CH4  → ? (A) 639 KJ/mol
Steam, 800 C
(B) 573 KJ/mol
(A) H2 and CO
(B) H O and CO (C) 746 KJ/mol
2 2

(C) H2 and CO2 (D) 680 KJ/mol

(D) H2O and CO
24. According to Wade’s rules, boron hydride
21. The new isotope formed when atoms [B5H5]2– shows
aluminum-27 are bombarded with alpha (A) nido structure
particles, along with a ‘neutron’ emission
(B) closo structure
is
31 31 (C) arachno structure
(A) 14 Si (B) 16 S
30 31 (D) hypho structure
(C) 15 P (D) 15 P

Paper II 4 K-2718
*K2718* Total Number of Pages : 16

25. Solid state structure of phosphorus 30. Column – I and Column – II contain,
pentachloride is best represented as respectively, the molecular species and
(A) [PCl4] + [Cl]– possible geometries. Match the species
in Column – I with one or more correct
(B) [PCl4] + [PCl6]–
geometries in Column – II. The correct
(C) PCl5 option is
(D) Cl5P ­– PCl5
Column – I Column – II
26. Plaster of Paris is P. ICI4– 1. tetrahedral
(A) CaSO4∙2H2O Q. SOF4 2. octahedral
(B) CaSO4∙0.5H2O R. XeF4 3. square planar
(C) CaCO3∙2H2O S. SiH4 4. trigonal
bipyramidal
(D) CaCO3∙0.5H2O
5. trigonal pyramidal
27. The π bond strengths to carbon are in 6. square pyramidal
the order (A) P = 4 ; Q = 6 ; R = 4 ; S = 1
(A) C = C > C = Si > C = Ge > C = Sn (B) P = 4 ; Q = 2 ; R = 2 ; S = 3
(B) C = C < C = Si < C = Ge < C = Sn (C) P = 2 ; Q = 4 ; R = 2 ; S = 1
(C) C = Si > C = C > C = Ge > C = Sn (D) P = 2 ; Q = 6 ; R = 4 ; S = 5
(D) C = C < C = Si > C = Ge > C = Sn
31. Among the following chemical reactions,
28. Oxidation states of Xenon in [XeO2F3]– hydrogen acting as an oxidizing agent
and XeO2(OTeF5)2 respectively, are is

(A) + 4 and + 6 (A) H2 + Cl2 → 2HCl

(B) + 6 and + 8 (B) H2 + 12 O2 → H2O

(C) 2Na + H2 → 2NaH
(C) + 6 and + 6
(D) CuO + H2 → Cu + H2O
(D) + 4 and + 8
32. The correct equation to calculate the
29. The complex that shows quadrupole
screening constant (σ) for d-electron of
bonding (delta bond) is
Br (Z = 35) is
(A) [Re2Cl8]4– (A) 1 × 10 + 0.85 × 8 + 10 × 0.35
(B) [Mo2(OAc)4] (B) 1 × 18 + 0.35 × 9
(C) [Re2Br4(PMe3)2] (C) 0.85 × 18 + 0.35 × 10
(D) [Re2Cl6(PPh3)2] (D) 1 × 10 + 0.85 × 8 + 0.35 × 9

Paper II 5 K-2718
*K2718* Total Number of Pages : 16

33. The following is the correct order as a 35. Which is the correct configurational
result of polarisation in (i) melting points notation for the following at C1 and C4
of the compounds : LiF, LiCl, LiBr and centres ?
LiI and (ii) solubility of the compounds
in polar solvents : AgF, AgCl, AgBr and
AgI
(A) LiF > LiCl > LiBr > LiI ; AgF > AgCl >
(A) 1R, 4R
AgBr > AgI
(B) 1S, 4R
(B) LiF < LiCl < LiBr < LiI ; AgF < AgCl <
(C) 1S, 4S
AgBr < AgI
(D) 1R, 4S
(C) LiF > LiCl > LiBr > LiI ; AgF < AgCl <
AgBr < AgI
(D) LiF < LiCl < LiBr < LiI ; AgF > AgCl < 36. Among the following, the most stable

AgBr > AgI isomer for 1, 4 – cyclohexane diol is

(A)
34. The IUPAC name of the following
compound is

(B)
(A) 2E, 4E – 3 – chlorohex –
2, 4 – diene – 1, 6 – diol

(B) 2Z, 4E – 3 – chlorohex –

2, 4 – diene – 1, 6 – diol (C)

(C) 2Z, 4Z – 4 – chlorohex –

2, 4 – diene – 1, 6 – diol

(D) 2E, 4Z – 4 – chlorohex –

2, 4 – diene – 1, 6 – diol
(D)

Paper II 6 K-2718
*K2718* Total Number of Pages : 16

37. In the given reactions P and Q respectively 38. The major product in the following reaction
are is
3 i) Ph P = CHOCH
Q 1) (CH 3)3 C MgBr
1) CH 3 MgBr
P Benzaldehyde 
3
→?
2) NH4Cl / H2O 2) NH4Cl / H2O ii) H3O ⊕ ∆

(A) PhCH = CHCH3

(B) PhCH2CHO
(A) and (C) PhCH2CH2OH
(D) Ph – CH = CH – OCH3

39. Which of the following dienes is

suitable as the diene component in
a Diel’s – Alder reaction ?

(A)

(B) and
(B)

(C)

(D)

(C) and 40. Which of the following is a non-aromatic

annulene ?
(A) 18 – annulene
(B) 8 – annulene dianion
(C) 8 – annulene
(D) 9 – annulene anion

41. Butadiene on thermal electrocyclic ring

closure reaction shows
(A) Dis-rotatory process
(B) Suprafacial rotatory process
(D) Only
(C) Con-rotatory process
(D) Antarafacial rotatory process

Paper II 7 K-2718
*K2718* Total Number of Pages : 16

42. In the following reaction, the number of 45. λmax for the following compounds are
isomeric deutero anilines formed is

and
KNH

→? 2
Liq ⋅ NH
3

(A) only one (B) only two
(C) three (D) four

43. Which of the following carbocation is

likely to undergo rearrangement through
hydride shift ? (A) 284 nm and 333 nm
⊕
(B) 333 nm and 284 nm

⊕ ⊕ (C) 280 nm and 330 nm

(D) 330 nm and 280 nm

(A) only X (B) X and Y
(C) only Y (D) only Z 46. The formation of the base peak in mass
spectrometry is due to
44. The IR stretching frequencies for the
compound shown below are as follows : (A) only ionisation
3300 – 3500 (s, br), 3000 (m), 2225 (s), (B) ionisation and stability of cation/
1680 (s) cm–1.
radical cation
(C) ionisation and stability of radical
(D) ionisation and stability of anion

The correct assignment of the absorption 47. The reaction given below is an example
band is of CO Et 2
CO2Et i) NaOEt
(A) γOH = 3300 – 3500 ; γCH = 3000 →
⊕
γCN = 1680 ; γCO = 2225 cm–1 CO2Et ii) H3O O
(B) γOH = 3300 – 3500 ; γCH = 2225 ;
γCN = 3000 ; γCO = 1680 cm–1 (A) Aldol condensation
(C) γOH = 3000 ; γCH = 3300 – 3500 ; (B) Knoevenagel condensation
γCN = 2225 ; γCO = 1680 cm–1
(C) Dieckmann cyclisation
(D) γOH = 3300 – 3500 ; γCH = 3000 ;
γCN = 2225 ; γCO = 1680 cm–1 (D) Acyloin cyclisation

Paper II 8 K-2718
*K2718* Total Number of Pages : 16
48. The rearranged product P of the reaction is 50. α-D-glucose is converted to a mixture of
OH α-D-glucose and β-D-glucose in water
due to
conc ⋅ H SO (A) mutarotation

2 4
→P
∆ (B) epimerization
(C) conformational change
(D) racemization
(A)
51. What is the sequence of bases in
RNA molecule synthesized on the
(B) TATCTACCTGGA strand of DNA ?
(A) AVAGAUGGACCU
(B) ATAGATGGACCT
(C) (C) TATCTACCTGGA
(D) ATTUGGAATG
52. Hofmann degradation is useful in the
(D) structural determination of
(A) Terpenoids (B) Lipids
(C) Steroids (D) Alkaloids
49. Predict the product for the following
transformation. 53. The major product formed in the following
reaction is
CH COONO
DDQ 3 2
 →?
 →?

(A) (A)

(B)
(B)

(C)
(C)

(D)
(D)

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54. In the following reaction, X is 55. The products X and Y in the following
reactions are

(CH ) CuLi
3 2 CH3 − Li
X ←   →Y
+ CS2 → X

(A) and

(A)
(B) only

(C) and

(B)

(D) only

56. An organic compound of molecular

formula C9H10O2 showed three peaks
in the PMR spectrum as given below :
δ 1.96, singlet (3H), δ 5.0, singlet (2H) and
(C) δ 7.2, singlet (5H). In IR spectrum one
of the intense bands of this compound
appears at 1740 cm–1. The structure of
the compound is
O
||
(A) C6H5 − CH2 − O − C − CH 3
O
||
(D) (B) C6H5 − CH2 − C − OCH 3
O
||
(C) C6H5 − O − CH2 − C − CH 3
O
||
(D) C6H5 − O − C − CH2 − CH 3

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57. The product X formed in the following 58. Which of the following compound yields
reaction is 14
CH2I2 as a product when treated with I2
in presence of NaOH ?

KCN/EtOH/H O
2
 →?

(A)

(A)

(B)

(B) (C)

(D)
(C)

59. What happens when chloroform is oxidised

on exposure to air ?

(A) Dichlorocarbene is produced

(D) (B) Carbon dioxide is produced

(C) Phosgene is produced

(D) Carbon monoxide is produced

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60. The most probable product in the 63. The product formed in the following
following reaction is reaction is

hν hν
 →?  →?

(A)
(A)

(B)
(B)

(C)

(C)

(D)

(D)

61. Which one is not a green solvent among 64. The products formed in the following
the following ? reaction are
i) Me3Si − I
(A) Liquid carbon dioxide C6H5 − O − CH3  →?
ii) H O⊕
3
(B) Liquid ammonia
(A) C6H5 – I and CH3 – OH
(C) Ionic liquids (B) C6H5 – OH and CH3 – I
(D) Water (C) C6H5 – SiMe3 and CH3 – OH
(D) C6H5 – OH and CH3 – SiMe3
62. The chemical bonding of carbon nanotubes
is composed entirely by 65. The effective catalyst for the mutarotation
of monosaccharides is
(A) sp bonds
(A) pyridine
(B) sp2 bonds (B) phenol
(C) sp3 bonds (C) 2-hydroxypyridine
(D) sp and sp bonds
3
(D) anhydrous acetic acid
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66. Among the following the narcotic 72. The ground state term symbol for
analgesic is Nb (atomic number : 41) is 6D.
(A) Heroin (B) Ibuprofen The electronic configuration is
(C) Naproxen (D) Aspirin (A) [Kr] 4d35s2 (B) [Kr] 4d45s1
(C) [Kr] 4d55s0 (D) [Kr] 4d35s15p1
67. Crown ether and creptate have
(A) N and O donor atoms respectively 73. The hybridization sp3d gives rise to the
following arrangement
(B) S and N donor atoms respectively
(A) Linear
(C) O and N donor atoms respectively (B) Octahedral
(D) O and S donor atoms respectively (C) Trigonal bipyramidal
8 π 2m (D) Trigonal planar
68. ∇2 in ∇ 2 Ψ + 2 (E − V) Ψ = 0 is known
as h 74. In the following molecule, the hybrid
(A) Hamiltonian operator state of 1 and 3 carbon atoms is
CH2 = C = CH2
(B) Laplacian operator
(A) sp (B) sp2
(C) Angular momentum (C) sp 3
(D) sp3d
(D) Energy operator
75. The bond order of the super oxide (O2–) is
69. If the function f = e–ax is acted upon by (A) 1.5 (B) 2.5
d (C) 1.0 (D) 2.0
the operator , the eigen value and
dx 76. Which of the following species possesses
eigen function respectively are
both C2 and C3 axis ?
(A) – a and e– ax (B) 2a and eax (A) SO3 (B) NH3
d ⊕
(C) ax and e– 2x (D) and eax (C) PCl3 (D) H 3O
dx
70. The quantum mechanical operator for 77. The symmetric streching vibrational
kinetic energy of a particle moving in mode of CO2 molecule is
three directions is (A) IR and Raman inactive
− h2 2 h (B) IR and Raman active
(A) ∇ (B) ∇
2
8π m 2πi (C) IR inactive but Raman active
(D) IR active but Raman inactive
h 8 π 2m 2
(C) 2
∇2 (D) ∇
8π m h2 78. Arrange the methyl halides (CH3Br,
CH3Cl, CH3I, CH3F) in the order of
71. According to Schrodinger equation the
increasing field strength by ′HNMR
energy of a particle (En) in one dimensional
technique.
box
(A) CH3Cl, CH3Br, CH3I, CH3F
n2h2 n2h2
(A) E n = (B) nE = (B) CH3Br, CH3Cl, CH3I, CH3F
ma 2 4ma
n2h2 nh (C) CH3I, CH3Br, CH3Cl, CH3F
(C) E n = (D) E n = (D) CH3F, CH3Cl, CH3Br, CH3I
8 ma 2 8 ma 2
Paper II 13 K-2718
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79. The relation between ∆E and ∆H is 85. A quantity of PCl5 was heated in a
(A) ∆E = ∆H + P∆V 10 litre vessel at 250°C. At equilibrium
(B) ∆E = ∆H – V∆P the vessel contains 0.10 mole of PCl5,
(C) ∆H = ∆E + P∆V 0.20 mole of PCl3 and 0.20 mole of Cl2.
(D) ∆H = ∆E – V∆P The equilibrium constant of the reaction,
80. Using the fundamental equation 
PCl5 (g)  
 PCl3 (g) + Cl2 (g) is

dA = – SdT – PdV the Maxwell relation is (A) 0.02 (B) 0.05
(C) 0.04 (D) 0.025
 ∂S  ∂V
(A)   =  86. Le Chatelier’s principle is not applicable to
 ∂ T  T  ∂ S V
(A) Fe(s) + S(s)  

 FeS(s)
 ∂S   ∂P 
(B)   =  
(B) H2 (g) + I2 (g) 
 2HI(g)
 ∂ V P  ∂ T V (C) N2 (g) + 3H2 (g) 
 2NH3 (g)
∂T  ∂P  
(D) N2 (g) + O2 (g)   2NO(g)
(C)   = 
 ∂ V S  ∂ S  T
87. The value of standard electrode potential
 ∂S   ∂P  for the change Fe3+(aq) + e– → Fe2+(aq)
 =
(D)  
 ∂ V  T  ∂ T V (
will be Given, E0Fe3 + /Fe = − 0.036 V ;

81. The condensed phase rule used for

E0Fe2 + /Fe = − 0.439 V)
Pb – Ag system is (A) – 0.072 V (B) + 0.385 V
(C) + 0.770 V (D) – 0.270 V
(A) F = C – P + 1
(B) F = C + P – 1 88. The standard E0red values of A, B and C are
(C) F = C – P + 2 + 0.68 V, – 2.54 V, – 0.50 V respectively.
(D) F = C + P + 2 The order of their reducing power is
(A) A > B > C (B) A > C > B
82. The number of phases in equilibrium at (C) C > B > A (D) B > C > A
triple point in water system are
(A) One (B) Two 89. The rate of equation for the reaction,
(C) Three (D) Zero 2 AB + B2 → 2AB2 is given by
rate = k [AB] [B2]
83. The value of 1.38 × 10–23 JK–1 represents
A possible mechanism consistent with
(A) Boltzmann constant
this rate law is
(B) Avogadro number slow
(C) Planck constant (A) 2AB + B 2 → 2 AB2
slow
(D) Gas constant (B) AB + B 2  → AB3
fast
84. The rate of entropy production is AB3 + AB → 2 AB2
(A) sum of force and flux 
(C) AB + AB  
 A 2B2 (fast )

(B) product of force and flux slow
A 2B2 + B2  → 2 AB2
(C) differences of force and flux 
(D) AB + B2 

 AB3 (fast )
force slow
(D) AB3 + AB → 2 AB2
flux
Paper II 14 K-2718
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90. Half life of a reaction is found to be 95. The atoms in a molecule of water adopts
inversely proportional to the cube of what kind of geometry
initial concentration. The order of the (A) Square planar
reaction is (B) Trigonal planar
(A) 13 (B) 2 (C) Linear
(D) Tetrahedral
(C) 3 (D) 4
91. Which of the following is the Wilkinson’s 96. The coordinates for the atoms in a body
catalyst ? centred cubic (bcc) unit cell are
(A) (PPh3)2 Ir (CO) Cl  1 1 1
(B) (PPh3)3 RhCl (A) (0, 0, 0) and  , , 
2 2 2
(C) PtO2
1 
(D) Ra – Ni (B) (0, 0, 0) and  , 0, 0 
2 
92. The correct statements among the
(C) (0, 0, 0) and  0, , 0 
following are 1
1. A catalyst does not affect the  2 
equilibrium constant.  1
2. Le Chatelier’s principle states that (D) (0, 0, 0) and  0, 0, 
a system at equilibrium, when  2
subjected to a disturbance responds 97. When a beam of light is passed through
in a way that minimizes the effect of a colloidal solution, it gets
the disturbance.
3. Increase in temperature favours the (A) scattered (B) absorbed
reactants in endothermic reactions (C) reflected (D) refracted
and products in exothermic
reactions. 98. An arsenic sulfide sol. carries (–)ve
4. Oxidation is the removal of electrons charge. The maximum precipitating
from a species and reduction is the power for this sol. is possessed by
addition of electrons to a species. (A) K2SO4 (B) CaCl2
(A) 1, 2 and 3 (B) 1, 2 and 4 (C) Na3PO4 (D) AlCl3
(C) 1, 3 and 4 (D) 2, 3 and 4
99. Median of the following set of results
93. The following compound is used in the 0.124, 0.130, 0.128, 0.126 and 0.122 is
preparation of Terylene
(A) 0.124 (B) 0.126
(A) Adipic acid
(C) 0.129 (D) 0.130
(B) Bisphenol A
100. Precision refers to
(C) Glycine
(A) agreement of measured parameters
(D) Dimethyl terephthalate with the theoretical value
94. The number average molecular weight (B) agreement among respective values
of a polymer sample containing equal of the measured parameters
number of molecules of molecular mass
104 and 1015 is (C) difference between the highest
and lowest values of the measured
(A) 0.5 × 109 (B) 0.5 × 1020 parameters
(C) 5.5 × 104 (D) 5.0 × 104 (D) systematic errors only

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Space for Rough Work

Paper II 16 K-2718