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Let generator.close() return StopIteration.value #104770

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Description

@ntessore

Feature or enhancement

Change the close() method of generators to return the value of StopIteration.

Pitch

If a generator handles the GeneratorExit thrown by close(), it can exit gracefully, raising StopIteration with its return value.

def f():
    try:
        yield
    except GeneratorExit:
        pass
    return 0

g = f()
g.send(None)
g.close()  # StopIteration handled by close()

The StopIteration is handled by close(), but the return value is currently discarded, and close() always returns None.

The proposed change is to let close() return the value of a StopIteration it encounters after a graceful generator exit.

Every other case, including errors thrown between except GeneratorExit and return, is already handled by close() and would remain unchanged. This includes repeated calls to close(): Only the first such call might cause a generator to exit gracefully, after which it cannot raise StopIteration any longer.

The change enables more natural use of generators as "pipelines" that process input data until ended. As a trivial example of the functionality, consider this computer of averages:

def averager():
    n = 0
    sum = 0.
    while True:
        try:
            x = yield n
        except GeneratorExit:
            break
        n += 1
        sum += x
    mean = sum/n
    return mean

avg = averager()
avg.send(None)
for number in get_some_numbers():
    avg.send(number)
mean = avg.close()

The generator processes data in an infinite loop. Once the controlling process terminates processing, the generator performs post-processing, and returns a final result. Without the return value of close(), there is no intrinsic way of obtaining such a post-processed result.

Previous discussion

Discourse thread: Let generator.close() return StopIteration.value

Linked PRs

Activity

  1. added a commit that references this issue on May 23, 2023
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