132 kV Line Feeder
1.2 CT dimensioning for Metering: Applicable Core: 2
General Project Data:
Customer: PGCB
Project: DESIGN,SUPPLY,INSTALLATION,TESTING
AND COMMISSIONING OF 132/33KV
SUBSTATIONS ON TURNKEY BASIS
(PACKAGE-2.1)
Station: GHATAIL 132/33KV NEW AIS
SUBSTATION
Feeder: RPCL-1/2(LINE BAY-01)
General System and Substation Data:
Nominal Voltage: 132 kV
Nominal Frequency: 50 Hz
Power System Time Constant: 47.511 ms
Rated Short Circuit current of the station: 40 kA
Data of Line CT according to IEC Norm:
<For CT Ratio 2000/1A>
Accuracy Class: 0.2
Rated Burden: 15 VA
Rated Primary Current Ipn: 2000 A
Rated Secondary Current Isn: 1A
Internal Burden RCT at 75oC: 10 Ω
Instrument Security Factor FS: 5
<For CT Ratio 1000/1A>
Accuracy Class: 0.2
Rated Burden: 7.5 VA
Rated Primary Current Ipn: 1000 A
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Rated Secondary Current Isn: 1A
Internal Burden RCT at 75oC: 5Ω
Instrument Security Factor FS: 5
DIGITAL METER IN BACKUP MIMIC DATA:
Manufacturer: ABB
Type: BCM 802
Rated relay current, Ir2 : 1A
Relay burden SR2 : 0.01VA
Permissive Overload for 1sec IPO : 50
ENERGY METER DATA:
Manufacturer: CEWE
Type: Prometer 100
Rated relay current, Ir3 : 1A
Relay burden SR3 (Per phase): 0.7mVA
Permissive Overload for 1sec IPO : 50
Calculation of Cable Burden:
Distance Iwire 170 m
Cable cross section αwire 4.0 mm2
Special resistivity(Cu) ρwire .02171 Ωmm2/m at 750C
Effective wire length kwire 1
𝐼𝑤𝑖𝑟𝑒 𝑥 𝜌𝑤𝑖𝑟𝑒 𝑥 𝑘𝑤𝑖𝑟𝑒
Rwire=
𝛼𝑤𝑖𝑟𝑒
Calculated Cable Burden Rwire 0.922675 Ω
With 20% margin RI 1.10721 Ω
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CT requirements for metering:
Requirement 1:
The current transformer for metering must have an effective instrument security factor FS’ that is
smaller than the value of the equations below
(𝑅𝑐𝑡 + 𝑅𝑁 )
𝐹𝑆 ′ = 𝐹𝑆 × 𝑆 ≤ 𝐼𝑝𝑜 (Requirement 1)
𝑅𝑐𝑡 +𝑅𝑙 + 2𝑅
𝐼𝑟
Requirement 2:
The ratio of actual burden to rated burden should be the value of equations below:
𝑆
(𝑅𝑐𝑡 +𝑅𝑙 + 2𝑅 )
𝐼𝑟 )
25% ≤ (𝑅𝑐𝑡 + 𝑅𝑁 )
≤ 100% (Requirement 2)
Where,
FS: Instrument Security Factor
RCT: Internal CT burden at 75oC [Ω]
𝑉𝐴
RN: Rated CT burden ( 2 )[Ω]
𝐼𝑛
Rl: Secondary wire burden [Ω]
SR: Rated instrument Burden[VA]
Ir: Rated Secondary Current of Relay [A]
Ipo: Rated instrument minimum permissive overload
<For CT ratio 2000/1>
FS: Instrument Security Factor = 5
RCT: Internal CT burden at 75oC [Ω] = 10 Ω
RN: Rated CT burden = 15 Ω
RL: Secondary wire burden = 1.10721 Ω
SR: Rated instrument burden = 0.0121 Ω
Ir: Rated Secondary Current of Relay [A] = 1A
Ipo: Rated instrument minimum permissive overload = 50
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Requirement 1:
10 + 15
𝐹𝑆 ′ = 5 ×
10 + 1.10721 + 0.0121
𝐹𝑆 ′ = 11.24 ≤ 50
Which fulfills requirement 1.
10+1.1072+0.0121
Requirement 2: Ratio =
10+15
= 44.48%
Therefore, Ratio=44.48% and fulfills requirement 2
<For CT ratio 1000/1>
FS: Instrument Security Factor = 5
RCT: Internal CT burden at 75oC [Ω] = 5 Ω
RN: Rated CT burden = 7.5 Ω
RL: Secondary wire burden = 1.10721 Ω
SR: Rated instrument burden = 0.0121 Ω
Ir: Rated Secondary Current of Relay [A] = 1A
Ipo: Rated instrument minimum permissive overload = 50
Requirement 1:
5 + 7.5
𝐹𝑆 ′ = 5 ×
5 + 1.10721 + 0.0121
𝐹𝑆 ′ = 10.2136 ≤ 50
Which fulfills requirement 1.
5+1.10721+0.0121
Requirement 2: Ratio =
5+7.5
= 48.95%
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Therefore, Ratio=48.95 % and fulfills requirement 2
SO, CT IS CORRECTLY DIMENSIONED.
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