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Unit-2 Part-One

The document discusses transistor amplifier circuits, focusing on D.C. and A.C. equivalent circuits, and introduces h-parameters used for analyzing transistor amplifiers. It details the calculations for current gain, input resistance, voltage gain, output resistance, and overall gains in a common emitter amplifier configuration. Additionally, it outlines the properties of common emitter amplifiers, highlighting their significant current and voltage gains.

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0% found this document useful (0 votes)
39 views36 pages

Unit-2 Part-One

The document discusses transistor amplifier circuits, focusing on D.C. and A.C. equivalent circuits, and introduces h-parameters used for analyzing transistor amplifiers. It details the calculations for current gain, input resistance, voltage gain, output resistance, and overall gains in a common emitter amplifier configuration. Additionally, it outlines the properties of common emitter amplifiers, highlighting their significant current and voltage gains.

Uploaded by

dad and son
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PPT, PDF, TXT or read online on Scribd
You are on page 1/ 36

Analog Circuits (Unit-2)

1
Transistor Amplifier Circuit:-
Transistor equivalent ckt are divided in two
types (i) D.C. equivalent ckt. (ii) A.C. equivalent ckt.

Fig.7.1(a) Transistor Amplifier using Self Bias 2


3
Fig.7.1(c) A.C. Equivalent ckt.

Fig.7.1(b) D.C. Equivalent Ckt.


4
 The capacitors CC1 & CC2 are called the coupling
capacitors. Capacitors CC1 is used to couple the a.c.
input signal to the base of the transistor. A coupling
capacitor is also called a blocking capacitor because
it blocks d.c.
Another capacitor CE is called bypass capacitor
because it bypasses the all a.c. current from the
emitter to ground.

5
Hybrid Parameter (h-Parameter):-
 h-parameter is widely used because they gives
accurate results & can be measured very easily.
 The transistor is a three terminal device but if one
terminal is grounded, then transistor can be used as a
two port network.
 The h-parameters are
V1=h11I1+h12V2
I2=h21I1+h22V2
The parameter h11, h12, h21 & h22 are called h-
parameters.
6
Fig.7.2 (a) General h-parameter Equivalent Circuit

7
Fig.2.2(b) Transistor Two Port Network
the h - parameter is summarized as,
V1
h11  I/P impedance with O/P shorted & unit is ohm
I1
it is also represented as, h11 h i
I2
h 21  forward current gain with O/P shorted & unit is none.
I1
it is also represented as h 21 h f
V1
h12  Reverse voltage gain with I/P open circuited & has no unit.
V2
it is also represented as, h12 h r
I2
h 22  O/P admittance with I/P open ckt. & unit is ohm-1 or mho.
V2
it is also represented as, h 22 h o
8
h-Parameter Representation for Transistor:-
Sr. h-Parameter Common Common Common
No. Emitter Base Collector
1. h11 hie hib hic

2. h21 hfe hfb hfc

3. h12 hre hrb hrc

4. h22 hoe hob hoc

9
Analysis of Transistor Amplifier by h-Parameter:-

Fig (a) General Amplifier Circuit with Source & Load Resistance

Fig (b) h-Parameter Equivalent Circuit of above General Amplifier


10
1. The Current Gain (Ai):- The current gain for the
transistor amplifier is defined as the ratio of O/P
current to the I/P current. Mathematically,
IL I2
A i  - ...eq.(1)
I1 I1
from above figure the voltage across the output terminal is V2 ,
V2 I L .R L -I2 .R L ...eq.(2)
Now the h - Parameters equations are,
V1 h i I1  h r V2 ...eq.(3)
I 2 h f I1  h o V2 ...eq.(4)
Now putting the value of V2 in eq.(4) we get,
I 2 h f I1 - I 2 .R L h o
11
I 2 (1  R L h o ) h f I1
I2 hf
So 
I1 1  R L h o
- I2 IL - hf
Ai   
I1 I1 1  R L h o

12
2. The Input Resistance (Ri):- The I/P resistance Ri is defined
as the resistance we see looking into the amplifier I/P
terminals (1-1’). Mathematically,
V1
So Ri 
I1
Now putting the value of V2 -I2 .R L in eq. of h - parameter
V1 h i I1  h r V2
V1 h i I1 - I 2 .R L h r
Now dividing the above eq. on both side by I1. we have,
V1  I2  V1
h i -  .R L h r But R i
I1  I1  I1

13
 I2  - I2
So therefore R i  h i -  .R L h r but A i
 I1  I1
 hf
R i  h i  A i .R L h r we know that A i 
1  h oR L
 - hf  h f R Lh r
so R i h i   .R L h r h i 
 1  h oR L  1  h oR L
hf hr hf hr
R i h i  h i 
ho  1 h o  YL
RL
1
where YL  Load Admittance
RL 14
3. The Voltage gain (Av):- The voltage gain is
defined as the ratio of the O/P voltage V 2 to I/P
V2 I2R L
voltage V1. A v   ... eq.(1)
V1 V1
Mathematically, I2
Since we Know that, A i  or I 2  A i I1
I1
A i I1R L  I1 
Therefore Av  A i R L  
V1  V1 
V1 Ai R L
But R i So, A v  ..eq.(2)
I1 Ri
 hf hrhf
Again we know that, A i  & R i h i 
1  hoR L 1
 ho
RL 15
now putting these value in eq.(2) then we have,
- hf R L
1 hoR L
Av 
hrhf
hi 
1
 ho
RL
 hf R L  hf R L
Av  
h i  h i h o - h r h f R L h i  Δh.R L
 hf R L
Av 
h i  Δh.R L
where Δh h i h o - h r h f 16
4. Output Resistance (Ro) :- The O/P resistance may be
calculated by reducing the source voltage V s to zero & load
resistance RL to infinity & driving the O/P terminals by a
voltage generator V2. as shown below,

Fig.(c) h-equivalent ckt. to calculate the O/P resistance


O/P resistance Ro is the ratio of the voltage V2 & the
current drawn from the voltage source I2
So Ro=V2/I2 17
from h - parameter eq. I 2 h f I1  h o V2
V2
hence Ro  ...eq.(1)
h f I1  h o V2
Applying KVL to the I/P side of the ckt. as shown in fig.7.4(c)
R s I1  h i I1  h r V2 0
or R s  h i I1  h r V2
 h r V2
I1  ...eq.(2)
R s  h i 
Now putting the value of I1 in eq.(1) we get,
V2 V2
Ro  
  h r V2   h f h r V2
h f    h o V2  h o V2
 R s  hi  R s  hi 18
Re arranging we get,
R s  hi R s  hi
Ro  
h o R s  h i  h f h r h o R s  h o h i  h f h r 
R s  hi
So, Ro  where Δh h o h i  h f h r
h o R s  Δh
if source resistance R s 0 then O/P resistance will be,
hi
Ro 
Δh

19
5. The Overall Voltage Gain (Avs):- The overall voltage gain of
the transistor amplifier is the ratio of O/P voltage V2 to the
source voltage Vs . It is denoted by Avs.

Fig Equivalent I/P ckt.


V2 V2 V1
Mathematically overall voltage gain, A vs   
Vs V1 Vs
V2 V1
but, A v  therefore A vs A v . ...eq.(1)
V1 Vs 20
now from equivalent ckt. here Zi represents the amplifier
I/P resistance from figure we have,
Vs .Zi V1 Zi
V1  or 
Zi  R s Vs Zi  R s
putting the value of V1/Vs in eq.(1) we get,
V1 Zi
A vs A v . A v
Vs Zi  R s
if R s 0 then A vs A v
therefore A v is the voltage gain with an ideal voltage
source (R s 0)

21
6. Overall Current Gain (Ais):- overall current gain of the
transistor amplifier is the ratio of the O/P current (I L) to the
current delivered by the source (Is)

Fig 7.4(e) Modified I/P Equivalent ckt.


IL I2
Mathematic ally overall Current gain, A is  
Is Is
modifying the above expression we have,
I 2 I1 I2
but, A is   ...eq.(1) but A i  22
I1 I s I1
I1
So A is A i . ...eq.(1)
Is
To determine A is we use modified I/P equivalent ckt.,
here Zi is amplifier I/P resistance, from fig.7.4(e) we have
Rs I1 Rs
I1 I s then  ...eq.(2)
R s  Zi I s R s  Zi
I1
now putting the value of in eq.(1) we get,
Is
I1 Rs
A is A i . A i 
Is R s  Zi
Now if R s  then A is A i therefore A i is the
23
current gain with an ideal current source (R s )
7.5 h-Parameter Expression for CE amplifier:-
B
C

E E E
Fig. h-parameter equivalent circuit for CE amplifier

24
1. Current gain (Ai):- - hf
Ai  (General Expression)
1  R Lh o
Current Gain for Common Emitter Amplifier,
h fe
A i -
1  R L h oe
2. Input Resistance (Ri):-
hf hr
R i h i  (General Expression )
ho  1
RL
The I/P resistance for C - E Amplifier,
h fe h re
R i h ie 
h oe  1
RL
for the fixed bias ckt. Zi R i R B & for no
25
biasing resistance then Z i R i
3. Voltage Gain (Av):- A   h f R L (General Expression)
v
h i  Δh.R L
 h fe R L
Voltage gain for CE amplifier, A v 
h ie  Δh.R L
where Δh h ie h oe - h re h fe
4. Output Resistance (Ro):-
R s  hi
Ro  (General Expression)
h o R s  Δh
R s  h ie
Ro  (for CE amplifier)
h oe R s  Δh
where Δh h oe h ie  h fe h re & R s is the source resistance
The O/P resistance of the amplifier stage will be
Zo R o R L 26
5. Overall Voltage Gain (Avs):-
V1 Zi
A vs A v . A v (general expression)
Vs Zi  R s
Zi  - h fe R L  Zi
A vs A v   (for CE amplifier)
Zi  R s  h ie  ΔhR L  Zi  R s
here Δh h ie h oe  h re h fe

6. Overall Current Gain (Ais):-


Rs   hf  Rs
A is A i    (General expression)
R s  Zi  1  h o R L  R s  Zi
  h fe  R s
A is   (For CE amplifier)
 1  h oe R L  R s  Zi
27
Properties of Common Emitter Amplifier:-
1. Large current gain (Ai=100).
2. Large voltage gain (Av=500).
3. Large power gain (Ap=Av.Ai)
4. Moderate I/P impedance (50KΩ).
5. Moderate O/P impedance (10KΩ).
6. Phase shift is 180º bet I/P & O/P voltage.

28
7.6 h-Parameter Expression for CB amplifier:-
1. Current gain (Ai):-
Current Gain for Common Base Amplifier,
h fb
A i -
1  R L h ob

2. Input Resistance (Ri):-


The I/P resistance for C - B Amplifier,
h fb h rb
R i h ib 
h ob  1
RL
The i/p resistance of the amplifier stage depends upon the
biasing arrangement.if there is no biasing then,
Zi R i 29
3. Voltage Gain (Av):-
 h fb R L
Voltage gain for CB amplifier, A v 
h ib  Δh.R L
where Δh h ib h ob - h rb h fb

4. Output Resistance (Ro):-


R s  h ib
Ro 
h ob R s  Δh
where Δh h ob h ib  h fb h rb & R s is the source resistance
The O/P resistance of the amplifier stage will be
Zo R o R L
30
5. Overall Voltage Gain (Avs):-
Zi  - h fb R L  Zi
A vs A v  
Zi  R s  h ib  ΔhR L  Zi  R s
here Δh h ob h ib  h fb h rb

6. Overall Current Gain (Ais):-


The overall current gain for the CB amplifier is,

  h fb  R s
A is  
 1  h ob R L  R s  Zi
31
Properties of Common base Amplifier:-
1. current gain is less than 1(Ai<1).
2. Large voltage gain (Av=150).
3. Power gain is less than CE configuration (Ap=Av.Ai)
4. Small I/P impedance (40Ω).
5. Large O/P impedance (1MΩ).
6. No voltage & current Phase shift.

32
h-Parameter Expression for CC amplifier:-
1. Current gain (Ai):-
Current Gain for Common collector Amplifier,
h fc
A i -
1  R L h oc

2. Input Resistance (Ri):-


The I/P resistance for C - C Amplifier,
h fc h rc
R i h ic 
h oc  1
RL
The i/p resistance of the amplifier stage depends upon the
biasing arrangement.if there is no biasing then,
Zi R i 33
3. Voltage Gain (Av):-
 h fc R L
Voltage gain for CC amplifier, A v 
h ic  Δh.R L
where Δh h ic h oc - h rc h fc

4. Output Resistance (Ro):-


The O/P resistance of the CC amplifier is,
R s  h ic
Ro 
h oc R s  Δh
where Δh h oc h ic  h fc h rc
R s is the source resistance
34
5. Overall Voltage Gain (Avs):-
Zi  - h fc R L  Zi
A vs A v  
Zi  R s  h ic  ΔhR L  Zi  R s
here Δh h oc h ic  h fc h rc

6. Overall Current Gain (Ais):-

The overall current gain for the CC amplifier is,

  h fc  R s
A is  
 1  h oc R L  R s  Zi

35
Properties of Common Collector Amplifier:-
1. current gain is Very high (Ai=100).
2. Voltage gain is less than unity (Av<1).
3. Power gain is less than CE configuration (Ap=Av.Ai)
4. Large I/P impedance (750KΩ).
5. Small O/P impedance (50Ω).
6. No voltage & current Phase shift.

36

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